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Two \(72.0-\mathrm{kg}\) hockey players skating at \(5.45 \mathrm{m} / \mathrm{s}\) collide and stick together. If the angle between their initial directions was \(115^{\circ},\) what is their speed after the collision?

Short Answer

Expert verified
The speed after the collision is approximately 2.81 m/s.

Step by step solution

01

Understand the Problem

Two hockey players with equal masses are moving at the same speed and collide at an angle of 115° between their paths. We are to find their speed post-collision.
02

Analyze the Conservation of Momentum

Since the collision is perfectly inelastic (they stick together), we apply the law of conservation of momentum. The total momentum before the collision in both the x and y directions should equal the total momentum after the collision.
03

Set Up Momentum Equations

The momentum of each player can be expressed individually in terms of x and y components. For player 1: \( p_{x1} = mv \) and \( p_{y1} = 0 \). For player 2, we use trigonometry: \( p_{x2} = mv \cos(115^{\circ}) \) and \( p_{y2} = mv \sin(115^{\circ}) \).
04

Calculate Total Initial Momentum

The total initial momentum in the x-direction is \( p_{x} = mv + mv \cos(115^{\circ}) \). The total initial momentum in the y-direction is \( p_{y} = mv \sin(115^{\circ}) \).
05

Apply Conservation of Momentum

After the collision, let the speed of the combined mass be \( v' \). Then, total momentum in x is \((2m)v'\cos(\theta') = mv + mv \cos(115^{\circ})\), and the total momentum in y is \((2m)v'\sin(\theta') = mv \sin(115^{\circ})\).
06

Solve for the Final Speed

Square and add both momentum equations to eliminate \(\theta'\): \((2m)^2(v')^2 = (mv + mv \cos(115^{\circ}))^2 + (mv \sin(115^{\circ}))^2\). Solve for \(v'\): \( v' = \sqrt{\left(v^2 + 2v^2 \cos(115^{\circ}) + v^2 \cos^2(115^{\circ}) + v^2 \sin^2(115^{\circ})\right) / 4} \).
07

Compute Numerical Result

Substitute the known values \( m = 72\,kg \), \( v = 5.45\,m/s \) and calculate using trigonometric values, \( \cos(115^{\circ}) \approx -0.4226 \) and \( \sin(115^{\circ}) \approx 0.9063 \). Perform the arithmetic to find \( v' \approx 2.81\,m/s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In an inelastic collision, such as when two hockey players stick together after colliding, the conservation of momentum plays a crucial role.
The law states that the total momentum of a closed system remains constant if no external forces are acting on it.
Here’s what that means in simple terms:
  • Before the collision, each player has their own momentum, which is a product of mass and velocity.
  • After they collide and stick together, their total momentum is the sum of their initial individual momentums.
Because the collision is inelastic, they move together as one mass after they collide. To find the final speed, we equate the total momentum before the collision to the total momentum after. This conservation helps us determine how fast they move collectively after colliding.
Trigonometry in Physics
Trigonometry is a valuable mathematical tool to break down vector quantities, like momentum, into components.
Understanding momentum in two dimensions requires insight into how angles affect direction and magnitude.In our problem, the players hit each other at a 115-degree angle, so we use trigonometry to split their velocities into x (horizontal) and y (vertical) components.
  • Player 1, moving purely horizontally, has an x-component of momentum.
  • Player 2 moves at an angle, contributing both x and y components to their momentum.
Using trigonometric functions: - The cosine of the angle gives us the x-component: \( p_{x2} = mv \cos(115^{\circ}) \).- The sine gives the y-component: \( p_{y2} = mv \sin(115^{\circ}) \).These help visualize how each player’s movement contributes to the total momentum in the x and y directions, which is essential for calculating their speed post-collision.
Momentum Components
Momentum components are essential for analyzing motion in multiple directions, especially in collisions.
They allow us to separate and understand how movement is distributed through different paths.In the scenario of our hockey players:
  • The x-component represents movement along a straight horizontal path.
  • The y-component deals with vertical or perpendicular movement driven by any angular force.
To solve the problem, we start by calculating the individual player's x and y momentum components: For player 1, all momentum is in the x-direction, while player 2, because of the angle, has portions in both x and y.This is expressed mathematically as:- Total initial x-momentum: \( mv + mv \cos(115^{\circ}) \).- Total initial y-momentum: \( mv \sin(115^{\circ}) \).By summing and balancing these components following the collision, which aligns with the conservation laws, we can find the final speed of the combined mass.

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