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An archer, about to shoot an arrow, is applying a force of \(+240 \mathrm{~N}\) to a drawn bowstring. The bow behaves like an ideal spring whose spring constant is \(480 \mathrm{~N} / \mathrm{m}\). What is the displacement of the bowstring?

Short Answer

Expert verified
The displacement is 0.5 meters.

Step by step solution

01

Understand the Problem

We need to determine the displacement of the bowstring when a force is applied to it. The bow behaves like an ideal spring, so we will use Hooke's Law to solve this problem.
02

Hooke's Law Formula

Hooke's Law is expressed as \( F = kx \), where \( F \) is the force applied, \( k \) is the spring constant, and \( x \) is the displacement of the spring (or the bow).
03

Rearrange the Formula

To find the displacement \( x \), we need to rearrange the formula to \( x = \frac{F}{k} \).
04

Substitute Given Values

We substitute the given values into the formula: \( F = 240 \text{ N} \) and \( k = 480 \text{ N/m} \). So we have \( x = \frac{240}{480} \).
05

Calculate the Displacement

Now, perform the division: \( x = \frac{240}{480} = 0.5 \). Thus, the displacement of the bowstring is 0.5 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Spring Constant
The spring constant, denoted as \( k \), is a fundamental concept when dealing with springs, particularly in systems like bows that mimic spring behavior. It represents the stiffness or rigidity of a spring. A higher spring constant indicates a stiffer spring, which requires more force to achieve the same displacement compared to a spring with a lower constant.
To visualize this, imagine trying to stretch a rubber band versus a steel spring. The steel spring would have a higher spring constant because it is much harder to stretch. In our exercise, the bow's spring constant is given as \( 480 \text{ N/m} \), suggesting it is relatively stiff and requires a substantial force to achieve significant displacement.
  • Measured in Newtons per meter (N/m).
  • Directly proportional to the force applied.
  • Determines how much force is needed for a unit of displacement.
Understanding the spring constant helps in predicting how the bowstring will respond when force is applied. It's crucial for designing systems that require precise control over force and movement.
Force and Displacement Connection
A pivotal concept in physics, the link between force and displacement is beautifully illustrated through Hooke's Law. When a force \( (F) \) is applied to a spring or a spring-like object, it causes the object to move, or displace. This displacement \( (x) \) is directly proportional to the force applied and inversely proportional to the spring constant \( (k) \).
According to Hooke's Law, the formula \( F = kx \) elegantly encapsulates this relationship. In our scenario:
  • \( F = 240 \text{ N} \) is the force exerted by the archer pulling the bowstring.
  • \( k = 480 \text{ N/m} \) is the spring constant of the bow modeled as a spring.
  • \( x \) is the displacement we want to calculate.
Rearranging the formula to \( x = \frac{F}{k} \) allows us to directly calculate how far the bowstring is pulled back. It's essential as understanding this relationship aids in predicting how different forces will alter the position of the bowstring, impacting the arrow's potential energy and trajectory.
Characteristics of an Ideal Spring
The term "ideal spring" in physics represents a theoretical model of a spring that obeys Hooke's Law perfectly. In this model, a spring's force and displacement are linearly related without any deformation or change in its properties, irrespective of how much stress is applied within its elastic limit.
An ideal spring is characterized by:
  • No energy loss due to heat.
  • No permanent deformation.
  • Response solely based on Hooke's Law \( F = kx \).
Our exercise uses the analogy of an ideal spring to describe the behavior of the bow. This simplifies the calculation as it assumes linear elasticity, meaning the relationship between force and displacement remains constant throughout the range of motion. Although no physical spring or bow can be truly ideal, this concept helps in understanding and simplifying complex physical systems, such as the bow being treated like an ideal spring for ease of calculation.

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Most popular questions from this chapter

A small ball is attached to one end of a spring that has an unstrained length of 0.200 \(\mathrm{m}\). The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of \(3.00 \mathrm{~m} / \mathrm{s}\). The spring remains nearly parallel to the ground during the motion and is observed to stretch by \(0.010 \mathrm{~m}\). By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?

A simple pendulum is made from a \(0.65-\mathrm{m}\) -long string and a small ball attached to its free end. The ball is pulled to one side through a small angle and then released from rest. After the ball is released, how much time elapses before it attains its greatest speed?

A rifle fires a \(2.10 \times 10^{-2}\) kg pellet straight upward, because the pellet rests on a compressed spring that is released when the trigger is pulled. The spring has a negligible mass and is compressed by \(9.10 \times 10^{-2} \mathrm{~m}\) from its unstrained length. The pellet rises to a maximum height of \(6.10 \mathrm{~m}\) above its position on the compressed spring. Ignoring air resistance, determine the spring constant.

A tray is moved horizontally back and forth in simple harmonic motion at a frequency of \(f=2.00 \mathrm{~Hz}\). On this tray is an empty cup. Obtain the coefficient of static friction between the tray and the cup, given that the cup begins slipping when the amplitude of the motion is \(5.00 \times 10^{-2} \mathrm{~m}\).

A \(15.0-\mathrm{kg}\) block rests on a horizontal table and is attached to one end of a massless, horizontal spring. By pulling horizontally on the other end of the spring, someone causes the block to accelerate uniformly and reach a speed of \(5.00 \mathrm{~m} / \mathrm{s}\) in \(0.500 \mathrm{~s}\). In the process, the spring is stretched by \(0.200 \mathrm{~m}\). The block is then pulled at a constant speed of \(5.00 \mathrm{~m} / \mathrm{s}\), during which time the spring is stretched by only \(0.0500 \mathrm{~m}\). Find (a) the spring constant of the spring and (b) the coefficient of kinetic friction between the block and the table

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