/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 An electron and a proton have th... [FREE SOLUTION] | 91Ó°ÊÓ

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An electron and a proton have the same speed. (a) Which has the longer de Broglie wavelength? Explain. (b) Calculate the ratio \(\left(\lambda_{\mathrm{e}} / \lambda_{\mathrm{p}}\right)\)

Short Answer

Expert verified
(a) The electron has a longer de Broglie wavelength. (b) Ratio: approximately 1836.

Step by step solution

01

Recall de Broglie's Wavelength Formula

De Broglie's wavelength formula is given by \( \lambda = \frac{h}{p} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant, and \( p \) is the momentum of the particle.
02

Define the Particles' Momentums

Momentum \( p \) is defined as \( p = mv \), where \( m \) is the mass and \( v \) is the velocity. Therefore, for both the electron (\( m_e \)) and the proton (\( m_p \)), if they have the same speed (\( v \)), their momentums are \( p_e = m_e \cdot v \) and \( p_p = m_p \cdot v \) respectively.
03

Substitute into the de Broglie Wavelength Formula

Given that the electron and proton have the same speed, we substitute their momenta into the de Broglie wavelength formula to get \( \lambda_e = \frac{h}{m_e \cdot v} \) and \( \lambda_p = \frac{h}{m_p \cdot v} \).
04

Calculate the Wavelength Ratio

The ratio of their de Broglie wavelengths is \( \frac{\lambda_e}{\lambda_p} = \frac{\frac{h}{m_e \cdot v}}{\frac{h}{m_p \cdot v}} = \frac{m_p}{m_e} \). Since \( m_p \approx 1836 \times m_e \), the ratio \( \frac{\lambda_e}{\lambda_p} \approx 1836 \).
05

Conclude with the Longer Wavelength

As the electron has a smaller mass than the proton, its de Broglie wavelength is longer. Hence, the electron has the longer de Broglie wavelength.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics which is defined as the product of an object's mass and velocity, expressed by the formula \( p = mv \). Here, \( p \) is the momentum, \( m \) is the mass of the particle, and \( v \) is its velocity.
  • Momentum depends directly on both mass and velocity. This means, for two objects with the same speed, the one with the larger mass will have more momentum.
  • In the context of the de Broglie wavelength, momentum plays a crucial role in determining the wavelength of a particle.
When comparing an electron and a proton moving at the same speed, we realize that the proton, which is much heavier, has a higher momentum than the electron. This mass difference is key because in the calculation of the de Broglie wavelength, the particle with the higher momentum will have a shorter wavelength when compared to the particle with less momentum.
Planck's Constant
Planck's constant is a fundamental constant in quantum mechanics, symbolized by \( h \). It has a value of approximately \( 6.626 \times 10^{-34} \) m² kg / s. This constant is crucial because it sets the scale of quantum effects, determining how the particles behave at atomic and subatomic levels.
  • Planck's constant is a key component of the de Broglie wavelength formula \( \lambda = \frac{h}{p} \), linking the wave characteristics of particles to their momentum.
  • Its relatively small value implies that quantum effects are significant only for very small particles like electrons and protons.
In the exercise, Planck's constant is used to translate the momentum of particles (electron and proton) into their de Broglie wavelength. This relationship highlights how particles exhibit both wave-like and particle-like properties, central to the concept of wave-particle duality.
Electron and Proton Comparison
When comparing an electron and a proton, especially when they share the same velocity, their differing masses lead to interesting outcomes in terms of their de Broglie wavelengths.
  • The electron is significantly lighter than the proton. The mass of a proton (\( m_p \)) is approximately 1836 times that of an electron (\( m_e \)).
  • Since both particles are moving at the same speed, the proton's momentum is much larger due to its larger mass.
This mass disparity brings about major differences in their de Broglie wavelengths. According to the formula \( \lambda = \frac{h}{p} \), a larger momentum (associated with the proton) results in a smaller wavelength. Consequently, the electron, having a much smaller momentum due to its lighter mass, exhibits a significantly longer de Broglie wavelength. This makes the concept of wave-particle duality more apparent in lighter particles like electrons. This demonstrates why, in quantum mechanics, smaller particles tend to exhibit more pronounced wave-like behaviors than larger, more massive particles.

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Most popular questions from this chapter

Light of frequency \(8.22 \times 10^{14} \mathrm{Hz}\) ejects electrons from surface A with a maximum kinetic energy that is \(2.00 \times 10^{-19} \mathrm{J}\) greater than the maximum kinetic energy of electrons ejected from surface B. (a) If the frequency of the light is increased, does the difference in maximum kinetic energy observed from the two surfaces increase, decrease, or stay the same? Explain. (b) Calculate the difference in work function for these two surfaces.

A laser produces a \(7.50-\mathrm{mW}\) beam of light, consisting of photons with a wavelength of \(632.8 \mathrm{nm}\). (a) How many photons are emitted by the laser each second? (b) The laser beam strikes a mirror at normal incidence and is reflected. What is the change in momentum of each reflected photon? Give the magnitude only, (c) What force does the laser beam exert on the mirror?

Predict/Explain A source of red light has a higher wattage than a source of green light. (a) Is the energy of photons emitted by the red source greater than, less than, or equal to the energy of photons emitted by the green source? (b) Choose the best explanation from among the following: I. The photons emitted by the red source have the greater energy because that source has the greater wattage. II. The red-source photons have less energy than the greensource photons because they have a lower frequency. The wattage of the source doesn't matter. III. Photons from the red source have a lower frequency, but that source also has a greater wattage. The two effects cancel, so the photons have equal energy.

Halogen Lightbulbs Modern halogen lightbulbs allow their filaments to operate at a higher temperature than the filaments in standard incandescent bulbs. For comparison, the filament in a standard lightbulb operates at about \(2900 \mathrm{K}\) whereas the filament in a halogen bulb may operate at \(3400 \mathrm{K}\). (a) Which bulb has the higher peak frequency? (b) Calculate the ratio of peak frequencies \(\left(f_{\text {hal }} / f_{\text {std }}\right)\). (c) The human eye is most sensitive to a frequency around \(5.5 \times 10^{14} \mathrm{Hz} .\) Which bulb produces a peak frequency closer to this value?

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