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Early one October, you go to a pumpkin patch to select your Halloween pumpkin. You lift the 3.2 -kg pumpkin to a height of \(1.2 \mathrm{m},\) then carry it \(50.0 \mathrm{m}\) (on level ground) to the check-out stand. (a) Calculate the work you do on the pumpkin as you lift it from the ground. (b) How much work do you do on the pumpkin as you carry it from the field?

Short Answer

Expert verified
(a) 37.632 J, (b) 0 J

Step by step solution

01

Understanding the Problem

The problem requires calculating the work done on a pumpkin when it's lifted vertically and carried horizontally. We will apply the work-energy principle, which states that work done is equal to the force applied times the displacement in the direction of the force.
02

Calculate the Force During Lifting

When lifting the pumpkin, the force applied is equal to the weight of the pumpkin. Weight \( W \) is calculated using \( W = mg \), where \( m = 3.2 \text{ kg} \) is the mass and \( g = 9.8 \text{ m/s}^2 \) is the acceleration due to gravity. Thus, \( W = 3.2 \times 9.8 = 31.36 \text{ N} \).
03

Calculate the Work Done Lifting the Pumpkin

Work done \( W \) is the product of the force and the vertical displacement. It is calculated using \( W = Fd \). Here, \( F = 31.36 \text{ N} \) and \( d = 1.2 \text{ m} \). So, \( W = 31.36 \times 1.2 = 37.632 \text{ J} \).
04

Calculate the Work Done Carrying the Pumpkin Horizontally

While carrying the pumpkin horizontally, the force of gravity acts vertically and the displacement is horizontal. Thus, there is no work done in the horizontal movement since the force and displacement are perpendicular. The work done is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravity
Gravity is the force that attracts two bodies towards each other, and on Earth, it gives weight to objects and causes them to fall if dropped. The gravitational force on Earth is approximately 9.8 m/s², which is the acceleration due to gravity that all objects experience. When you lift an object vertically, gravity acts as an opposing force. To lift an object at rest, like the pumpkin in our exercise, you need to apply a force equal to its weight.

The Weight of an Object
- Weight is calculated by multiplying the mass ( ) of an object by the acceleration due to gravity (g). - Hence, for the pumpkin weighing 3.2 kg, the calculation becomes: - Weight ( W ) = 3.2 kg × 9.8 m/s² = 31.36 N.

In this exercise, understanding gravity helps in determining the amount of force needed to lift the pumpkin. When you pick it up, you're working against this gravitational force.
Force
Force is a vector quantity, meaning it has both magnitude and direction. It is essentially any interaction that, when unopposed, will change the motion of an object. In our context with the pumpkin, forces play a pivotal role in calculating work.

Vertical and Horizontal Forces
- A vertical force is exerted when lifting the pumpkin. This force equals the weight of the pumpkin, given as 31.36 N.
- When carrying the pumpkin on level ground, although you apply horizontal force to move it, the force of gravity does not contribute to work because it's perpendicular to the displacement.

Work Done by Forces
- The work done (W) when lifting is calculated by the equation: \( W = F \cdot d \) where F is the force applied and d is the displacement in the direction of the force.- Therefore, to calculate the work done in lifting the pumpkin, you multiply the force needed to overcome gravity by the height lifted: \( W = 31.36 \times 1.2 = 37.632 \, \text{J} \).

Force and direction must align to compute work; otherwise, the work done, as seen when simply carrying the pumpkin on flat ground, is zero.
Displacement
Displacement refers to the change in position of an object. In the context of work and energy, it is crucial because work is only done when a force causes a displacement.

Implications of Displacement
- Displacement is the straight-line distance between the starting and ending points, not the path traveled.
- If the direction of the displacement is the same as the direction of the force applied, work is done.

Vertical vs. Horizontal Displacement
- When the pumpkin is lifted, the displacement is vertical, aligning with the force of the lift, which results in work done equalling 37.632 J.
- In contrast, when carrying the pumpkin horizontally, the displacement and gravitational force are perpendicular. Therefore, as the force of gravity does not contribute to horizontal displacement, no work is performed (0 J) in this setup.

Understanding displacement is essential in evaluating whether or not work is done in an activity, such as lifting or carrying objects across different planes.

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Most popular questions from this chapter

IP To clean a floor, a janitor pushes on a mop handle with a force of \(50.0 \mathrm{N}\). (a) If the mop handle is at an angle of \(55^{\circ}\) above the horizontal, how much work is required to push the mop \(0.50 \mathrm{m} ?\) (b) If the angle the mop handle makes with the horizontal is increased to \(65^{\circ},\) does the work done by the janitor increase, decrease, or stay the same? Explain.

IP A 0.14-kg pinecone falls 16 m to the ground, where it lands with a speed of \(13 \mathrm{m} / \mathrm{s}\). (a) With what speed would the pinecone have landed if there had been no air resistance? (b) Did air resistance do positive work, negative work, or zero work on the pinecone? Explain.

At \(t=1.0 \mathrm{s},\) a \(0.40-\mathrm{kg}\) object is falling with a speed of \(6.0 \mathrm{m} / \mathrm{s}\) At \(t=2.0 \mathrm{s},\) it has a kinetic energy of \(25 \mathrm{J} .\) (a) What is the kinetic energy of the object at \(t=1.0 \mathrm{s} ?\) (b) What is the speed of the object at \(t=2.0 \mathrm{s} ?\) (c) How much work was done on the object between \(t=1.0 \mathrm{s}\) and \(t=2.0 \mathrm{s} ?\)

BI 0 Muscle Cells Biological muscle cells can be thought of as nanomotors that use the chemical energy of ATP to produce mechanical work. Measurements show that the active proteins within a muscle cell (such as myosin and actin) can produce a force of about \(7.5 \mathrm{pN}\) and displacements of \(8.0 \mathrm{nm} .\) How much work is done by such proteins?

IP A pitcher accelerates a 0.14-kg hardball from rest to \(42.5 \mathrm{m} / \mathrm{s}\) in \(0.060 \mathrm{s}\). (a) How much work does the pitcher do on the ball? (b) What is the pitcher's power output during the pitch? (c) Suppose the ball reaches \(42.5 \mathrm{m} / \mathrm{s}\) in less than \(0.060 \mathrm{s}\). Is the power produced by the pitcher in this case more than, less than, or the same as the power found in part (b)? Explain.

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