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Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is about \(f=2.0 \times 10^{12} \mathrm{~Hz},\) and the amplitude is about \(1.1 \times 10^{-11} \mathrm{~m}\). For a typical atom, what is its (a) maximum speed and (b) maximum acceleration?

Short Answer

Expert verified
Maximum speed is approximately 138 m/s, and maximum acceleration is approximately \(1.09 \times 10^{15}\) m/s².

Step by step solution

01

Identify the given values

The problem gives us the frequency of vibration as \( f = 2.0 \times 10^{12} \, \mathrm{Hz} \) and the amplitude as \( A = 1.1 \times 10^{-11} \, \mathrm{m} \). We need to find the maximum speed and acceleration of the atom.
02

Use the formula for maximum speed

For simple harmonic motion, the maximum speed \( v_{max} \) is given by \( v_{max} = 2 \pi f A \). Substitute the given frequency and amplitude into this formula: \[ v_{max} = 2 \pi \times 2.0 \times 10^{12} \, \mathrm{Hz} \times 1.1 \times 10^{-11} \, \mathrm{m} \].
03

Calculate the maximum speed

Calculate \( v_{max} \) using the formula: \[ v_{max} = 2 \pi \times 2.0 \times 10^{12} \times 1.1 \times 10^{-11} \]. Calculate the result: \[ v_{max} \approx 1.38 \times 10^{2} \, \mathrm{m/s} \].
04

Use the formula for maximum acceleration

The maximum acceleration \( a_{max} \) in simple harmonic motion is given by \( a_{max} = (2 \pi f)^2 A \). Substitute the values: \[ a_{max} = (2 \pi \times 2.0 \times 10^{12})^2 \times 1.1 \times 10^{-11} \].
05

Calculate the maximum acceleration

Calculate \( a_{max} \) using the formula: \[ a_{max} = (2 \pi \times 2.0 \times 10^{12})^2 \times 1.1 \times 10^{-11} \]. This results in \[ a_{max} \approx 1.09 \times 10^{15} \, \mathrm{m/s^2} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vibration of Atoms
Atoms in a solid are dynamic, constantly vibrating around their equilibrium positions. This means they are never at rest, which is a fascinating aspect of their existence. These vibrations arise due to energy present at the atomic level, even at very low temperatures. The movement can be described using simple harmonic motion principles, which provide a framework for understanding how atoms displace and move back and forth from their equilibrium points.
  • The vibrations are akin to a spring-mass system, where atoms oscillate similar to a mass attached to a spring.
  • Simple harmonic motion assumes the restoring force is proportional to the displacement, hence being predictable and cyclic.
These vibrations are crucial, as they influence the physical properties of materials, including their thermal and electrical conductivities. Understanding atomic vibrations allows scientists to predict how materials behave under various temperature conditions.
Maximum Speed
In the context of simple harmonic motion, an atom's maximum speed happens when it passes through its equilibrium position. At this point, the kinetic energy is at its peak, making the velocity the highest it will be during the cycle. The formula to calculate this maximum speed is \( v_{max} = 2 \pi f A \), where:
  • \( f \) is the frequency of vibration, and
  • \( A \) is the amplitude of the motion.
By substituting the known values for an atom, the equation lets us find \( v_{max} \) easily. The maximum speed helps in understanding how energetically atoms are moving, which in turn affects how they interact and bond with each other within materials.
Maximum Acceleration
For simple harmonic motion, the atom's maximum acceleration is found when the atom is at its maximum displacement, that is, at the extremes of its motion. At these points, the force acting on the atom is also at its maximum, pushing it back towards its equilibrium point. Maximum acceleration is calculated using the formula: \( a_{max} = (2 \pi f)^2 A \). This equation indicates the acceleration is dependent on both the square of the frequency and the amplitude.
  • This highlights that a small change in frequency can significantly impact the acceleration, given it is squared.
  • Similarly, greater amplitude will also increase \( a_{max} \), making the system more dynamic.
Understanding this helps in assessing how forces within a material change, affecting its stability and reactions to external forces.
Frequency and Amplitude
Frequency and amplitude are key parameters in describing simple harmonic motion. Frequency, denoted as \( f \), is the number of cycles an atom completes per second and is measured in Hertz (Hz). It informs us about the energy level associated with the vibrations.
  • Higher frequencies mean higher energy, leading to more vigorous atomic motion.
  • They also affect how sound waves propagate through various materials.
Amplitude, represented as \( A \), is the maximum extent of displacement from the equilibrium position. It reflects the intensity of the motion. The amplitude doesn't change the speed but tells us how far the atom travels from its resting position.
  • Large amplitudes imply atoms have more space to move, which can influence how they interact with each other.
  • Amplitude affects the material's thermal properties, such as expansion when heated.
Understanding frequency and amplitude allows scientists to better manipulate material characteristics for various applications, such as designing temperature-resistant materials.

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Most popular questions from this chapter

Multiple-Concept Example 6 presents a model for solving this problem. As far as vertical oscillations are concerned, a certain automobile can be considered to be mounted on four identical springs, each having a spring constant of \(1.30 \times 10^{5} \mathrm{~N} / \mathrm{m}\). Four identical passengers sit down inside the car, and it is set into a vertical oscillation that has a period of \(0.370 \mathrm{~s}\). If the mass of the empty car is \(1560 \mathrm{~kg}\), determine the mass of each passenger. Assume that the mass of the car and its passengers is distributed evenly over the springs.

A \(15.0\) -kg block rests on a horizontal table and is attached to one end of a massless, horizontal spring. By pulling horizontally on the other end of the spring, someone causes the block to accelerate uniformly and reach a speed of \(5.00 \mathrm{~m} / \mathrm{s}\) in \(0.500 \mathrm{~s}\). In the process, the spring is stretched by \(0.200 \mathrm{~m}\). The block is then pulled at a constant speed of \(5.00 \mathrm{~m} / \mathrm{s}\), during which time the spring is stretched by only \(0.0500 \mathrm{~m}\). Find (a) the spring constant of the spring and (b) the coefficient of kinetic friction between the block and the table.

A student's CD player is mounted on four cylindrical rubber blocks. Each cylinder has a height of \(0.030 \mathrm{~m}\) and a cross-sectional area of \(1.2 \times 10^{-3} \mathrm{~m}^{2}\), and the shear modulus for rubber is \(2.6 \times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\). If a horizontal force of magnitude \(32 \mathrm{~N}\) is applied to the CD player, how far will the unit move sideways? Assume that each block is subjected to one-fourth of the force.

A \(30.0\) -kg block is resting on a flat horizontal table. On top of this block is resting a \(15.0\) kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is \(325 \mathrm{~N} / \mathrm{m}\). The coefficient of kinetic friction between the lower block and the table is \(0.600\), and the coefficient of static friction between the two blocks is \(0.900\). A horizontal force \(\overrightarrow{\mathbf{F}}\) is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed. At the point where the upper block begins to slip on the lower block, determine (a) the amount by which the spring is compressed and (b) the magnitude of the force \(\overrightarrow{\mathbf{F}}\).

If the period of a simple pendulum is to be \(2.0 \mathrm{~s},\) what should be its length?

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