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Give a list of all possible sets of the four quantum numbers \(\left(n, \ell, m_{\ell}, m_{\mathrm{s}}\right)\) for electrons in the \(3 \mathrm{s}\) subshell.

Short Answer

Expert verified
The sets are \((3, 0, 0, +\frac{1}{2})\) and \((3, 0, 0, -\frac{1}{2})\).

Step by step solution

01

Understanding the Subshell

The question involves the 3s subshell. In quantum mechanics, the subshell is characterized by a principal quantum number \(n\) and an azimuthal quantum number \(\ell\). For the 3s subshell, \(n\) is 3 and \(\ell\) is 0, since it's an s subshell.
02

Determine the Magnetic Quantum Number

The magnetic quantum number \(m_{\ell}\) is determined by the azimuthal quantum number \(\ell\). Since \(\ell = 0\) for the s subshell, \(m_{\ell}\) can only be 0 as it ranges from \(-\ell\) to \(\ell\). Thus, \(m_{\ell} = 0\).
03

Identify the Spin Quantum Number

The spin quantum number \(m_{\mathrm{s}}\) represents the direction of the electron's spin and can have values of either \(+\frac{1}{2}\) or \(-\frac{1}{2}\). This means for each electron there are two possible spin states.
04

List the Possible Quantum Number Sets

Considering all the determined quantum numbers: \(n = 3\), \(\ell = 0\), \(m_{\ell} = 0\), and the two possible values for \(m_{\mathrm{s}}\), the possible sets of quantum numbers for electrons in the 3s subshell are:\1. \((3, 0, 0, +\frac{1}{2})\)\2. \((3, 0, 0, -\frac{1}{2})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
In quantum mechanics, the principal quantum number, denoted as \( n \), plays a crucial role in defining the energy level and size of an atomic orbital. It represents the shell or energy level the electron occupies around an atom's nucleus. The principal quantum number can take any positive integer value such as 1, 2, 3, etc.

A higher \( n \) value indicates a higher energy level and a larger radius that the electron occupies. For example, an electron with \( n = 3 \) resides in the third energy level, which is farther from the nucleus compared to \( n = 1 \) or \( n = 2 \).

The principal quantum number sets the stage for an electron's energy and helps in categorizing the electron configuration within an atom. In the context of the 3s subshell, the principal quantum number is 3, indicating this orbital is part of the third energy level.
Azimuthal Quantum Number
The azimuthal quantum number, denoted as \( \ell \), determines the shape of the orbital. We often refer to this as the angular momentum quantum number. Its value depends on the principal quantum number \( n \), since it ranges from 0 to \( n-1 \).

Each value of \( \ell \) corresponds to a particular subshell:
  • \( \ell = 0 \) corresponds to the s subshell
  • \( \ell = 1 \) corresponds to the p subshell
  • \( \ell = 2 \) corresponds to the d subshell
  • \( \ell = 3 \), and so on corresponds to f, g, etc.
For the 3s subshell, the azimuthal quantum number is \( \ell = 0 \). This value tells us that the 3s orbital is spherically shaped.

Overall, \( \ell \) defines how many nodal planes an orbital will have, impacting the electron's angular momentum and how the electron cloud is distributed around the nucleus.
Magnetic Quantum Number
The magnetic quantum number, represented by \( m_{\ell} \), specifies the orientation of the orbital in space. The value of \( m_{\ell} \) depends directly on the azimuthal quantum number \( \ell \).

For a given \( \ell \), \( m_{\ell} \) can take on any integer value ranging from \(-\ell\) to \( \ell \). In the case of the s subshell where \( \ell = 0 \), \( m_{\ell} \) can only be 0. This singular value reflects the spherical nature of all s orbitals, as they have no specific directional orientation.

The magnetic quantum number is crucial for understanding the spatial orientation of orbitals, particularly in fields affecting the electron paths, such as magnetic fields.
Spin Quantum Number
The spin quantum number, symbolized by \( m_{\text{s}} \), describes the intrinsic angular momentum or "spin" of an electron within an orbital. Unlike the other quantum numbers, \( m_{\text{s}} \) is independent of the others and is always either \( +\frac{1}{2} \) or \( -\frac{1}{2} \).

Electron spin is a fundamental property, comparable to its charge or mass, and it represents the two possible orientations of an electron's spin within a magnetic field: "up" or "down."

The introduction of the spin quantum number allowed for a fuller understanding of electron behavior and rejected prior classical understandings, illuminating deeper atomic complexities.
3s Subshell
The term '3s subshell' specifically refers to an electron orbital within the third energy level (as indicated by \( n = 3 \)) and possessing the s shape as signified by \( \ell = 0 \). The complete set of quantum numbers for an electron in the 3s subshell is \( (3, 0, 0, m_{\text{s}}) \).

The 3s subshell can accommodate up to two electrons, distinctly identified by their spin states: \( +\frac{1}{2} \) or \( -\frac{1}{2} \). Thus, a 3s subshell holds a maximum of two electrons:
  • One with the quantum numbers \( (3, 0, 0, +\frac{1}{2}) \)
  • Another with \( (3, 0, 0, -\frac{1}{2}) \)
This specific arrangement highlights the Pauli exclusion principle, which posits that no two electrons in an atom can have the same set of all four quantum numbers. The 3s subshell's unique configuration elegantly demonstrates how quantum mechanical principles govern atomic structure.

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Most popular questions from this chapter

Suppose an electron is in the ground state of hydrogen. (a) What is the highest-energy photon this system can absorb without dissociating the electron from the proton? Explain. (b) What is the lowest-energy photon this system can absorb? Explain.

An electron in hydrogen absorbs a photon and jumps to a higher orbit. (a) Find the energy the photon must have if the initial state is \(n=3\) and the final state is \(n=5 .\) (b) If the initial state was \(n=5\) and the final state \(n=7\), would the energy of the photon be greater than, less than, or the same as that found in part (a)? Explain. (c) Calculate the photon energy for part (b).

An ionized atom has only a single electron. The \(n=6\) Bohr orbit of this electron has a radius of \(2.72 \times 10^{-10} \mathrm{m} .\) Find (a) the atomic number \(Z\) of this atom and (b) the total energy \(E\) of its \(n=3\) Bohr orbit.

What is the energy difference (in eV) between the states of an argon atom that are responsible for a photon with a wavelength of \(514.5 \mathrm{nm} ?\) A. \(2.13 \mathrm{eV}\) B. \(2.42 \mathrm{eV}\) C. \(3.87 \mathrm{eV}\) D. \(6.40 \mathrm{eV}\)

It was pointed out in Section \(31-3\) that intermolecular collisions at room temperature do not have enough energy to cause an excitation in hydrogen from the \(n=1\) state to the \(n=2\) state. Given that the average kinetic energy of a hydrogen atom in a high-temperature gas is \(\frac{3}{2} \mathrm{KT}\) (where \(k\) is Boltzmann's constant), find the minimum temperature required for atoms to have enough thermal energy to excite electrons from the ground state to the \(n=2\) state.

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