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Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full and weighs \(120 \mathrm{N}\); the other bucket is only partly filled and weighs \(63 \mathrm{N}\). (a) Initially, you hold onto the lighter bucket to keep it from moving. What is the tension in the rope? (b) You release the lighter bucket and the heavier one descends. What is the tension in the rope now? (c) Eventually the heavier bucket lands and the two buckets come to rest. What is the tension in the rope now?

Short Answer

Expert verified
(a) 63 N; (b) 89.5 N; (c) 0 N.

Step by step solution

01

Analyze the Situation

We have two buckets of different weights connected by a rope over an ideal pulley. One bucket weighs \(120 \mathrm{N}\) and the other weighs \(63 \mathrm{N}\). The system is initially in equilibrium because you are holding onto the lighter bucket. In questions like this, initially, the tension in the rope is equal to the weight of the lighter bucket because the system is in static equilibrium.
02

Solve for Part (a) - Static Equilibrium

Initially, when the lighter bucket is held still, the tension in the rope, \(T\), must balance the weight of the lighter bucket. So, \(T = 63 \mathrm{N}\). This is because the system is not moving, hence the tension matches the weight of the smaller force.
03

Solve for Part (b) - Dynamic Situation

Upon releasing the lighter bucket, the system starts moving under the influence of gravity due to the imbalance in weight. Use Newton's second law to set up the equation for each bucket. For the heavier bucket, \(120 \mathrm{N} - T = 12.24 \, m/s^2 \times M_H\), and for the lighter bucket, \(T - 63 \mathrm{N} = 12.24 \, m/s^2 \times M_L\). Simplifying these equations and solving them gives: \[ T = \frac{(2 \times 120 \mathrm{N} \times 63 \mathrm{N})}{120 \mathrm{N} + 63 \mathrm{N}} = 89.5 \mathrm{N} \]
04

Solve for Part (c) - Final Equilibrium

Once the heavier bucket lands, the forces change and both buckets come to a rest, so the tension in the rope drops to zero. This is because there's no longer any net force on the system since the motion has stopped and they are not suspended causing any rope tension.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Equilibrium
In physics, static equilibrium refers to a situation where all forces acting on an object are balanced, resulting in no movement. This concept is crucial in understanding systems like pulleys at rest. Take the initial scenario in the exercise, where you hold the lighter bucket, preventing it from moving. Here, the system is in static equilibrium.

The tension in the rope must balance with the weight of the bucket you're holding. Imagine you are pulling just enough to hold the lighter bucket steady. That's how tension attempts to balance forces. Since the lighter bucket weighs 63 N, the tension equals 63 N.

While in static equilibrium, even though the heavier bucket tries to pull down with all its might, your action of holding stops both arrows of motion. This 'forces in balance' characteristic is a classic feature and a telltale sign of static equilibrium across many scenarios.
Dynamic Motion
Dynamic motion occurs when objects move due to unbalanced forces. As soon as you let go of the lighter bucket, the setup moves. The heavier bucket pulls down, setting the dynamic stage.

In this dynamic phase, the system ceases to be a simple tug of war between two forces. Now, the differing weights exert forces leading to acceleration. Using Newton's second law allows us to calculate the new tension in motion, which accounts for the weight difference. Here, we found the tension to be approximately 89.5 N.

This value is higher than the static tension due to both gravitational pull and motion playing their parts. Understanding this transformation helps us see how forces shift our equilibrium state to a dynamic one, introducing acceleration, speed, and because of that, a new tension value.
Newton's Second Law
Newton's second law of motion states that the acceleration of an object depends on two variables: the net force acting upon the object and the mass of the object. It is represented as \( F = ma \). This law is essential for solving dynamic problems.

As the buckets begin to move, this law tells us how to account for the changes in tension. Now, the acceleration due to the mass difference becomes a player in calculating force interaction.

In part (b) of the problem, the motion resumes due to the unbalanced forces, meaning the heavier bucket’s influence causes the system to move. By setting up equations using Newton's second law for each bucket, you can isolate and determine the tension in the rope during motion. Newton's law seamlessly bridges the gap from static to dynamic scenarios.

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Most popular questions from this chapter

Suppose the coefficients of static and kinetic friction between the crate and the truck bed are 0.415 and 0.382 , respectively. (a) Does the crate begin to slide at a tilt angle that is greater than, less than, or equal to \(23.2^{\circ} ?\) (b) Verify your answer to part (a) by determining the angle at which the crate begins to slide. (c) Find the length of time it takes for the crate to slide a distance of \(2.75 \mathrm{m}\) when the tilt angle has the value found in part (b).

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