/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A highway is to be built between... [FREE SOLUTION] | 91Ó°ÊÓ

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A highway is to be built between two towns, one of which lies \(35.0 \mathrm{~km}\) south and \(72.0 \mathrm{~km}\) west of the other. What is the shortest length of highway that can be built between the two towns, and at what angle would this highway be directed with respect to due west?

Short Answer

Expert verified
80.07 km at 26.57° south of due west.

Step by step solution

01

Understand the Problem

We need to find the shortest distance between two points, which can be represented as points on a Cartesian coordinate system. One town is 35.0 km south and 72.0 km west of the other town.
02

Set Up the Problem

Represent the position of the towns on a coordinate plane. Let's assume town A is at the origin (0, 0), then town B is at (-72, -35) because it is 72 km west and 35 km south of town A.
03

Use the Pythagorean Theorem

To find the shortest distance between the two points, use the Pythagorean theorem. The formula is given by \[ c = \sqrt{a^2 + b^2} \]where \( a = 72 \text{ km} \) and \( b = 35 \text{ km} \).
04

Calculate the Shortest Distance

Substitute the values into the formula:\[ c = \sqrt{72^2 + 35^2} \]Calculate:\[ c = \sqrt{5184 + 1225} \]\[ c = \sqrt{6409} \approx 80.07 \text{ km} \]So, the shortest length of highway is approximately 80.07 km.
05

Find the Angle with Respect to Due West

To find the angle, use the tangent function:\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{35}{72} \]To find \( \theta \), use the arctangent:\[ \theta = \arctan\left(\frac{35}{72}\right) \approx 26.57^\circ \]
06

Conclusion

The shortest length of highway that can be built between the two towns is approximately 80.07 km, and the highway is directed at an angle of approximately 26.57° south of due west.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Coordinate System
The Cartesian Coordinate System is a way to represent points in space using a pair of numerical coordinates. These coordinates are based on two fixed perpendicular lines, usually called axes. The horizontal axis is known as the x-axis, and the vertical axis as the y-axis.
In the context of the exercise, the position of the two towns is plotted on the Cartesian plane. We assume one town, Town A, is at the origin, (0, 0). Therefore, Town B, which is 72 km west and 35 km south of Town A, is placed at the coordinate (-72, -35).
  • The negative sign indicates direction: west (negative x-direction) and south (negative y-direction).
  • This coordinate system helps in visualizing distances and directions in a two-dimensional plane.
Understanding this setup makes it easier to solve problems involving distance and direction.
Distance Calculation
To calculate the shortest distance between two points on a plane, the Pythagorean theorem comes in handy. This theorem applies because the two points and the differences in their x and y coordinates form a right triangle.
The formula according to the Pythagorean theorem is \[ c = \sqrt{a^2 + b^2} \]
where \(a\) and \(b\) are the lengths of the two sides of the triangle, and \(c\) is the hypotenuse, representing the shortest distance.
  • The length \(a\) is the difference along the x-axis (72 km).
  • The length \(b\) is the difference along the y-axis (35 km).

Substituting these values into the formula, we get:\[ c = \sqrt{72^2 + 35^2} = \sqrt{5184 + 1225} = \sqrt{6409} \approx 80.07 \text{ km}\]
This result represents the shortest possible highway distance between the two towns.
Trigonometry
Trigonometry, the study of triangles, specifically right triangles, aids in finding more than just distances; it helps determine angles.
When you have a right triangle, as created by the two points on the Cartesian plane, trigonometric functions relate the angles of the triangle to the lengths of its sides.
In this case, we are interested in finding the angle between the shortest path (hypotenuse) and the horizontal x-axis.
  • The tangent function, \( \tan(\theta) \), relates the angle \(\theta\) to the opposite side (difference in y coordinates) and the adjacent side (difference in x coordinates).

The formula used here is:\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{35}{72} \]
From this, we can use the inverse tangent function to find \(\theta\). Understanding trigonometry is crucial for solving real-world problems involving direction and angles.
Angle Measurement
Once we have the tangent of the angle, the next step is to calculate the angle itself. This angle is measured from the west direction.
To find this angle, we use the arctangent function, denoted by \( \arctan \). The arctangent function will give us the measure of the angle whose tangent is a given number.
The calculation is:\[ \theta = \arctan\left(\frac{35}{72}\right) \approx 26.57^\circ \]
This result tells us that the highway makes an angle of approximately 26.57° south of due west.
  • An understanding of angles is essential in navigation and construction, as it dictates the precise direction in which something like a highway should be built.
Measuring angles correctly ensures that the constructed path is both optimal and accurate.

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Most popular questions from this chapter

The components of vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}\) and \(A_{y}\) (both positive), and the angle that it makes with respect to the positive \(x\) axis is \(\theta\). (a) Does increasing the component \(A_{x}\) (while holding \(A_{y}\) constant) increase or decrease the angle \(\theta\) ? (b) Does increasing the component \(A_{v}\) (while holding \(A_{r}\) constant) increase or decrease the angle \theta? Account for your answers. Problem (a) The components of displacement vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}=12 \mathrm{~m}\) and \(A_{y}=12 \mathrm{~m}\) Find \(\theta\). (b) The components of displacement vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}=17 \mathrm{~m}\) and \(A_{y}=12 \mathrm{~m}\) Find \(\theta\). (c) The components of displacement vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}=12 \mathrm{~m}\) and \(A_{y}=17 \mathrm{~m}\) Find \(\theta\). Be sure that your answers are consistent with your answers to the Concept Questions.

The route followed by a hiker consists of three displacement vectors \(\overrightarrow{\mathrm{A}}, \overrightarrow{\mathrm{B}},\) and \(\overrightarrow{\mathrm{C}}\). Vector \(\overrightarrow{\mathrm{A}}\) is along a measured trail and is \(1550 \mathrm{~m}\) in a direction \(25.0^{\circ}\) north of east. Vector \(\overrightarrow{\mathrm{B}}\) is not along a measured trail, but the hiker uses a compass and knows that the direction is \(41.0^{\circ}\) east of south. Similarly, the direction of vector \(\overrightarrow{\mathrm{C}}\) is \(35.0^{\circ}\) north of west. The hiker ends up back where she started, so the resultant displacement is zero, or \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}+\overrightarrow{\mathrm{C}}=0 .\) Find the magnitudes of \((\mathrm{a})\) vector \(\overrightarrow{\mathrm{B}}\) and \((\mathrm{b})\) vector \(\overrightarrow{\mathrm{C}}\)

In wandering, a grizzly bear makes a displacement of \(1563 \mathrm{~m}\) due west, followed by a displacement of \(3348 \mathrm{~m}\) in a direction \(32.0^{\circ}\) north of west. What are (a) the magnitude and (b) the direction of the displacement needed for the bear to return to its starting point? Specify the direction relative to due east.

The corners of a square lie on a circle of diameter \(D\). Each side of the square has a length \(L\). Is \(L\) smaller or larger than \(D ?\) Explain your reasoning using the Pythagorean theorem. In a \(1330-\mathrm{ft}^{2}\) apartment, how many square meters of area are there? Be sure that your answer is consistent with your answers to the Concept Questions. The diameter \(D\) of the circle is \(0.35 \mathrm{~m}\). Each side of the square has a length \(L\). Find \(L\). Be sure that your answer is consistent with your answer to the Concept Question.

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force \(\overrightarrow{\mathbf{F}}_{\mathbf{A}}\), as part \(a\) of the drawing shows. By itself, however, force \(\overrightarrow{\mathbf{F}}_{\mathbf{A}}\) is insufficient. Therefore, two additional forces \(\overrightarrow{\mathbf{F}}_{\mathbf{B}}\) and \(\overrightarrow{\mathbf{F}}_{\mathbf{C}}\) are applied, as in part \(b\) of the drawing. Each of these additional forces has the same magnitude \(F\). The magnitude of the resultant force acting on the elephant in part \(b\) of the drawing is twice that in part \(a\). Find the ratio \(F / F_{\mathrm{A}}\).

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