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A solid cylinder (radius \(=0.150 \mathrm{~m},\) height \(=0.120 \mathrm{~m}\) ) has a mass of \(7.00 \mathrm{~kg}\). This cylinder is floating in water. Then oil \(\left(\rho=725 \mathrm{~kg} / \mathrm{m}^{3}\right)\) is poured on top of the water until the situation shown in the drawing results. How much of the height of the cylinder is in the oil?

Short Answer

Expert verified
0.0432 m of the cylinder is in the oil.

Step by step solution

01

Understand the problem

We need to find the height of the cylinder that is submerged in oil, given that it floats both in water and oil.
02

Calculate the volume of the cylinder

The volume of a cylinder is given by the formula \( V = \pi r^2 h \). Here, \( r = 0.150 \text{ m} \) and \( h = 0.120 \text{ m} \). Plugging in these values, we get \( V = \pi \times (0.150)^2 \times 0.120 \). Calculate this to find the volume.
03

Calculate buoyant force required for equilibrium

The buoyant force must equal the weight of the cylinder for balance. The weight \( W = m \times g = 7.00 \times 9.81 \). Thus, the buoyant force \( F_b = 7.00 \times 9.81 \).
04

Volume of water displaced

Since the cylinder is floating, the total weight of the displaced fluid equals the cylinder's weight. First find how much of the cylinder's volume is submerged by water using the density of water (\(1000 \text{ kg/m}^3\)). Use \( V_{water} = \frac{m \times g}{\rho_{water} \times g} \). This simplifies to \( V_{water} = \frac{m}{\rho_{water}} \).
05

Volume of oil displaced

Now use the balance of forces to find the volume of oil displaced. \( V_{oil} = V_{total} - V_{water} \), based on the total volume of the cylinder calculated previously.
06

Find the height of the cylinder in oil

The volume in the oil \( V_{oil} = \pi \times r^2 \times h_{oil} \). Solve for \( h_{oil} \) using \( V_{oil} \) from Step 5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' principle
Archimedes' principle is a fundamental concept in fluid mechanics that describes the buoyancy experienced by objects submerged in a fluid. It states that an object submerged in a fluid is buoyed up by a force equal to the weight of the fluid that it displaces.
In our given problem, where a cylinder is floating in both water and oil, Archimedes' principle allows us to determine how much of the cylinder's volume will be submerged in each fluid. Since the total buoyant force is equal to the weight of the cylinder, this principle allows us to calculate the volume of water and oil displaced.
Understanding Archimedes' principle helps us see why objects float or sink depending on how their weight compares to the weight of the fluid they displace. In the case of the cylinder, the oil and water together provide enough buoyant force to keep it floating.
Fluid mechanics
Fluid mechanics is the branch of physics concerned with the behavior of fluids (liquids and gases) and the forces on them. This discipline provides the tools needed to solve problems involving fluid motion and equilibrium.
When analyzing our floating cylinder, fluid mechanics principles are applied to understand the interaction between the cylinder, the water, and the oil. It allows us to understand how these liquid layers support the floating object through buoyancy.
Fluid mechanics involves concepts such as pressure, buoyancy, and viscosity, which are crucial for predicting how fluids behave under various conditions. By applying these principles, we can solve complex problems, such as calculating the portion of a cylinder submerged in displacing fluids.
Density
Density is a property that measures how much mass is contained in a given volume of a substance, usually expressed as \( \rho = \frac{m}{V} \). This characteristic is pivotal in determining how much of an object will float or submerge in a fluid due to buoyancy.
In the context of the cylinder submersed in water and oil, density plays a key role in understanding the situation. The oil's density of 725 kg/m³ compared to the water's higher density of 1000 kg/m³ affects how much buoyant force each liquid exerts on the cylinder.
The differences in density explain why only a certain portion of the cylinder's height is submerged in oil, as water provides a stronger buoyant lift due to its higher density.
Displacement
Displacement in fluid mechanics refers to the amount of fluid that is moved out of place when an object is submerged in a fluid. It directly ties into Archimedes' principle, where the displaced volume helps determine the buoyant force.
For the floating cylinder, the concept of displacement means the water and oil displaced by the cylinder's volume provide the necessary force to support its weight.
To find how much of the cylinder is immersed in oil, we first calculate how much water is displaced by using the \( V_{water} = \frac{m}{\rho_{water}} \). Once this is known, the remaining volume represents the displacement in the oil, which helps determine the height of the cylinder submerged in oil.

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Most popular questions from this chapter

A blood transfusion is being set up in an emergency room for an accident victim. Blood has a density of \(1060 \mathrm{~kg} / \mathrm{m}^{3}\) and a viscosity of \(4.0 \times 10^{-3} \mathrm{~Pa} \cdot \mathrm{s}\). The needle being used has a length of \(3.0 \mathrm{~cm}\) and an inner radius of \(0.25 \mathrm{~mm} .\) The doctor wishes to use a volume flow rate through the needle of \(4.5 \times 10^{-8} \mathrm{~m}^{3} / \mathrm{s}\). What is the distance \(h\) above the victim's arm where the level of the blood in the transfusion bottle should be located? As an approximation, assume that the level of the blood in the transfusion bottle and the point where the needle enters the vein in the arm have the same pressure of one atmosphere. (In reality, the pressure in the vein is slightly above atmospheric pressure.)

Prairie dogs are burrowing rodents. They do not suffocate in their burrows, because the effect of air speed on pressure creates sufficient air circulation. The animals maintain a difference in the shapes of two entrances to the burrow, and because of this difference, the air \(\left(\rho=1.29 \mathrm{~kg} / \mathrm{m}^{3}\right)\) blows past the openings at different speeds, as the drawing indicates. Assuming that the openings are at the same vertical level, find the difference in air pressure between the openings and indicate which way the air circulates.

One of the concrete pillars that support a house is \(2.2 \mathrm{~m}\) tall and has a radius of \(0.50 \mathrm{~m}\). The density of concrete is about \(2.2 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\). Find the weight of this pillar in pounds \((1 \mathrm{~N}=0.2248 \mathrm{lb})\).

A 58 -kg skier is going down a slope oriented \(35^{\circ}\) above the horizontal. The area of each ski in contact with the snow is \(0.13 \mathrm{~m}^{2}\). Determine the pressure that each ski exerts on the snow.

A suitcase (mass \(m=16 \mathrm{~kg}\) ) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures \(0.50 \mathrm{~m}\) by \(0.15 \mathrm{~m} .\) The elevator is moving upward, the magnitude of its acceleration being \(1.5 \mathrm{~m} / \mathrm{s}^{2}\). What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

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