/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 The resistance of a bagel toaste... [FREE SOLUTION] | 91Ó°ÊÓ

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The resistance of a bagel toaster is \(14 \Omega\). To prepare a bagel, the toaster is operated for one minute from a \(120-\mathrm{V}\) outlet. How much energy is delivered to the toaster?

Short Answer

Expert verified
The energy delivered to the toaster is approximately 61714.2 joules.

Step by step solution

01

Identify the Given Information

We are given the resistance \( R = 14 \, \Omega \), the voltage \( V = 120 \, \text{volts} \), and the time \( t = 1 \, \text{minute} = 60 \, \text{seconds} \).
02

Use the Formula for Power

We use the formula for power delivered, \( P = \frac{V^2}{R} \), because we know both the voltage and the resistance.
03

Calculate the Power

Substitute the values into the formula: \[ P = \frac{120^2}{14} = \frac{14400}{14} \approx 1028.57 \, \text{watts} \].
04

Use the Formula for Energy Delivered

Energy delivered is given by the formula \( E = P \times t \). Since we already have the power \( P \) and the time \( t \) in seconds, we can calculate the energy.
05

Calculate the Energy Delivered

Substitute the values into the formula: \[ E = 1028.57 \times 60 \approx 61714.2 \, \text{joules} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is an essential principle in the study of electrical circuits, and it relates voltage, current, and resistance. The law is expressed with the formula:
  • \( V = I \cdot R \)
In this formula, \( V \) stands for voltage (in volts), \( I \) represents current (in amperes), and \( R \) is the resistance (in ohms, \( \Omega \)).
If you know any two of these values, you can calculate the third. This makes Ohm's Law extremely useful for solving electric circuit problems.
In our exercise, Ohm's Law could help us find the current once we have voltage and resistance. But for this particular problem, it wasn't directly used since we utilized the power formula instead.
Power Formula
The power formula is crucial for calculating the rate at which energy is used in an electrical circuit. Power is a measure of how much energy is consumed per unit of time.
The formula used for power calculation is:
  • \( P = \frac{V^2}{R} \)
Here, \( P \) is power in watts, \( V \) denotes voltage across the resistance, and \( R \) is the resistance itself.
This specific form of the power formula is handy when you know the voltage and resistance, which was the case in our toaster example. By calculating the power, we can later derive how much energy is used over a period, as power directly influences energy consumption.
Energy Conversion
Energy conversion is a key concept when dealing with electrical devices, as it explains how energy is transformed from electrical energy to other forms, such as heat, light, or motion.
In the context of our example, the toaster is converting electrical energy from the outlet into heat energy to toast a bagel.
The energy delivered can be calculated using the formula:
  • \( E = P \times t \)
where \( E \) is energy in joules, \( P \) is power in watts, and \( t \) is time in seconds. This formula tells us that the energy consumed is a product of the power and the duration of time the device is operating.
Electrical Resistance
Electrical resistance is a fundamental property that quantifies how much a material opposes the flow of electric current.
Measured in ohms (\( \Omega \)), resistance depends on factors like material composition, temperature, and physical dimensions of the component.
In our example, the toaster has a resistance of \( 14 \Omega \). This value determines how much current will flow through the toaster when connected to a voltage source (in this case, 120 V).
High resistance means less current flows and, subsequently, less energy conversion occurs, impacting the performance of devices like heaters or toasters. Understanding this helps in designing circuits with desired power and energy characteristics.

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Most popular questions from this chapter

A sheet of gold foil (negligible thickness) is placed between the plates of a capacitor and has the same area as each of the plates. The foil is parallel to the plates, at a position one-third of the way from one to the other. Before the foil is inserted, the capacitance is \(C_{0}\). What is the capacitance after the foil is in place? Express your answer in terms of \(C_{0}\) -

An electric heater is used to boil small amounts of water and consists of a \(15-\Omega\) coil that is immersed directly in the water. It operates from a \(120-\mathrm{V}\) socket. How much time is required for this heater to raise the temperature of \(0.50 \mathrm{~kg}\) of water from \(13^{\circ} \mathrm{C}\) to the normal boiling point?

A piece of Nichrome wire has a radius of \(6.5 \times 10^{-4} \mathrm{~m}\). It is used in a laboratory to make a heater that uses \(4.00 \times 10^{2} \mathrm{~W}\) of power when connected to a voltage source of \(120 \mathrm{~V}\). Ignoring the effect of temperature on resistance, estimate the necessary length of wire.

Concept Question Two capacitors, \(C_{1}\) and \(C_{2}\), are connected to a battery whose voltage is \(V\). Recall from Section \(19.5\) that the electrical energy stored by each capacitor is \(\frac{1}{2} C_{1} V_{1}^{2}\) and \(\frac{1}{2} C_{2} V_{2}^{2}\), where \(V_{1}\) and \(V_{2}\) are, respectively, the voltages across \(C_{1}\) and \(C_{2}\). If the capacitors are connected in series, is the total energy stored by them greater than, less than, or equal to the total energy stored when they are connected in parallel? Justify your answer. Problem The battery voltage is \(V=60.0 \mathrm{~V}\), and the capacitances are \(C_{1}=2.00 \mu \mathrm{F}\) and \(C_{2}=4.00 \mu \mathrm{F}\). Determine the total energy stored by the two capacitors when they are wired (a) in parallel and (b) in series. Check to make sure that your answer is consistent with your answer to the Concept Question.

A \(60.0-\Omega\) resistor is connected in parallel with a \(120-\Omega\) resistor. This parallel group is connected in series with a \(20.0-\Omega\) resistor. The total combination is connected across a \(15.0\) - \(\mathrm{V}\) battery. Find (a) the current and (b) the power delivered to the \(120.0-\Omega\) resistor.

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