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Vector \(\overrightarrow{\mathrm{A}}\) has a magnitude of 6.00 units and points due east. Vector \(\overrightarrow{\mathrm{B}}\) points due north. (a) What is the magnitude of \(\overrightarrow{\mathbf{B}},\) if the vector \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) points \(60.0^{\circ}\) north of east? (b) Find the magnitude of \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\).

Short Answer

Expert verified
(a) Magnitude of \(\overrightarrow{B}\) is approximately 10.39 units. (b) Magnitude of \(\overrightarrow{A} + \overrightarrow{B}\) is approximately 12.00 units.

Step by step solution

01

Understanding Vector Components

Start by considering vector \(\overrightarrow{\mathrm{A}}\) which is entirely in the east (x-direction) with a magnitude of 6.00 units. It therefore has components \(A_x = 6.00\) and \(A_y = 0\).
02

Expressing \(\overrightarrow{B}\) in Components

Since \(\overrightarrow{\mathrm{B}}\) points due north, it only has a y-component. Let \(B_y = B\) and \(B_x = 0\) for vector \(\overrightarrow{\mathrm{B}}\).
03

Using the Resultant Vector Direction

The vector sum \(\overrightarrow{\mathrm{A}} + \overrightarrow{\mathrm{B}}\) is given as \(60^{\circ}\) north of east. Use the tangent function for the angle: \(\tan(60^{\circ}) = \frac{\text{Total y-component}}{\text{Total x-component}} = \frac{B}{6.00}\).
04

Calculating Magnitude of \(\overrightarrow{B}\)

Since \(\tan(60^{\circ}) = \sqrt{3}\), we set \(\frac{B}{6.00} = \sqrt{3}\). Solving for \(B\), we find \(B = 6.00 \times \sqrt{3} \approx 10.39\) units.
05

Magnitude of the Resultant Vector

The components of the resultant vector \(\overrightarrow{\mathrm{A}} + \overrightarrow{\mathrm{B}}\) are \(A_x + B_x = 6.00 + 0 = 6.00\) (x-component) and \(A_y + B_y = 0 + 10.39 = 10.39\) (y-component).
06

Calculating Magnitude of \(\overrightarrow{\mathrm{A}} + \overrightarrow{\mathrm{B}}\)

Use the Pythagorean theorem: The magnitude is \(\sqrt{(6.00)^2 + (10.39)^2} = \sqrt{36 + 107.98} = \sqrt{143.98} \approx 12.00\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resultant Vector
In physics, understanding how two or more vectors combine to form a "resultant vector" is essential. The resultant vector is what you get when you add two or more individual vectors together. Think of vectors as arrows that show direction and have a certain length (magnitude). When you add vectors, you're essentially looking for the single vector that has the same effect as both of the original ones put together.

To find a resultant vector, you need to consider both the direction and magnitude of each contributing vector. This often involves breaking down each vector into its horizontal and vertical components and then combining these components. The direction of the resultant vector can also be described using an angle, which shows how far north or east (or in other directions) the vector points.
  • It is essential to understand the influence of both the direction and magnitude when adding vectors.
  • The angle of the resultant makes it easy to visualize how the components interact.
Vector Components
When dealing with vectors, breaking them down into "vector components" makes calculations easier. Particularly in the Cartesian coordinate system, any vector can be resolved into a horizontal (x-axis) and vertical (y-axis) component. Each component can be considered independently when analyzing the vector's effect.

For example, a vector with a magnitude pointing due east is fully represented along the x-axis. If another vector points due north, it will have only a y-component. By resolving vectors this way, you can add them more easily by separately summing their respective components.
  • Horizontal vector components affect the movement along the x-axis.
  • Vertical components determine the movement along the y-axis.
Breaking vectors into components can simplify the math, especially when vectors point in different directions.
Magnitude Calculation
"Magnitude calculation" is vital for finding out how much effect a vector has in terms of size or quantity. Magnitude determines the "length" of a vector and is usually calculated using the Pythagorean theorem when dealing with two-dimensional components.

In the case of adding vectors such as \(\overrightarrow{\mathrm{A}} + \overrightarrow{\mathrm{B}}\), once you have the x and y components, the magnitude can be found using the formula:

\[\text{Magnitude} = \sqrt{A_x^2 + B_y^2}\]

This mathematical approach allows us to deal with vector combinations using simple algebra. Plus, it shows the importance of geometry in physics by connecting various conceptual components.
  • The Pythagorean theorem helps calculate the total effect of combined vectors.
  • Accurate magnitude measurements are crucial in correctly representing vector impacts.
Understanding magnitude is crucial for interpreting physical quantities such as force, velocity, and displacement in real-world scenarios.

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Most popular questions from this chapter

In wandering, a grizzly bear makes a displacement of \(1563 \mathrm{~m}\) due west, followed by a displacement of \(3348 \mathrm{~m}\) in a direction \(32.0^{\circ}\) north of west. What are (a) the magnitude and (b) the direction of the displacement needed for the bear to return to its starting point? Specify the direction relative to due east.

An ocean liner leaves New York City and travels \(18.0^{\circ}\) north of east for \(155 \mathrm{~km}\). How far east and how far north has it gone? In other words, what are the magnitudes of the components of the ship's displacement vector in the directions (a) due east and (b) due north?

The speed of an object and the direction in which it moves constitute a vector quantity known as the velocity. An ostrich is running at a speed of \(17.0 \mathrm{~m} / \mathrm{s}\) in a direction of \(68.0^{\circ}\) north of west. What is the magnitude of the ostrich's velocity component that is directed (a) due north and (b) due west?

To review the solution to a similar problem, consult Interactive Solution \(1.37\) at . The magnitude of the force vector \(\vec{F}\) is \(82.3\) newtons. The \(x\) component of this vector is directed along the \(+x\) axis and has a magnitude of \(74.6\) newtons. The \(y\) component points along the \(+y\) axis. (a) Find the direction of \(\overrightarrow{\mathbf{F}}\) relative to the \(+x\) axis. (b) Find the component of \(\overrightarrow{\mathbf{F}}\) along the \(+y\) axis.

(a) Two workers are trying to move a heavy crate. One pushes on the crate with a force \(\vec{A}\), which has a magnitude of 445 newtons and is directed due west. The other pushes with a force \(\vec{B}\), which has a magnitude of 325 newtons and is directed due north. What are the magnitude and direction of the resultant force \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) applied to the crate? (b) Suppose that the second worker applies a force \(-\overrightarrow{\mathrm{B}}\) instead of \(\overrightarrow{\mathrm{B}}\). What then are the magnitude and direction of the resultant force \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\) applied to the crate? In both cases express the direction relative to due west.

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