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An \(81.0-k g\) in-line skater does +3420 J of nonconservative work by pushing against the ground with his skates. In addition, friction does -715 J of nonconservative work on the skater. The skater's initial and final speeds are \(2.50 \mathrm{m} / \mathrm{s}\) and \(1.22 \mathrm{m} / \mathrm{s},\) respectively. (a) Has the skater gone uphill, downhill, or remained at the same level? Explain. (b) Calculate the change in height of the skater.

Short Answer

Expert verified
(a) The skater went uphill. (b) The change in height is approximately 3.66 meters.

Step by step solution

01

Identify the Known Quantities

We start by listing the given quantities:- Mass of the skater, \(m = 81.0\, \text{kg}\).- Nonconservative work done by the skater, \(W_\text{nc, skater} = +3420\, \text{J}\).- Nonconservative work done by friction, \(W_\text{nc, friction} = -715\, \text{J}\).- Initial speed, \(v_i = 2.50\, \text{m/s}\).- Final speed, \(v_f = 1.22\, \text{m/s}\).
02

Apply the Work-Energy Principle

The work-energy principle states:\[W_\text{nc} = \Delta KE + \Delta PE,\]where \(\Delta KE\) is the change in kinetic energy and \(\Delta PE\) is the change in potential energy.
03

Calculate the Change in Kinetic Energy

The change in kinetic energy (\(\Delta KE\)) is given by:\[\Delta KE = \frac{1}{2}m(v_f^2 - v_i^2).\]Substituting the values:\[\Delta KE = \frac{1}{2}(81.0)((1.22)^2 - (2.50)^2) = \frac{1}{2}(81.0)(1.4884 - 6.25).\]Simplifying gives:\[\Delta KE = (40.5)(-4.7616) = -192.8\, \text{J}.\]
04

Calculate Total Nonconservative Work Done

The total nonconservative work (\(W_\text{nc, total}\)) is the sum of work done by the skater and by friction:\[W_\text{nc, total} = W_\text{nc, skater} + W_\text{nc, friction} = 3420 + (-715) = 2705\, \text{J}.\]
05

Solve for the Change in Potential Energy

Using the equation from Step 2:\[2705 = -192.8 + \Delta PE.\]Solve for \(\Delta PE\):\[\Delta PE = 2705 + 192.8 = 2897.8\, \text{J}.\]
06

Determine if the Skater Went Uphill or Downhill

Since \(\Delta PE\) is positive (2897.8 J), the skater's height increased, indicating he went uphill.
07

Calculate Change in Height

The change in potential energy \(\Delta PE\) is also given by:\[\Delta PE = mgh,\]where \(h\) is the change in height and \(g = 9.81\, \text{m/s}^2\). Solve for \(h\):\[2897.8 = 81.0 \times 9.81 \times h \h = \frac{2897.8}{81.0 \times 9.81} \approx 3.66\, \text{m}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonconservative Work
In physics, work done by nonconservative forces involves energy transfer that is not recoverable as mechanical energy. Such forces include friction, air resistance, and applied forces like pushes or pulls. In this exercise, the skater does +3420 J of work against the ground. This positive work indicates energy input by the skater pushing himself forward. Meanwhile, friction, a nonconservative force, counters this movement by doing -715 J of work against him. These energies cause changes in both kinetic and potential energies of the system.
The work-energy principle equation, \( W_{\text{nc}} = \Delta KE + \Delta PE \), shows how nonconservative work contributes to energy changes in a system. It demonstrates that the sum of nonconservative work influences both kinetic (motion-related) and potential (position-related) energy. In this scenario, the skater’s efforts and friction's resistance affect his total energy balance.
Kinetic Energy
Kinetic energy is the energy associated with the motion of an object. It is expressed mathematically as \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity. Changes in kinetic energy are directly tied to changes in the object's speed.
In the given exercise, the skater’s initial speed is \( 2.50 \, \text{m/s} \) and his final speed is \( 1.22 \, \text{m/s} \). Calculating the change in kinetic energy using:
  • \( \Delta KE = \frac{1}{2}m(v_f^2 - v_i^2) \)
This formula accounts for the reduction in speed, resulting in a drop in kinetic energy. The skater loses 192.8 J of kinetic energy, reflecting the energy consumed in overcoming friction and the gravitational potential to move uphill.
Potential Energy
Potential energy is energy stored by an object's position, typically concerning height in gravitational fields. It is calculated with \( PE = mgh \), where \( m \) is mass, \( g \) is the gravitational constant \( 9.81 \, \text{m/s}^2 \), and \( h \) is height change.
The positive change in potential energy, 2897.8 J in this exercise, suggests the skater moved to a higher elevation. This is because potential energy increases as an object ascends. Using the formula for potential energy change, \( \Delta PE = mgh \), we solve for the change in height \( h \) to find the skater ascends approximately 3.66 meters. This uphill movement ties into the work-energy principle, showing how energy input by the skater raises his potential energy as he climbs against gravity.

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