/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 A driver who does not wear a sea... [FREE SOLUTION] | 91Ó°ÊÓ

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A driver who does not wear a seatbelt continues to move forward with a speed of \(18.0 \mathrm{m} / \mathrm{s}\) (due to inertia) until something solid like the steering wheel is encountered. The driver now comes to rest in a much shorter distance - perhaps only a few centimeters. Find the magnitude of the net force acting on a \(65.0-\mathrm{kg}\) driver who is decelerated from \(18.0 \mathrm{m} / \mathrm{s}\) to rest in \(5.00 \mathrm{cm} .\) A. \(3240 \mathrm{N}\) B. \(1.17 \times 10^{4} \mathrm{N}\) C. \(2.11 \times 10^{5} \mathrm{N}\) D. \(4.21 \times 10^{5} \mathrm{N}\)

Short Answer

Expert verified
The correct answer is C: \(2.11 \times 10^{5} \mathrm{N}\).

Step by step solution

01

Identify the Known Values

We need to recognize the parameters given in the problem. The initial velocity \( v_i \) is \( 18.0 \, \text{m/s} \), the final velocity \( v_f \) is \( 0 \, \text{m/s} \), the distance over which the driver comes to rest \( d \) is \( 5.00 \, \text{cm} = 0.05 \, \text{m} \), and the driver's mass \( m \) is \( 65.0 \, \text{kg} \).
02

Use Kinematic Equation to Find Acceleration

We use the kinematic equation \( v_f^2 = v_i^2 + 2a d \) to solve for acceleration \( a \). Substituting the known values gives us:\[0 = (18.0)^2 + 2a(0.05)\]Solving for \( a \), we get:\[a = \frac{-18.0^2}{2 \times 0.05}\]
03

Calculate the Acceleration

Continuing from Step 2, calculate \( a \):\[a = \frac{-324}{0.1} = -3240 \, \text{m/s}^2\]
04

Use Newton's Second Law to Find Net Force

Using Newton's Second Law \( F = ma \), where \( m \) is mass and \( a \) is acceleration. Substitute the mass (\( 65.0 \, \text{kg} \)) and acceleration (\( -3240 \, \text{m/s}^2 \)):\[F = 65.0 \times (-3240)\]
05

Calculate the Net Force

Perform the multiplication to find \( F \):\[F = -65.0 \times 3240 = -210600 \, \text{N}\]Thus, the magnitude of the net force is \( 2.11 \times 10^{5} \, \text{N} \).
06

Conclusion

By comparing the calculated net force with the provided options, we see that the magnitude \( 2.11 \times 10^{5} \, \text{N} \) corresponds to option C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations help us relate different aspects of motion, such as velocity, acceleration, and distance. These equations are incredibly useful when solving problems involving acceleration, like the deceleration experienced by a car crash victim without a seatbelt.
They provide a way to calculate unknown variables when some are already known.
For instance, in our original problem, the driver starts with a known initial velocity and comes to a stop (final velocity of zero) over a short distance. Using the kinematic equation: \( v_f^2 = v_i^2 + 2a d \), we can solve for the acceleration \( a \) by inputting the known values:
  • Initial velocity \( v_i = 18.0 \, \text{m/s} \)
  • Final velocity \( v_f = 0 \, \text{m/s} \)
  • Distance \( d = 0.05 \, \text{m} \)
By rearranging this equation to solve for \( a \), we find the acceleration that allowed the driver to decelerate to rest. Calculating \( a \) gives us a measure of how rapidly the driver stopped moving.
Deceleration
Deceleration is essentially negative acceleration – a decrease in speed over time. In the context of the problem, the driver is decelerating when the forward motion is abruptly stopped.
This happens as they collide with something solid like the steering wheel.
Understanding deceleration is crucial because it affects the force experienced by the driver. The formula \( a = \frac{-18.0^2}{2 \times 0.05} \) was used to determine deceleration. When a vehicle or person decelerates, it tends to happen over a shorter distance than the initial motion.
Such sharp deceleration can be hazardous because the force exerted during this rapid stop can cause severe injury.
The amount of deceleration influences the net force applied to the driver. Thus, knowing how to calculate this helps in designing safety features like seatbelts that can reduce the rate of deceleration and thus the force on the human body.
Inertia
Inertia is a property of matter that describes an object's resistance to changes in its state of motion.
It is why a driver not wearing a seatbelt continues to move at a constant speed until an external force acts upon them.
This concept is central to Newton's First Law, which states that an object in motion will remain in motion unless acted upon by an external force. In the scenario outlined, the driver has inertia, carrying them forward at the initial speed even though the vehicle has come to a stop.
Inertia is not a force; rather, it is a property of mass.
The greater the mass (such as a driver with a mass of 65 kg), the greater the force needed to change their motion. Hence, more force is required to stop the driver abruptly, as demonstrated when calculating the net force exerted during deceleration. Understanding inertia is crucial for comprehending why we wear seatbelts.
Seatbelts provide the external force needed to safely alter the amount of inertia keeping the driver in motion, thereby reducing the risk of injury.

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Most popular questions from this chapter

On a planet far, far away, an astronaut picks up a rock. The rock has a mass of \(5.00 \mathrm{kg}\), and on this particular planet its weight is \(40.0 \mathrm{N}\). If the astronaut exerts an upward force of \(46.2 \mathrm{N}\) on the rock, what is its acceleration?

Blo Gecko Feet Researchers have found that a gecko's foot is covered with hundreds of thousands of small hairs (setae) that allow it to walk up walls and even across ceilings. A single foot pad, which has an area of \(1.0 \mathrm{cm}^{2}\), can attach to a wall or ceiling with a force of \(11 \mathrm{N}\). (a) How many \(250-g\) geckos could be suspended from the ceiling by a single foot pad? (b) Estimate the force per square centimeter that your body exerts on the soles of your shoes, and compare with the \(11 \mathrm{N} / \mathrm{cm}^{2}\) of the sticky gecko foot.

" IP A drag racer crosses the finish line doing \(202 \mathrm{mi} / \mathrm{h}\) and promptly deploys her drag chute (the small parachute used for braking). (a) What force must the drag chute exert on the \(891-\mathrm{kg}\) ear to slow it to \(45.0 \mathrm{mi} / \mathrm{h}\) in a distance of \(185 \mathrm{m} ?\) (b) Describe the strategy you used to solve part (a).

Predict/Explain You jump out of an airplane and open your parachute after an extended period of free fall. (a) To decelerate your fall, must the force exerted on you by the parachute be greater than, less than, or equal to your weight? (b) Choose the best explanation from among the following: I. Parachutes can only exert forces that are less than the weight of the skydiver. II. The parachute exerts a force exactly equal to the skydiver's weight. III. To decelerate after free fall, the net force acting on a skydiver must be upward.

\(\cdot\) Suppose a rocket launches with an acceleration of \(30.5 \mathrm{m} / \mathrm{s}^{2}\) What is the apparent weight of an \(92-\mathrm{kg}\) astronaut aboard this rocket?

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