/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 A Boeing 747 "Jumbo Jet" has a l... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A Boeing 747 "Jumbo Jet" has a length of \(59.7 \mathrm{~m}\). The runway on which the plane lands intersects another runway. The width of the intersection is \(25.0 \mathrm{~m} .\) The plane decelerates through the intersection at a rate of \(5.70 \mathrm{~m} / \mathrm{s}^{2}\) and clears it with a final speed of \(45.0 \mathrm{~m} / \mathrm{s}\). How much time is needed for the plane to clear the intersection?

Short Answer

Expert verified
The plane takes approximately 0.537 seconds to clear the intersection.

Step by step solution

01

Identify Known Variables

First, let's identify and list all the known values given in the problem: the initial speed of the plane before entering the intersection is unknown, the final speed (\(v_f\)) as it clears the intersection is \(45.0 \, \mathrm{m/s}\), the deceleration rate (\(a\)) is \(-5.70 \, \mathrm{m/s}^{2}\), and the distance (\(d\)) the plane travels during the intersection is \(25.0 \, \mathrm{m}\).
02

Use Kinematic Equation to Find Initial Speed

We will use the kinematic equation \(v_f^2 = v_i^2 + 2ad\) to find the initial speed \(v_i\). Rearranging the equation to solve for \(v_i\):\[ v_i^2 = v_f^2 - 2ad \]Substitute the known values:\[ v_i^2 = (45.0)^2 - 2(-5.70)(25.0) \]\[ v_i^2 = 2025 + 285 \]\[ v_i^2 = 2310 \]\[ v_i = \sqrt{2310} \approx 48.06 \, \mathrm{m/s} \]
03

Calculate Time to Clear Intersection

With the initial speed \(v_i\) calculated, use the kinematic equation \(v_f = v_i + at\) to find the time \(t\). Solving for \(t\):\[ t = \frac{v_f - v_i}{a} \]Substitute the known values:\[ t = \frac{45.0 - 48.06}{-5.70} \]\[ t = \frac{-3.06}{-5.70} \]\[ t \approx 0.537 \, \mathrm{seconds} \]
04

Final Step: Conclusion

The plane will take approximately \(0.537\) seconds to clear the intersection.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Speed Calculation
Understanding how to calculate the initial speed in a kinematics problem is essential. Here, the problem involves a Boeing 747 that decelerates as it crosses an intersection. We're given the final speed of the plane, the deceleration rate, and the distance it travels. However, we're not directly given the initial speed, which is crucial to solving the problem. To find it, we use the kinematic equation:\[ v_f^2 = v_i^2 + 2ad \]We are solving for the initial speed, \(v_i\). To do this, rearrange the equation:\[ v_i^2 = v_f^2 - 2ad \]Once rearranged, you substitute the known values of \(v_f\), \(a\), and \(d\) to solve for \(v_i\). Remember, the square root of the result gives the initial speed. This process is fundamental for determining how fast an object was moving before any changes to its speed. It provides a critical starting point for solving the rest of the problem.
Kinematic Equations
Kinematic equations are the mathematical representations of motion, providing relationships between different motion parameters. These equations are pivotal in solving problems related to linear motion, such as speed, velocity, acceleration, and distance.When dealing with constant acceleration, the kinematic equations become particularly useful. Here are the primary equations used:
  • \( v = u + at \)
  • \( s = ut + \frac{1}{2}at^2 \)
  • \( v^2 = u^2 + 2as \)
  • \( s = \frac{(u + v)t}{2} \)
In the exercise, the second equation is used to determine the initial speed, while the first one is employed to calculate the time taken for the plane to pass the intersection. By understanding each variable, you gain the ability to swap and solve for any unknown in a motion problem. These equations form the backbone of many physics problems and enable deep comprehension of motion mechanics.
Deceleration
Deceleration is a specific type of acceleration that refers to the slowing down of an object. It is represented by a negative acceleration value. In the context of the exercise with the Boeing 747, the deceleration is given as \(-5.70 \, \mathrm{m/s}^2\). This means the plane is reducing its speed by that amount every second.Deceleration is crucial in scenarios where objects need to slow down before stopping or before reaching a certain goal, like a plane landing on a runway. It's calculated using the same principles as acceleration but focuses on decreasing speed. The formula for deceleration can still be part of the broader kinematic equations:\[ v_f = v_i + at \]In this situation, the negative sign of the deceleration impacts how you set up your equations; it tells you that the final speed will be less than the initial speed. By properly incorporating deceleration into your calculations, you account for how rapidly an object's speed decreases over time.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car makes a trip due north for three-fourths of the time and due south one- fourth of the time. The average northward velocity has a magnitude of \(27 \mathrm{~m} / \mathrm{s},\) and the average southward velocity has a magnitude of \(17 \mathrm{~m} / \mathrm{s}\). What is the average velocity, magnitude and direction, for the entire trip?

The Space Shuttle travels at a speed of about \(7.6 \times 10^{3} \mathrm{~m} / \mathrm{s}\). The blink of an astronaut's eye lasts about \(110 \mathrm{~ms}\). How many football fields (length \(=91.4 \mathrm{~m}\) ) does the Shuttle cover in the blink of an eye?

A speedboat starts from rest and accelerates at \(+2.01 \mathrm{~m} / \mathrm{s}^{2}\) for \(7.00 \mathrm{~s}\). At the end of this time, the boat continues for an additional \(6.00 \mathrm{~s}\) with an acceleration of \(+0.518 \mathrm{~m} / \mathrm{s}^{2}\) Following this, the boat accelerates at \(-1.49 \mathrm{~m} / \mathrm{s}^{2}\) for \(8.00 \mathrm{~s}\). (a) What is the velocity of the boat at \(t=21.0 \mathrm{~s} ?\) (b) Find the total displacement of the boat.

Review Interactive Solution 2.29 at in preparation for this problem. Suppose a car is traveling at \(20.0 \mathrm{~m} / \mathrm{s},\) and the driver sees a traffic light turn red. After \(0.530 \mathrm{~s}\) has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at \(7.00 \mathrm{~m} / \mathrm{s}^{2}\). What is the stopping distance of the car, as measured from the point where the driver first notices the red light?

Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up for \(402 \mathrm{~m}\) with an acceleration of \(+17.0 \mathrm{~m} / \mathrm{s}^{2}\). A parachute then opens, slowing the car down with an acceleration of \(-6.10 \mathrm{~m} / \mathrm{s}^{2} .\) How fast is the racer moving \(3.50 \times 10^{2} \mathrm{~m}\) after the parachute opens?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.