/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Multiple-Concept Example 9 deals... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Multiple-Concept Example 9 deals with the concepts that are important in this problem. A grasshopper makes four jumps. The displacement vectors are (1) \(27.0 \mathrm{~cm}\), due west; (2) \(23.0 \mathrm{~cm}, 35.0^{\circ}\) south of west; (3) \(28.0 \mathrm{~cm}, 55.0^{\circ}\) south of east; and (4) \(35.0 \mathrm{~cm}, 63.0^{\circ}\) north of east. Find the magnitude and direction of the resultant displacement. Express the direction with respect to due west.

Short Answer

Expert verified
The resultant displacement is approximately 26.6 cm at 9.27° south of west.

Step by step solution

01

Convert Vectors to Components

First, let's convert each displacement vector into its x (west-east) and y (south-north) components. 1. For vector 1: \( x_1 = -27.0 \text{ cm}\) (since it's due west, all in the negative x) and \( y_1 = 0 \text{ cm} \).2. For vector 2: \( x_2 = -23.0 \cos(35.0^{\circ}) \) \( y_2 = -23.0 \sin(35.0^{\circ}) \) (south is negative y).3. For vector 3: \( x_3 = 28.0 \cos(55.0^{\circ}) \) \( y_3 = -28.0 \sin(55.0^{\circ}) \) (south is negative y).4. For vector 4: \( x_4 = 35.0 \cos(63.0^{\circ}) \) \( y_4 = 35.0 \sin(63.0^{\circ}) \) (north is positive y).
02

Calculate Component Sums

Now calculate the sum of all x and y components:\[x_{\text{total}} = x_1 + x_2 + x_3 + x_4 = -27.0 + (-23.0\cos(35.0^{\circ})) + (28.0\cos(55.0^{\circ})) + (35.0\cos(63.0^{\circ}))\]\[y_{\text{total}} = y_1 + y_2 + y_3 + y_4 = 0 + (-23.0\sin(35.0^{\circ})) + (-28.0\sin(55.0^{\circ})) + (35.0\sin(63.0^{\circ}))\]
03

Calculate Resultant Magnitude

The magnitude of the resultant vector \( R \) can be found using the Pythagorean theorem:\[R = \sqrt{(x_{\text{total}})^2 + (y_{\text{total}})^2}\]
04

Determine Direction

Calculate the direction \( \theta \) with respect to due west using the tangent function:\[\theta = \tan^{-1}\left(\frac{y_{\text{total}}}{x_{\text{total}}}\right)\]This angle \( \theta \) is measured counter-clockwise from due west. Make sure to adjust for the correct quadrant based on the signs of \( x_{\text{total}} \) and \( y_{\text{total}} \).
05

Evaluate Results

Compute the numerical answers for each component, the resultant magnitude, and the angle. Perform all calculations step by step to ensure accuracy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Understanding vector components is key when analyzing any vector quantity, such as displacement. Vectors have both magnitude and direction. To simplify calculations, we often break them down into components along the x-axis (horizontal) and y-axis (vertical). This is especially useful when dealing with multiple vectors in different directions.

- For each vector, use trigonometry to convert it into x and y components. - Use \( x = r \cos(\theta) \) for the x-component.- Use \( y = r \sin(\theta) \) for the y-component. - The angle \( \theta \) is measured from the positive x-axis, so adjust accordingly when the direction is specified differently.

In our problem, the vectors were converted using angles measured from specific directions, so careful attention was paid to the trigonometric sign conventions: west implies negative x, while south implies negative y. By breaking up the initial vectors into components, we can more easily sum them to find the resultant vector.
Resultant Vector
The resultant vector gives us the overall effect of combining multiple vectors. Once each vector is broken into components, the next step is to find the sum of these components to determine the resultant vector of the system.

- Sum up all x-components to get \( x_{\text{total}} \).- Sum up all y-components to get \( y_{\text{total}} \).

The resultant vector then is simply the combination of \( x_{\text{total}} \) and \( y_{\text{total}} \).

This vector represents the overall displacement in our grasshopper problem and shows how all individual vectors interact to result in a single direction and magnitude of movement. Visualizing this as one vector rather than four separate ones helps us understand the total effect of all jumps.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental tool in finding the magnitude of the resultant vector from its components. Given the sum of x and y components, you can think of them as forming the two legs of a right triangle, with the resultant vector as the hypotenuse.

Using the equation:
\[ R = \sqrt{(x_{\text{total}})^2 + (y_{\text{total}})^2} \]
calculate the magnitude of the resultant vector.

This formula calculates the straight-line distance (or displacement) from the starting point to the ending point of the grasshopper's jumps, giving a clearer perspective of the total movement rather than just using directional components.
Angle Calculation
After finding the magnitude of the resultant vector, the next step is to determine its direction. This involves calculating the angle \( \theta \) the vector makes with a reference direction.

- Use the formula: \[ \theta = \tan^{-1}\left(\frac{y_{\text{total}}}{x_{\text{total}}}\right) \]This will give you the angle of the resultant vector counter-clockwise from due west.

It is important to consider the signs of \( x_{\text{total}} \) and \( y_{\text{total}} \) to determine the correct quadrant in which the angle lies. - If \( x \) is negative and \( y \) is positive, the angle is indeed counter-clockwise from west.
This ensures accurate representation of direction, crucial in applications from navigation to physics, ensuring the angle is always correctly interpreted.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Vector \(\overrightarrow{\mathrm{A}}\) points along the \(+y\) axis and has a magnitude of \(100.0\) units. Vector \(\overrightarrow{\mathbf{B}}\) points at an angle of \(60.0^{\circ}\) above the \(+x\) axis and has a magnitude of \(200.0\) units. Vector \(\vec{C}\) points along the \(+x\) axis and has a magnitude of \(150.0\) units. Which vector has (a) the largest \(x\) component and (b) the largest \(y\) component?

You are on a treasure hunt and your map says "Walk due west for 52 paces, then walk \(30.0^{\circ}\) north of west for 42 paces, and finally walk due north for 25 paces." What is the magnitude of the component of your displacement in the direction (a) due north and (b) due west?

A force vector points at an angle of \(52^{\circ}\) above the \(+x\) axis. It has a \(y\) component of +290 newtons. Find (a) the magnitude and (b) the \(x\) component of the force vector.

Vector \(\overrightarrow{\mathrm{A}}\) points due west, while vector \(\overrightarrow{\mathbf{B}}\) points due south. (a) Does the direction \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) point north or south of due west? (b) Does the direction of \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\) point north or south of due west? Give your reasoning in each case. Vector \(\overrightarrow{\mathbf{A}}\) has a magnitude of 63 units and points due west, while vector \(\overrightarrow{\mathbf{B}}\) has the same magnitude and points due south. Find the magnitude and direction of (a) \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) and (b) \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\). Specify the directions relative to due west. Verify that your answers agree with your answers to the Concept Questions.

The route followed by a hiker consists of three displacement vectors \(\overrightarrow{\mathrm{A}}, \overrightarrow{\mathrm{B}},\) and \(\overrightarrow{\mathrm{C}}\). Vector \(\overrightarrow{\mathrm{A}}\) is along a measured trail and is \(1550 \mathrm{~m}\) in a direction \(25.0^{\circ}\) north of east. Vector \(\overrightarrow{\mathrm{B}}\) is not along a measured trail, but the hiker uses a compass and knows that the direction is \(41.0^{\circ}\) east of south. Similarly, the direction of vector \(\overrightarrow{\mathrm{C}}\) is \(35.0^{\circ}\) north of west. The hiker ends up back where she started, so the resultant displacement is zero, or \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}+\overrightarrow{\mathrm{C}}=0 .\) Find the magnitudes of \((\mathrm{a})\) vector \(\overrightarrow{\mathrm{B}}\) and \((\mathrm{b})\) vector \(\overrightarrow{\mathrm{C}}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.