/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 In a discussion person \(\mathrm... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a discussion person \(\mathrm{A}\) is talking \(1.5 \mathrm{~dB}\) louder than person \(\mathrm{B},\) and person \(\mathrm{C}\) is talking \(2.7 \mathrm{~dB}\) louder than person \(\mathrm{A}\). What is the ratio of the sound intensity of person \(\mathrm{C}\) to the sound intensity of person \(\mathrm{B} ?\)

Short Answer

Expert verified
The ratio of sound intensity is approximately 2.63.

Step by step solution

01

Understanding the Decibel Formula

The decibel (dB) scale is a logarithmic scale used to compare sound intensities. The formula for sound intensity level in decibels is given by \( L = 10 \log_{10}(I/I_0) \), where \( L \) is the sound level in decibels, \( I \) is the intensity of the sound, and \( I_0 \) is a reference intensity.
02

Establishing Relationships Between Intensities

We know that person A is talking 1.5 dB louder than person B, and person C is talking 2.7 dB louder than person A. The total difference in decibels between person C and person B is 1.5 + 2.7 = 4.2 dB.
03

Using the Intensity Ratio Formula

To find the intensity ratio, use the formula for decibels: \( \,\Delta L = 10 \log_{10}(I_C/I_B) \). Here \( \,\Delta L = 4.2 \). Thus, \( \log_{10}(I_C/I_B) = 0.42 \).
04

Solving for the Intensity Ratio

To find \( I_C/I_B \), rearrange the equation from the previous step: \( I_C/I_B = 10^{0.42} \).
05

Calculating the Exact Ratio

Compute the value of \( 10^{0.42} \) using a calculator to get the exact intensity ratio. This gives \( I_C/I_B \approx 2.63 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Intensity
Sound intensity refers to the amount of energy carried by sound waves per unit area in a direction perpendicular to that area. It represents the strength or power of a sound wave and is measured in watts per square meter (W/m²). In simpler terms, it helps us understand how "loud" a sound is at a particular point.

When we talk about sound intensity, we are focusing on the physical attribute of sound that can be quantified. Intensity determines how much energy is transmitted through the air to your ears.

Keep in mind:
  • High sound intensity can lead to a louder perceived sound.
  • Intensity diminishes with distance from the sound source.
  • It is a crucial factor in fields like acoustics and audio engineering.
Understanding sound intensity is essential in the context of discussing decibels, which use it as a basis for comparison.
Logarithmic Scale
The logarithmic scale is a way of displaying numerical data over a very wide range of values in a condensed manner. In acoustics, the decibel (dB) scale is logarithmic, meaning each step on the scale represents a tenfold increase or decrease in actual sound intensity.

This scale is particularly useful for measuring sound because the human ear perceives sound intensity logarithmically rather than linearly. For example, an increase of 10 dB roughly corresponds to a tenfold increase in the sound energy and is perceived as "twice as loud".

Some highlights of logarithmic scales:
  • They allow us to represent very large or very small ranges of data in a scaled-down manner.
  • A small increase in decibels can correspond to a large increase in intensity.
  • They help in many scientific calculations where exponential growth or decrease is present.
This is why we use the log scale in sound measurements, helping to quantify "louder" or "quieter" more tangibly.
Sound Level
Sound level, as measured in decibels (dB), represents the loudness or intensity of sound as perceived by the human ear. The sound level is calculated using the formula:
\[ L = 10 \log_{10}(I/I_0) \] where:
  • \( L \) is the sound level in decibels.
  • \( I \) is the intensity of the sound.
  • \( I_0 \) is the reference intensity, typically set as the threshold of hearing (\(10^{-12} \) W/m²).
This calculation allows us to compare the loudness of different sounds.
For example, if one person is speaking at 1.5 dB louder than another, it doesn't seem like much on the linear scale, but it indicates a more noticeable difference in perceived sound intensity. Similarly, a sound level 3 dB higher will have double the intensity of another.

A practical aspect of sound level involves:
  • Understanding environmental noise conditions.
  • Setting audio equipment accurately.
  • Processing sound signals in various technological applications.
Sound levels in decibels provide a consistent, standardized way of assessing and calculating sound intensity, crucial for both everyday life and scientific exploration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The security alarm on a parked car goes off and produces a frequency of \(960 \mathrm{~Hz}\). The speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). As you drive toward this parked car, pass it, and drive away you observe the frequency to change by \(95 \mathrm{~Hz}\). At what speed are you driving?

A wave traveling in the \(+x\) direction has an amplitude of \(0.35 \mathrm{~m},\) a speed of \(5.2 \mathrm{~m} /\) \(\mathrm{s},\) and a frequency of \(14 \mathrm{~Hz}\). Write the equation of the wave in the form given by either Equation 16.3 or 16.4

Consider the freight train in Figure 16 -6. Suppose 15 boxcars pass by in a time of \(12.0 \mathrm{~s}\) and each has a length of \(14.0 \mathrm{~m}\). (a) What is the frequency at which each boxcar passes? (b) What is the speed of the train?

A wave has the following properties: amplitude \(=0.37 \mathrm{~m}\), period \(=0.77 \mathrm{~s}\), wave speed \(=12 \mathrm{~m} / \mathrm{s} .\) The wave is traveling in the \(-x\) direction. What is the mathematical expression (similar to Equation 16.3 or 16.4 ) for the wave?

Consult Multiple-Concept Example 11 in order to review a model for solving this type of problem. A car is accelerating while its horn is blowing. Just after the car passes a stationary person, the person hears a frequency of \(966.0 \mathrm{~Hz}\). Fourteen seconds later, the frequency heard by the person has decreased to \(912.0 \mathrm{~Hz}\). When the car is stationary, its horn emits a sound whose frequency is \(1.00 \times 10^{3} \mathrm{~Hz}\). The speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). What is the acceleration of the car?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.