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The average value of the squared speed \(v^{2}\) does not equal the square of the average speed \((\bar{v})^{2}\). To verify this fact, consider three particles with the following speeds: \(v_{1}=3.0 \mathrm{~m} / \mathrm{s}, v_{2}=7.0 \mathrm{~m} / \mathrm{s},\) and \(v_{3}=9.0 \mathrm{~m} / \mathrm{s} .\) Calculate \((\mathrm{a}) \bar{v}^{\overline{2}}=\frac{1}{3}\left(v_{1}^{2}+v_{2}^{2}+v_{3}^{2}\right)\) and (b) \((\bar{v})^{2}=\left[\frac{1}{3}\left(v_{1}+v_{2}+v_{3}\right)\right]^{2}\).

Short Answer

Expert verified
\(\bar{v}^{\overline{2}} = 46.33 \neq (\bar{v})^2 = 40.11\), hence the two averages differ.

Step by step solution

01

Identify and Square Each Speed

Given the speeds of the particles as \( v_1 = 3.0 \mathrm{~m/s}, v_2 = 7.0 \mathrm{~m/s}, v_3 = 9.0 \mathrm{~m/s} \). Start by squaring each speed. \( v_1^2 = 9, v_2^2 = 49, v_3^2 = 81 \).
02

Calculate Average of Squared Speeds

Calculate the average of the squared speeds using the formula \( \bar{v}^{\overline{2}} = \frac{1}{3}(v_1^2 + v_2^2 + v_3^2) \). Substitute the squared values: \( \bar{v}^{\overline{2}} = \frac{1}{3}(9 + 49 + 81) = \frac{139}{3} \approx 46.33 \).
03

Calculate Average Speed

Compute the average speed using the formula \( \bar{v} = \frac{1}{3}(v_1 + v_2 + v_3) \). Substitute the given speeds: \( \bar{v} = \frac{1}{3}(3 + 7 + 9) = \frac{19}{3} \approx 6.33 \mathrm{~m/s} \).
04

Square the Average Speed

Now, square the average speed \((\bar{v})^2\). So, \((\bar{v})^2 = (\frac{19}{3})^2 = \frac{361}{9} \approx 40.11 \).
05

Comparison of Results

Compare the results of \( \bar{v}^{\overline{2}} = 46.33 \) and \((\bar{v})^2 = 40.11 \). Notice that \( \bar{v}^{\overline{2}} eq (\bar{v})^2 \), verifying the initial statement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Squared Speed
When examining speeds, it is useful to consider the concept of squared speed. Squaring a speed simply means multiplying the speed by itself. For example, if a particle moves at a speed of 3 m/s, the squared speed will be \( (3 \, \mathrm{m/s})^2 = 9 \, \mathrm{m^2/s^2} \).
This is important in physics because squaring is commonly used when analyzing kinetic energy or variance in speeds. By dealing with squared speeds, we get rid of direction, focusing solely on magnitude.
In exercises involving multiple particles, like in our example with speeds 3, 7, and 9 m/s, squaring those gives us 9, 49, and 81 \( \mathrm{m^2/s^2} \) respectively.
The squared speed concept simplifies complex dynamics by turning vector quantities into scalar quantities, making further calculations more straightforward.
Average Value
In math, finding the average is a way of determining the central value of a set of numbers. To find the average, you sum up all the numbers and then divide that sum by the number of values.
For instance, to find the average squared speed (\( \bar{v}^{\overline{2}} \)) of particles, you'd calculate as follows:
  • Add the squared speeds: \( 9 + 49 + 81 = 139 \)
  • Then, divide by 3 (the number of values): \( \frac{139}{3} \approx 46.33 \)
This gives the average squared speed.
It's essential to differentiate between averaging the speeds first and squaring the result, versus averaging squared speeds directly, as these procedures yield very different results.
While similar, these averages can convey distinct information, especially in physics where variance and data dispersion are critical.
Particle Speed
Particle speed refers to the rate at which a particle moves through space. In our example, speeds of particles are given as 3 m/s, 7 m/s, and 9 m/s.
The speed of a particle gives us a scalar quantity - it has magnitude but no direction. This characteristic makes it straightforward to compute overall measures like average speed. Calculating an average speed involves adding all particle speeds and dividing by the number of particles:
  • Sum of speeds: 3 + 7 + 9 = 19 m/s
  • Average speed: \( \frac{19}{3} = 6.33 \, \mathrm{m/s} \)
Particle speed is not merely a mathematical term; it's crucial in assessing the behavior of a system or material as particles, such as gas molecules, often move at varying speeds.
Understanding differences between speeds and their squared values can further illuminate the dynamics of the particle ensemble.
Mathematical Proof
Mathematical proof allows us to verify or refute statements using logic. In the given exercise, we used proof to show that the average squared speed does not equal the squared average speed.
The verification process involved calculating both \( \bar{v}^{\overline{2}} \) and \((\bar{v})^2\) separately.
  • Calculate \( \bar{v}^{\overline{2}} \): Add squared speeds (9, 49, 81), divide by the count: \( \frac{139}{3} \approx 46.33 \)
  • Calculate \((\bar{v})^2\): Average actual speeds, then square it: \((6.33)^2 \approx 40.11 \)
By comparing these values, we concluded that \( \bar{v}^{\overline{2}} eq (\bar{v})^2 \), proving our initial statement that they are not equivalent.
This example illustrates how mathematical proof is not only about verifying a calculation but also demonstrating relationships between variables in physics and mathematics.

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The average value of the squared speed \(\overline{v^{2}}\) does not equal the square of the average speed \((\bar{v})^{2}\). To verify this fact, consider three particles with the following speeds: \(v_{1}=3.0 \mathrm{~m} / \mathrm{s}, v_{2}=7.0 \mathrm{~m} / \mathrm{s}\), and \(v_{3}=9.0 \mathrm{~m} / \mathrm{s} .\) Calculate (a) \(\overline{v^{2}}=\frac{1}{3}\left(v_{1}^{2}+v_{2}^{2}+v_{3}^{2}\right)\) and (b) \((\bar{v})^{2}=\left[\frac{1}{3}\left(v_{1}+v_{2}+v_{3}\right)\right]^{2}\).

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