/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 The driver of a \(1300-\mathrm{k... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The driver of a \(1300-\mathrm{kg}\) car moving at \(17 \mathrm{m} / \mathrm{s}\) brakes quickly to \(11 \mathrm{m} / \mathrm{s}\) when he spots a local garage sale. (a) Find the change in the car's kinetic energy. (b) Explain where the "missing" kinetic energy has gone.

Short Answer

Expert verified
(a) The change in kinetic energy is \(-109,200 \\ ext{J} \). (b) It is mostly transformed into heat energy due to braking friction.

Step by step solution

01

Understand Kinetic Energy

Kinetic energy (\( KE \)) is given by the formula: \[ \text{KE} = \frac{1}{2}mv^2 \]where \( m \)is the mass of the object and\( v \)is its velocity. We want to find the initial and the final kinetic energies of the car to determine the change.
02

Calculate Initial Kinetic Energy

The initial velocity of the car is \( 17 \ ext{m/s} \)and the mass is \( 1300 \ ext{kg} \).The initial kinetic energy is calculated as: \[ KE_{initial} = \frac{1}{2} \times 1300 \times 17^2 \] Solving this gives: \[ KE_{initial} = 187,850 \ ext{J} \] (Joules).
03

Calculate Final Kinetic Energy

The final velocity is \( 11 \ ext{m/s} \).The final kinetic energy is: \[ KE_{final} = \frac{1}{2} \times 1300 \times 11^2 \] Solving this yields: \[ KE_{final} = 78,650 \ ext{J} \].
04

Determine Change in Kinetic Energy

The change in kinetic energy (\( \Delta KE \)) is given by the difference between initial and final kinetic energies: \[ \Delta KE = KE_{final} - KE_{initial} \] Substituting the known values: \[ \Delta KE = 78,650 - 187,850 = -109,200 \ ext{J} \] The negative sign indicates a loss of kinetic energy.
05

Explain the Energy Transformation

The missing kinetic energy has been transformed into other forms of energy due to braking. Most of it becomes thermal energy due to friction between the brake pads and the wheels and some may cause slight sound and deformation of materials (heat and sound energy losses).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Transformation
When a vehicle rapidly slows down, such as the car in this exercise, energy transformation is the process taking place. The law of conservation of energy states that energy cannot be created or destroyed but only transformed from one form to another.
In the context of the car braking, the kinetic energy decreases due to the reduction in velocity. This lost kinetic energy doesn't just disappear; it changes into other forms. Let's explore these transformations:
  • **Thermal energy**: When brakes are applied, friction occurs between the brake pads and wheels, converting a substantial portion of the car’s kinetic energy into heat. The increase in temperature is how we can tell thermal energy is being generated.
  • **Sound energy**: As the car slows down, you might hear screeching. This sound is another transformation of the kinetic energy, albeit a much smaller portion than thermal energy.
  • **Deformation**: There could be minor deformations in the brake components or tires as they work to stop the car, converting energy into slight physical changes.
Understanding these transformations helps us appreciate how energy flows and changes forms in everyday scenarios.
Thermal Energy
Thermal energy, often referred to as heat energy, becomes more significant during physical changes involving friction, like braking. It is a form of energy generated and released when objects resist motion across each other.
In the scenario of the car braking, the kinetic energy of the car is partially converted to thermal energy due to friction between the brake pads and wheels. This frictional force generates heat, which dissipates into the surroundings, primarily through the brake system and wheels.
Thermal energy can increase noticeably - it is why brakes get hot after repeated use. It also demonstrates energy efficiency in mechanical systems. A significant portion of the lost kinetic energy in this problem is transformed into thermal energy, which emphasizes how vehicles depend on friction for effective stopping power.
Physics Problem Solving
Solving physics problems like the one presented involves systematically breaking down concepts into understandable steps. Here’s how you approach such a problem:

To solve for the kinetic energy reduction in the car:
  • **Identify the Known Values:** List out the mass and initial and final velocities as provided.
  • **Apply the Formula:** Use the kinetic energy formula \(KE = \frac{1}{2}mv^2\) to find initial and final energies.
  • **Calculate Energy Change:** Subtract the final kinetic energy from the initial to find the change: \(\Delta KE = KE_{final} - KE_{initial}.\)
This approach not only finds numerical solutions but deepens understanding of the underlying physics. Visualization and a stepwise breakdown simplify complex transformations, making it easier to communicate results and implications. Practice with a variety of physics problems improves skills in methodically tackling questions, ensuring clearer and more accurate problem-solving.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Predict/Explain On reentry, the space shuttle's protective heat tiles become extremely hot. (a) Is the mechanical energy of the shuttle-Earth system when the shuttle lands greater than, less than, or the same as when it is in orbit? (b) Choose the best explanation from among the following: I. Dropping out of orbit increases the mechanical energy of the shuttle. II. Gravity is a conservative force. III. A portion of the mechanical energy has been converted to heat energy.

A \(1250-\mathrm{kg}\) car drives up a hill that is \(16.2 \mathrm{m}\) high. During the drive, two non conservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car's engine. The work done by friction is \(-3.11 \times 10^{5} \mathrm{J} ;\) the work done by the engine is \(+6.44 \times 10^{5}\) J. Find the change in the car's kinetic energy from the bottom of the hill to the top of the hill.

A person is to be released from rest on a swing pulled away from the vertical by an angle of \(20.0^{\circ} .\) The two frayed ropes of the swing are \(2.75 \mathrm{m}\) long, and will break if the tension in either of them exceeds \(355 \mathrm{N}\). (a) What is the maximum weight the person can have and not break the ropes? (b) If the person is released at an angle greater than \(20.0^{\circ}\), does the maximum weight increase, decrease, or stay the same? Explain.

\(A\) 15,800-kg truck is moving at \(12.0 \mathrm{m} / \mathrm{s}\) when it starts down a \(6.00^{\circ}\) incline in the Canadian Rockies. At the start of the descent the driver notices that the altitude is \(1630 \mathrm{m}\). When she reaches an altitude of \(1440 \mathrm{m},\) her speed is \(29.0 \mathrm{m} / \mathrm{s}\). Find the change in (a) the gravitational potential energy of the system and (b) the truck's kinetic energy. (c) Is the total mechanical energy of the system conserved? Explain.

BIO A Flea's Jump The resilin in the upper leg (coxa) of a flea has a force constant of about \(26 \mathrm{N} / \mathrm{m}\), and when the flea cocks its jumping legs, the resilin in each leg is stretched by approximately \(0.10 \mathrm{mm}\). Given that the flea has a mass of \(0.50 \mathrm{mg}\) and that two legs are used in a jump, estimate the maximum height a flea can attain by using the energy stored in the resilin. (Assume the resilin to be an ideal spring.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.