/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 The drawing shows sodium and chl... [FREE SOLUTION] | 91Ó°ÊÓ

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The drawing shows sodium and chloride ions positioned at the corners of a cube that is part of the crystal structure of sodium chloride (common table salt). The edge of the cubs is \(0.281 \mathrm{nm}\left(1 \mathrm{nm}=1\right.\) nanometer \(\left.=10^{-9} \mathrm{~m}\right)\) in length. Find the distance (in nanometers) between the sodium ion located at one corner of the cube and the chloride ion located on the diagonal at the opposite corner.

Short Answer

Expert verified
The distance is approximately 0.486 nanometers.

Step by step solution

01

Understand the Cube Structure

A cube has its sides all equal in length. The sodium and chloride ions are at opposite corners of this cube, and we need to find the distance across the diagonal of the cube.
02

Determine the Formula for Diagonal of a Cube

The formula for the length of a diagonal in a cube with edge length \(a\) is \(\sqrt{3} \times a\). This formula comes from the Pythagorean theorem applied in three dimensions.
03

Substitute the Given Values into the Formula

The edge length \(a\) of the cube is given as \(0.281\, \text{nm}\). Substituting this into the diagonal formula gives us: \(\text{Diagonal} = \sqrt{3} \times 0.281\, \text{nm}\).
04

Perform the Calculation

Calculate the diagonal by multiplying \(\sqrt{3} \approx 1.732\) and \(0.281\, \text{nm}\): \[\text{Diagonal} = 1.732 \times 0.281 = 0.486\, \text{nm}.\]
05

Verify the Units

Ensure that all units are consistent and correctly stated in nanometers (nm) since the problem requires the answer in these units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sodium Chloride
Sodium chloride, commonly known as table salt, is an essential compound. It has a chemical formula of NaCl and is composed of sodium and chloride ions. Inside the crystal structure of sodium chloride, every sodium ion is surrounded by six chloride ions and vice versa. This arrangement forms a repeating pattern known as a face-centered cubic (FCC) lattice.
In sodium chloride crystals, the ions arrange themselves in a cube-like structure where each edge of the cube alternately hosts sodium and chloride ions. This kind of arrangement is highly efficient as it maximizes ionic bonding and stability of the crystal lattice.
Understanding the crystal structure is important when calculating distances between ions, as these often appear as cube-related problems in physics and chemistry.
Cube Diagonal
When dealing with cubic structures, understanding cube geometry is essential. One fundamental aspect is the calculation of the diagonal that spans from one cube corner to the opposite corner.
The cube diagonal is significant in crystal structures because it often measures the maximum distance between atoms or ions in the structure. In the context of a cube with edge length "a," the diagonal can be found by imagining a straight line passing through the center of the cube from one corner to the opposite corner.
This diagonal isn't just across one face of the cube but through the entire cube in three dimensions. The formula to find this is \[\text{Diagonal} = \sqrt{3} \times a\]which factors in the three-dimensionality of the cube.
Knowing this concept is vital, especially when transitioning from working with two-dimensional shapes to three-dimensional structures like those encountered in crystal lattices.
Pythagorean Theorem
The Pythagorean theorem is a cornerstone of geometry, often remembered by the formula \(a^2 + b^2 = c^2\) in the context of right triangles. But its usefulness extends beyond simple two-dimensional problems.
In the world of three-dimensional crystals, like the sodium chloride cubic lattice, the Pythagorean theorem helps find lengths across space, such as the cube diagonal. When each edge of the cube is equal, as it is in the sodium chloride crystal lattice, one can extend the Pythagorean theorem to three dimensions.
This simplification from applying it in three dimensions gives:\[\text{Diagonal} = \sqrt{3} \times a\]where "a" is the edge length. This formula aids in calculating distances between ions in cubic structures, helping understand spatial relationships in crystallography.
Thus, grasping the Pythagorean theorem in a three-dimensional framework opens the door to comprehending complex structures effectively.

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Most popular questions from this chapter

You are driving into St. Louis, Missouri, and in the distance you see the famous Gateway-to-the-West arch. This monument rises to a height of \(192 \mathrm{~m}\). You estimate your line of sight with the top of the arch to be \(2.0^{\circ}\) above the horizontal. Approximately how far (in kilometers) are you from the base of the arch?

The mass of the parasitic wasp Caraphractus cintus can be as small as \(5 \times 10^{-6} \mathrm{~kg}\). What is this mass in (a) grams (g), (b) milligrams (mg), and (c) micrograms\((\mu g) ?\)

A car is being pulled out of the mud by two forces that are applied by the two ropes shown in the drawing. The dashed line in the drawing bisects the \(30.0^{\circ}\) angle. The magnitude of the force applied by each rope is 2900 newtons. Arrange the force vectors tail to head and use the graphical technique to answer the following questions, (a) How much force would a single rope need to apply to accomplish the same effect as the two forces added together? (b) How would the single rope be directed relative to the dashed line?

Vector \(\vec{A}\) has a magnitude of \(6.00\) units and points due east. Vector \(\overrightarrow{\mathbf{B}}\) points due north. (a) What is the magnitude of \(\overrightarrow{\mathrm{B}}\), if the vector \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) points \(60.0^{\circ}\) north of east? (b) Find the magnitude of \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\).

To review the solution to a similar problem, consult Interactive Solution \(1.37\) at . The magnitude of the force vector \(\vec{F}\) is \(82.3\) newtons. The \(x\) component of this vector is directed along the \(+x\) axis and has a magnitude of \(74.6\) newtons. The \(y\) component points along the \(+y\) axis. (a) Find the direction of \(\overrightarrow{\mathbf{F}}\) relative to the \(+x\) axis. (b) Find the component of \(\overrightarrow{\mathbf{F}}\) along the \(+y\) axis.

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