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How much heat is required to change the temperature of \(1.5 \mathrm{~mol}\) of a monatomic ideal gas by \(77 \mathrm{~K}\) if the pressure is held constant?

Short Answer

Expert verified
2399.78 J

Step by step solution

01

Identify the formula

To find the heat required to change the temperature of a gas at constant pressure, we use the formula: \( q = nC_p\Delta T \), where \( q \) is the heat added, \( n \) is the number of moles, \( C_p \) is the molar heat capacity at constant pressure, and \( \Delta T \) is the temperature change.
02

Determine the molar heat capacity

For a monatomic ideal gas, the molar heat capacity at constant pressure \( C_p \) is given by \( \frac{5}{2}R \), where \( R = 8.314\, \text{J/mol K} \). Calculate \( C_p \): \( C_p = \frac{5}{2} \times 8.314 = 20.785 \, \text{J/mol K} \).
03

Use the formula to calculate heat

Substitute the values into the formula: \( q = 1.5 \times 20.785 \times 77 \). This represents the heat required to change the temperature by 77 K for 1.5 moles of a monatomic ideal gas at constant pressure.
04

Perform the multiplication

Calculate \( q = 1.5 \times 20.785 \times 77 = 2399.78 \) J. This is the total heat required.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental equation in thermodynamics that describes the behavior of an ideal gas. It is expressed as \( PV = nRT \), where:
  • \( P \) is the pressure of the gas,
  • \( V \) is the volume,
  • \( n \) is the number of moles,
  • \( R \) is the gas constant (8.314 J/mol K),
  • \( T \) is the temperature in Kelvin.
This equation provides a relationship between the pressure, volume, and temperature of a gas, assuming it behaves ideally. In our exercise, we are dealing with a monatomic ideal gas, which means it perfectly follows the ideal gas law without any deviations. Understanding this law helps in solving problems related to gas behavior under varying conditions such as changes in pressure, volume, or temperature.
Heat Capacity
Heat capacity is an important concept in thermodynamics that describes the amount of heat required to change the temperature of a substance by a certain amount. It is usually expressed in terms of two conditions: constant volume (\( C_V \)) and constant pressure (\( C_P \)). For different substances, the heat capacity can vary.
In our problem, we focus on the heat capacity at constant pressure since the pressure of the gas is held constant while changing its temperature. This heat capacity helps determine how much energy is needed to increase the temperature of the specified amount of gas. Heat capacity is crucial for understanding how energy transfers within substances and is often a key component in thermodynamic calculations.
Molar Heat Capacity
Molar heat capacity refers to the heat capacity per mole of a substance. It is a refined form of heat capacity expressed as \( C = \frac{Q}{n \Delta T} \), where \( Q \) is the heat, \( n \) is the number of moles, and \( \Delta T \) is the temperature change. The unit is usually J/mol K.
For an ideal gas, the molar heat capacity at constant pressure \( (C_p) \) differs based on the nature of the gas. For a monatomic ideal gas, \( C_p \) is given by \( \frac{5}{2}R \), making it a straightforward multiplication involving the universal gas constant \( R \). Understanding molar heat capacity is crucial for predicting how much heat energy is required to change the temperature of a mole of gas under constant pressure.
Temperature Change
Temperature change is a critical factor in thermodynamic problems, representing how much the temperature of a substance alters due to energy exchange. It is described by the temperature difference \( \Delta T = T_f - T_i \), where \( T_f \) is the final temperature and \( T_i \) is the initial temperature.
In the context of our exercise, the problem states a temperature change of 77 K. This change, combined with the number of moles and the molar heat capacity, determines the total heat required for the desired temperature shift. Understanding the concept of temperature change is essential for proper thermodynamic computation and for predicting energy flows in various processes.
Constant Pressure Process
A constant pressure process signifies that the pressure in a system does not change as other parameters, such as temperature and volume, are altered. This is often referred to in thermodynamics as an isobaric process.
In our problem, since pressure is held constant, the heat required is calculated using specific formulas that take into account the constant pressure constraint. Constant pressure processes are significant in many chemical and physical contexts, helping simplify equations and making calculations more manageable. Knowledge of these processes helps in understanding and solving a variety of thermodynamic problems.

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Most popular questions from this chapter

A monatomic ideal gas is heated while at a constant volume of \(1.00 \times 10^{-3} \mathrm{~m}^{3}\), using a ten-watt heater. The pressure of the gas in creases by \(5.0 \times 10^{4} \mathrm{~Pa}\). How long was the heater on?

Five thousand joules of heat is put into a Carnot engine whose hot and cold reservoirs have temperatures of 500 and \(200 \mathrm{~K}\), respectively. How much heat is converted into work?

A mountain climber, starting from rest, does work in climbing upward. At the if top, she is again at rest. In the process, her body generates \(4.1 \times 10^{6} \mathrm{~J}\) of energy via metabolic processes. In fact, her body acts like a heat engine, the efficiency of which is given by Equation 15.11 as \(e=|W| /\left|Q_{\mathrm{H}}\right|,\) where \(|W|\) is the magnitude of the work and \(\left|Q_{\mathrm{H}}\right|\) is the magnitude the input heat. (a) Is the \(4.1 \times 10^{6} \mathrm{~J}\) of energy equal to \(|W|\) or to \(\left|Q_{\mathrm{H}}\right| ?\) (b) How is the work done in climbing upward related to the vertical height of the climb? Explain. Problem The vertical height of the climb is \(730 \mathrm{~m}\). The climber has a mass of \(52 \mathrm{~kg}\). Find her efficiency as a heat engine.

In moving out of a dormitory at the end of the semester, a student does \(1.6 \times 10^{4} \mathrm{~J}\) of work. In the process, his internal energy decreases by \(4.2 \times 10^{4} \mathrm{~J}\). Determine each of the following quantities (including the algebraic sign): (a) \(W,(\mathrm{~b}) \Delta U\) and \((\mathrm{c}) Q\)

Refer to Interactive Solution 15.87 at for help in solving this problem. A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignite the fuel occurs because the pistons compress the air in the cylinders. Suppose air at an initial temperature of \(21^{\circ} \mathrm{C}\) is compressed adiabatically to a temperature of \(688^{\circ} \mathrm{C}\). Assume the air to be an ideal gas for which \(\gamma=\frac{7}{5} .\) Find the compression ratio, which is the ratio of the initial volume to the final volume.

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