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(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of \(8.0 \mathrm{~m} / \mathrm{s}\) when going down a slope for \(5.0 \mathrm{~s} ?\) (b) How far does the skier travel in this time?

Short Answer

Expert verified
The skier's average acceleration is \(1.6 \, \text{m/s}^2\), and the distance traveled is 20 meters.

Step by step solution

01

Identify Initial Conditions

The skier starts from rest, so the initial velocity \( u = 0 \, \text{m/s} \). After \( t = 5.0 \, \text{s} \), the final velocity \( v = 8.0 \, \text{m/s} \). We need to find the average acceleration and the distance traveled.
02

Calculate Average Acceleration

The formula for average acceleration \( a \) is given by:\[ a = \frac{v - u}{t} \]Substitute the known values: \( v = 8.0 \, \text{m/s} \), \( u = 0 \, \text{m/s} \), and \( t = 5.0 \, \text{s} \).\[ a = \frac{8.0 \, \text{m/s} - 0 \, \text{m/s}}{5.0 \, \text{s}} = \frac{8.0}{5.0} = 1.6 \, \text{m/s}^2 \]
03

Apply Kinematic Equation for Distance

To find the distance \( s \), we use the equation:\[ s = ut + \frac{1}{2}at^2 \]Substitute \( u = 0 \, \text{m/s} \), \( a = 1.6 \, \text{m/s}^2 \), and \( t = 5.0 \, \text{s} \):\[ s = 0 + \frac{1}{2} \times 1.6 \, \text{m/s}^2 \times (5.0 \, \text{s})^2 \]\[ s = 0.8 \times 25 = 20 \, \text{m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations are essential tools in physics that help describe motion. These equations deal with variables like initial velocity, final velocity, acceleration, time, and distance. Understanding these relationships allows us to predict the movement of objects.
In the context of our skier problem, we apply two key kinematic equations. The first one is used to determine average acceleration, while the second helps us find the distance traveled. Both equations rely on known values like initial and final velocities and time, showcasing the interconnectedness of motion variables.
To calculate average acceleration, we use:
  • \( a = \frac{v - u}{t} \)
Then, to find distance traveled:
  • \( s = ut + \frac{1}{2}at^2 \)
These equations offer a structured way to solve dynamic problems, helping us break down complex motions into understandable pieces.
Initial Velocity
Initial velocity is the speed at which an object starts its motion. It is a crucial part of kinematic analysis as it often provides a starting point for calculations. In many problems, the initial velocity can be zero, indicating that the object starts from rest.
In our skier exercise, the initial velocity (
  • \( u = 0 \text{ m/s} \)
) reflects the fact that the skier begins from a stationary position at the top of the slope. By understanding and correctly identifying initial velocity, we can accurately apply kinematic equations to study subsequent motion. Whether the task is to predict how quickly an object reaches a certain speed, or how far it travels in a defined time, initial velocity is often the first parameter defined.
Distance Traveled
Distance traveled is a measure of how far an object moves over a period of time. In kinematics, understanding how to calculate distance requires integrating acceleration, time, initial velocity, and sometimes final velocity.
  • The basic equation to find distance when acceleration is steady is:
  • \( s = ut + \frac{1}{2}at^2 \)
This formula comes in handy in scenarios like our skier example, where initial velocity is zero, and we know both acceleration and time. By substituting these known values, we compute the total distance. In this problem, after calculating, the skier travels a distance of 20 meters down the slope.
Without accurate distance calculations, predicting where an object will end up or confirming a physics model’s reality can be difficult. Thus, understanding and calculating distance is vital to interpreting any physical motion.
Final Velocity
Final velocity is the speed at which an object is moving after a specified period of time or at the end of a motion event. This concept is key in comprehending the full spectrum of an object's journey, especially when initial velocity and acceleration are known.
In our skier situation, the final velocity (
  • \( v = 8.0 \text{ m/s} \)
) is what the skier achieves at the bottom of the slope after accelerating down. Calculating final velocity, or understanding it in context, can reveal the total change in an object's speed during motion.
Recognizing final velocity helps in analyzing how forces like gravity, friction, and applied powers interact. In our exercise, it marks the culmination of acceleration starting from rest, driving a clearer image of the skier's dynamic experience.

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Most popular questions from this chapter

A penny is dropped from rest from the top of the Sears Tower in Chicago. Considering that the height of the building is \(427 \mathrm{~m}\) and ignoring air resistance, find the speed with which the penny strikes the ground.

An 18 -year-old runner can complete a \(10.0\) -km course with an average speed of \(4.39 \mathrm{~m} / \mathrm{s}\). A 50 -year-old runner can cover the same distance with an average speed of \(4.27 \mathrm{~m} / \mathrm{s}\). How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?

A jetliner, traveling northward, is landing with a speed of \(69 \mathrm{~m} / \mathrm{s}\). Once the jet touches down, it has \(750 \mathrm{~m}\) of runway in which to reduce its speed to \(6.1 \mathrm{~m} / \mathrm{s}\). Compute the average acceleration (magnitude and direction) of the plane during landing.

Interactive Solution \(2.31\) at offers help in modeling this problem. A car is traveling at a constant speed of \(33 \mathrm{~m} / \mathrm{s}\) on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is \(2.5 \mathrm{~km}\) away?

The initial velocity \(v_{0}\) and acceleration \(a\) of four moving objects at a given instant in time are given in the table: $$ \begin{array}{|c|c|c|} \hline & \text { Initial velocity } v_{0} & \text { Acceleration } a \\ \hline \text { (a) } & +12 \mathrm{~m} / \mathrm{s} & +3.0 \mathrm{~m} / \mathrm{s}^{2} \\ \hline \text { (b) } & +12 \mathrm{~m} / \mathrm{s} & -3.0 \mathrm{~m} / \mathrm{s}^{2} \\ \hline \text { (c) } & -12 \mathrm{~m} / \mathrm{s} & +3.0 \mathrm{~m} / \mathrm{s}^{2} \\ \hline \text { (d) } & -12 \mathrm{~m} / \mathrm{s} & -3.0 \mathrm{~m} / \mathrm{s}^{2} \\ \hline \end{array} $$ Draw vectors for \(v_{0}\) and \(a\) and, in each case, state whether the speed of the object is increasing or decreasing in time. Account for your answers. Problem For each of the four pairs in the table above, determine the final speed of the object if the elapsed time is \(2.0 \mathrm{~s}\). Compare your final speeds with the initial speeds and make sure that your answers are consistent with your answers to the Concept Questions.

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