/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 A \(1.80-\mathrm{kg}\) block sli... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(1.80-\mathrm{kg}\) block slides on a rough horizontal surface. The block hits a spring with a speed of \(2.00 \mathrm{m} / \mathrm{s}\) and compresses it a distance of \(11.0 \mathrm{cm}\) before coming to rest. If the coefficient of kinetic friction between the block and the surface is \(\mu_{\mathrm{k}}=0.560\) what is the force constant of the spring?

Short Answer

Expert verified
The force constant of the spring is approximately 397 N/m.

Step by step solution

01

Write down known variables

Begin by identifying and listing all the given parameters of the problem:- Mass of the block, \( m = 1.80 \, \text{kg} \)- Initial speed of the block, \( v_i = 2.00 \, \text{m/s} \)- Compression of the spring, \( x = 11.0 \, \text{cm} = 0.11 \, \text{m} \)- Coefficient of kinetic friction, \( \mu_k = 0.560 \)We need to find the spring constant \( k \).
02

Calculate the force of kinetic friction

The force of kinetic friction \( f_k \) can be calculated using the formula:\[ f_k = \mu_k \times m \times g \]Substitute in the values:\[ f_k = 0.560 \times 1.80 \, \text{kg} \times 9.81 \, \text{m/s}^2 \]
03

Calculate the work done by friction

The work done by friction \( W_f \) is calculated using:\[ W_f = f_k \times x \]where \( f_k \) is the force of friction found in Step 2 and \( x \) is the compression of the spring.
04

Write the energy conservation equation

Using the work-energy principle, the initial kinetic energy is equal to the work done by friction plus the elastic potential energy stored in the spring:\[ \frac{1}{2} m v_i^2 = W_f + \frac{1}{2} k x^2\] We will solve this for the spring constant \( k \).
05

Solve for the spring constant \( k \)

Rearrange the energy conservation equation to solve for \( k \):\[ \frac{1}{2} k x^2 = \frac{1}{2} m v_i^2 - W_f \] Substitute the expression for \( W_f \) into the equation and rearrange:\[ k = \frac{m v_i^2 - 2 W_f}{x^2}\]Insert the known values and solve for \( k \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is a type of friction that occurs when two objects are moving relative to each other. It acts opposite to the direction of movement and is responsible for converting kinetic energy into other forms, like heat.
This frictional force plays a crucial role in many physics problems, especially those involving motion and energy.In our exercise, the block is sliding on a rough surface which introduces kinetic friction. The coefficient of kinetic friction, denoted by \( \mu_k \), is a measure of how "sticky" or "rough" the surfaces are against each other. A higher \( \mu_k \) means more friction.
The force of kinetic friction \( f_k \) can be calculated using the formula:
  • \( f_k = \mu_k \times m \times g \)
where \( m \) is the mass of the block and \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
The kinetic friction opposes the motion of the block, reducing its speed and contributing to the work done by friction.
Spring Constant
The spring constant, denoted as \( k \), describes how stiff or flexible a spring is. It is a characteristic property of the spring that quantifies the force needed to compress or extend the spring by a certain distance.
In our exercise, the spring opposes the movement of the block. When the block compresses the spring, it stores potential energy in the spring. The spring constant \( k \) can be found using the equation:
  • \( k = \frac{m v_i^2 - 2 W_f}{x^2} \)
where \( x \) is the compression distance.
To find \( k \), it's essential to first determine the work done by friction \( W_f \) as this work will change the total energy of the block-spring system.
A larger spring constant means the spring is harder to compress, requiring more force for the same amount of compression.
Work-Energy Principle
The work-energy principle states that the work done by all forces acting on an object will result in a change in the object's kinetic energy.
This principle provides a way to understand and solve problems involving motion and energy transformations. In this exercise, it is applied to relate the initial kinetic energy of the block to work done by friction and the energy stored in the spring.When the block compresses the spring and comes to rest, its initial kinetic energy has been converted into work done against friction plus the elastic potential energy stored in the spring.
The expression used for this transformation is:
  • \( \frac{1}{2} m v_i^2 = W_f + \frac{1}{2} k x^2 \)
Solving this equation enables us to find the spring constant, connecting kinetic friction, energy conservation, and the properties of the spring.
This principle highlights how energy changes form but is conserved within a closed system.

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Most popular questions from this chapter

Running Shoes The soles of a popular make of running shoe have a force constant of \(2.0 \times 10^{5} \mathrm{N} / \mathrm{m} .\) Treat the soles as ideal springs for the following questions. (a) If a \(62-\mathrm{kg}\) person stands in a pair of these shoes, with her weight distributed equally on both feet, how much does she compress the soles? (b) How much energy is stored in the soles of her shoes when she's standing?

In a tennis match, a player wins a point by hitting the ball sharply to the ground on the opponent's side of the net. (a) If the ball bounces upward from the ground with a speed of \(16 \mathrm{m} / \mathrm{s}\) and is caught by a fan in the stands with a speed of \(12 \mathrm{m} / \mathrm{s}\), how high above the court is the fan? Ignore air resistance. (b) Explain why it is not necessary to know the mass of the tennis ball.

A person is to be released from rest on a swing pulled away from the vertical by an angle of \(20.0^{\circ} .\) The two frayed ropes of the swing are \(2.75 \mathrm{m}\) long, and will break if the tension in either of them exceeds \(355 \mathrm{N}\). (a) What is the maximum weight the person can have and not break the ropes? (b) If the person is released at an angle greater than \(20.0^{\circ}\), does the maximum weight increase, decrease, or stay the same? Explain.

A 2.9-kg block slides with a speed of 1.6 \(\mathrm{m} / \mathrm{s}\) on a frictionless horizontal surface until it encounters a spring. (a) If the block compresses the spring \(4.8 \mathrm{cm}\) before coming to rest, what is the force constant of the spring? (b) What initial speed should the block have to compress the spring by \(1.2 \mathrm{cm} ?\)

Predict/Explain When a ball of mass \(m\) is dropped from rest from a height \(h,\) its kinetic energy just before landing is \(K\). Now, suppose a second ball of mass \(4 m\) is dropped from rest from a height \(h / 4 .\) (a) Just before ball 2 lands, is its kinetic energy \(4 K, 2 K, K, K / 2,\) or \(K / 4 ?\) (b) Choose the best explanation from among the following: I. The two balls have the same initial energy. II. The more massive ball will have the greater kinetic energy. III. The reduced drop height results in a reduced kinetic energy.

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