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Three identical resistors are connected in parallel. The equivalent resistance increases by \(700-\Omega\) when one resistor is removed and connected in series with the remaining two, which are still in parallel. Find the resistance of each resistor.

Short Answer

Expert verified
The resistance of each resistor is 600 \(\Omega\).

Step by step solution

01

Understand the Problem

We have three identical resistors connected in parallel, which are then reorganized into a series-parallel configuration. We need to find the resistance of each resistor based on the change in equivalent resistance.
02

Equivalent Resistance in Parallel Configuration

For three identical resistors, each of resistance \(R\), connected in parallel, the equivalent resistance \(R_1\) is given by:\[\frac{1}{R_1} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{3}{R}\]Thus, \(R_1 = \frac{R}{3}\).
03

Equivalent Resistance After Reconfiguration

When one resistor is removed and added in series with the remaining two (still in parallel), the configuration changes. First, find the equivalent resistance of the two parallel resistors:\[\frac{1}{R_2} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R}\]So, \(R_2 = \frac{R}{2}\).Then, add the resistance of the third resistor in series:\[R_{eq} = R + \frac{R}{2} = \frac{3R}{2}\].
04

Set Up the Equation Based on Resistance Increase

According to the problem, the equivalent resistance increases by \(700-\Omega\) when reconfigured:\[\frac{3R}{2} = \frac{R}{3} + 700\].
05

Solve the Equation for R

Rearrange the equation to solve for \(R\):\[\frac{3R}{2} - \frac{R}{3} = 700\]Find a common denominator and simplify:\[\left(\frac{9R}{6} - \frac{2R}{6}\right) = 700\]\[\frac{7R}{6} = 700\]Multiply both sides by 6:\[7R = 4200\]Divide by 7:\[R = 600 \Omega\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel Resistors
Understanding parallel resistors can be quite straightforward! When resistors are connected in parallel, they share the same two nodes. This means that the voltage across each resistor is the same, but the current can vary through each one.
In a parallel configuration, the total or equivalent resistance decreases. The formula to calculate the equivalent resistance for parallel resistors is:- If you have three identical resistors with resistance \( R \), the formula is given by: \[ \frac{1}{R_{eq}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R}. \] This implies that the equivalent resistance \( R_1 \) is \( \frac{R}{3} \).
Lowering the equivalent resistance allows a parallel circuit to carry more current than a series circuit with the same resistors. This is why parallel circuits are commonly used in wiring systems where maintaining the voltage across devices is essential. Parallel resistors effectively decrease the overall resistance, resulting in a greater current flow for a given applied voltage. This is a handy property when designing electrical circuits that require a consistent voltage level.
Series Resistors
When resistors are connected in series, the current that flows through them is the same, but the voltage across each one might be different. The combined resistance in a series circuit is always more than the resistance of any individual resistor in the chain.
The formula for the equivalent resistance of resistors in series is simple: you simply add them together!- For instance, if you have three resistors in series each of resistance \( R \), the equivalent resistance \( R_{eq} \) would be: \[ R_{eq} = R + R + R = 3R. \]In our problem, we first had two resistors in parallel (which we calculated previously) and then added a third one in series.
Therefore, the equivalent resistance after reconfiguring became the resistance of the initially parallel resistors plus the third one in series. This led us to a key equation in solving the problem: we observe a substantial increase in resistance when one resistor is added in series with parallel resistors.
This characteristic makes series circuits useful in applications where increased resistance can help limit current or distribute voltage among components.
Resistance Calculation
Calculating equivalent resistance often involves understanding the configuration of resistors. The transition from parallel to a series-parallel setup in our problem provides insight into these calculations.
Here are some calculation principles:- **For parallel resistors**: The reciprocal of the total resistance is the sum of the reciprocals of each resistance. So, for three identical resistors of resistance \( R \): \[ \frac{1}{R_1} = \frac{3}{R}. \]- **For series resistors**: Simply add the resistances directly. For example, if two resistors in parallel were \( \frac{R}{2} \), adding a third one in series would give: \[ R_{eq} = R + \frac{R}{2} = \frac{3R}{2}. \]To solve real-world problems, like in our exercise, it is crucial to set up equations reflecting the known and unknown values, combining rules for both series and parallel connections.
-- We used the difference in equivalent resistance noticed by reconfiguring the resistors, setting up the equation: \[ \frac{3R}{2} = \frac{R}{3} + 700. \]- From there, solving algebraically allowed us to find the resistance of each resistor, \( R = 600 \Omega \).
Mastering these calculations paves the way for effectively managing electrical circuits – key for everything from simple household circuits to complex industrial systems.

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Most popular questions from this chapter

In measuring a voltage, a voltmeter uses some current from the circuit. Consequently, the voltage measured is only an approximation to the voltage present when the voltmeter is not connected. Consider a circuit consisting of two \(1550-\Omega\) resistors connected in series across a \(60.0-\mathrm{V}\) battery. (a) Find the voltage across one of the resistors. (b) A voltmeter has a full-scale voltage of \(60.0 \mathrm{~V}\) and uses a galvanometer with a full-scale deflection of \(5.00 \mathrm{~mA}\). Determine the voltage that this voltmeter registers when it is connected across the resistor used in part (a).

Three capacitors \((4.0,6.0\), and \(12.0 \mu \mathrm{F})\) are connected in series across a \(50.0-\mathrm{V}\) battery. Find the voltage across the \(4.0-\mu \mathrm{F}\) capacitor.

The total current delivered to a number of devices connected in parallel is the sum of the individual currents in each device. Circuit breakers are resettable automatic switches that protect against a dangerously large total current by "opening" to stop the current at a specified safe value. A 1650 -W toaster, a 1090 -W iron, and a 1250 -W microwave oven are turned on in a kitchen. As the drawing shows, they are all connected through a 20 -A circuit breaker to an ac voltage of \(120 \mathrm{~V}\). (a) Find the equivalent resistance of the three devices. (b) Obtain the total current delivered by the source and determine whether the breaker will "open" to prevent an accident.

The average power used by a stereo speaker is \(55 \mathrm{~W}\). Assuming that the speaker can be treated as a \(4.0-\Omega\) resistance, find the peak value of the ac voltage applied to the speaker.

A new "D" battery has an emf of \(1.5 \mathrm{~V}\). When a wire of negligible resistance is connected between the terminals of the battery, a current of \(28 \mathrm{~A}\) is produced. Find the internal resistance of the battery.

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