/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Takeoff from an Aircraft Carrier... [FREE SOLUTION] | 91Ó°ÊÓ

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Takeoff from an Aircraft Carrier On an aircraft carrier, a jet can be catapulted from 0 to \(155 \mathrm{mi} / \mathrm{h}\) in \(2.00 \mathrm{s}\), If the average force exerted by the catapult is \(9.35 \times 10^{5} \mathrm{N},\) what is the mass of the jet?

Short Answer

Expert verified
The mass of the jet is approximately 26983 kg.

Step by step solution

01

Convert Speed to Meters per Second

First, convert the jet's final speed from miles per hour to meters per second. We have \(155 \text{ mi/h}\). Use the conversion factors: \(1 \text{ mi} = 1609.34 \text{ meters}\) and \(1 \text{ hour} = 3600 \text{ seconds}\). Our conversion looks like this: \( 155 \text{ mi/h} \times \frac{1609.34 \text{ m}}{1 \text{ mi}} \times \frac{1 \text{ h}}{3600 \text{ s}} \approx 69.3 \text{ m/s} \).
02

Calculate Acceleration

The acceleration \(a\) can be found using the formula \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v = 69.3 \text{ m/s} - 0 \text{ m/s} = 69.3 \text{ m/s} \) and \( \Delta t = 2.00 \text{ s} \). Thus, \( a = \frac{69.3}{2.00} = 34.65 \text{ m/s}^2 \).
03

Use Newton's Second Law

According to Newton's second law, Force \( F = m \cdot a \), we can find the mass \( m \) of the jet. We know \( F = 9.35 \times 10^{5} \text{ N} \) and \( a = 34.65 \text{ m/s}^2 \). Rearrange the formula to solve for mass: \( m = \frac{F}{a} = \frac{9.35 \times 10^{5}}{34.65} \approx 26983 \text{ kg} \).
04

Conclusion

The calculated mass of the jet using the given force and acceleration is approximately \( 26983 \text{ kg} \). Ensure the math and unit conversions are correct to verify this solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is an essential skill in physics and engineering, particularly when dealing with different measurement systems. Often, you'll encounter values in units that need to be consistent to make calculations easier.
Let's focus on converting speed from miles per hour (mi/h) to meters per second (m/s), which is critical when working with distances in meters and time in seconds.
To do this conversion, you use specific conversion factors:
  • 1 mile = 1609.34 meters
  • 1 hour = 3600 seconds
In our exercise, the jet's speed is given as 155 mi/h. To convert this to m/s:Step 1: Multiply the speed by the number of meters in a mile:\[155 ext{ mi/h} \times \frac{1609.34 ext{ m}}{1 ext{ mi}}\]Step 2: Divide by the number of seconds in an hour:\[\frac{249418.7 ext{ m}}{3600 ext{ s}}\]This calculation simplifies to approximately 69.3 m/s. Hence, converting units properly ensures you can plug values directly into formulas without errors.
Acceleration
Acceleration is the rate of change of velocity of an object. It is a vector quantity, meaning it has both magnitude and direction.
In physics problems, acceleration tells us how fast an object is speeding up or slowing down.
To calculate acceleration when the initial velocity (\(v_i\)) and final velocity (\(v_f\)) are known, you can use:
  • \(a = \frac{\Delta v}{\Delta t}\)
Where \(\Delta v\) is the change in velocity and \(\Delta t\) is the change in time.In our scenario, the jet accelerates from 0 m/s to 69.3 m/s over 2 seconds:
  • Change in velocity (\(\Delta v\)): 69.3 m/s
  • Time interval (\(\Delta t\)): 2 seconds
  • Acceleration (\(a\)): \(\frac{69.3 \text{ m/s}}{2\text{ s}} = 34.65 \text{ m/s}^2\)
Understanding acceleration helps us comprehend how forces affect motion, such as the immediate speed-up of a jet leaving an aircraft carrier.
Mass Calculation
Determining mass in physics often involves understanding and applying Newton's laws of motion. Newton's Second Law states that Force = mass × acceleration, or \(F = m \cdot a\). This relationship is pivotal in calculating mass when force and acceleration are given.
In the example of the jet on an aircraft carrier, the force exerted by the catapult is known (\(F = 9.35 \times 10^5 \text{ N}\)), and we've calculated the acceleration (\(a = 34.65 \text{ m/s}^2\)). We aim to find the mass (\(m\)): To solve for mass, rearrange Newton's Second Law:
  • \(m = \frac{F}{a}\)
Plug in the values:\[m = \frac{9.35 \times 10^5}{34.65} \approx 26983 \text{ kg}\]This calculation shows that by knowing only the force and acceleration, you can find the mass, demonstrating the profound interconnection between these physical quantities.

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