/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Light of a particular wavelength... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Light of a particular wavelength does not eject electrons from the surface of a given metal. (a) Should the wavelength of the light be increased or decreased in order to cause electrons to be ejected? (b) Choose the best explanation from among the following: I. The photons have too little energy to eject electrons. To increase their energy, their wavelength should be increased. II. The energy of a photon is proportional to its frequency; that is, inversely proportional to its wavelength. To in crease the energy of the photons so they can eject electrons, one must decrease their wavelength.

Short Answer

Expert verified
Decrease the wavelength; explanation II is correct.

Step by step solution

01

Understanding the Photoelectric Effect

The photoelectric effect describes the ejection of electrons from a material when it is exposed to light. This effect depends on the energy of the photons, which is related to the frequency of light. If the light does not have enough energy, it will not eject electrons.
02

Energy-Wavelength Relationship

The energy of photons is given by the equation \(E = h u\), where \(E\) is the energy, \(h\) is Planck’s constant, and \(u\) is the frequency of the light. The frequency and wavelength are related by \(u = \frac{c}{\lambda}\), where \(c\) is the speed of light and \(\lambda\) is the wavelength. Therefore, \(E = \frac{hc}{\lambda}\), showing that energy is inversely proportional to wavelength.
03

Determining Wavelength Changes

To increase the energy of the photons, the wavelength must be decreased. This is because energy is inversely proportional to wavelength, meaning shorter wavelengths correspond to higher energy photons.
04

Choosing the Correct Explanation

Among the given explanations, Explanation II is correct. It states that the energy of a photon is inversely proportional to its wavelength, and to increase the photon energy to eject electrons, the wavelength should be decreased.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Photon Energy
Photon energy is a key concept in understanding the photoelectric effect. When light strikes a surface, it is made up of tiny energy packets called photons. Each photon carries energy that can be calculated using the formula \( E = h u \), where \( E \) is the energy of the photon, \( h \) is Planck’s constant, and \( u \) is the frequency of the light. For an electron to be ejected from a metal surface through the photoelectric effect, a photon must possess sufficient energy to overcome the material's work function, the minimum energy required to release an electron.
  • If the photons' energy is below the work function, no electrons are ejected.
  • To increase photon energy, it's crucial to understand the role of frequency in the equation.
Increasing a photon's frequency will therefore increase its energy, enabling electron ejection if the energy surpasses the threshold.
Wavelength and Frequency
Wavelength and frequency are interconnected properties of waves, including light waves. These properties help determine the energy of photons. The relationship between wavelength and frequency is expressed through the equation \( u = \frac{c}{\lambda} \), where \( u \) represents frequency, \( c \) is the speed of light, and \( \lambda \) is wavelength.
  • Wavelength is the distance between two corresponding points of consecutive waves, such as crest to crest.
  • Frequency measures how many waves pass a point in one second (measured in hertz).
When wavelength decreases, frequency increases. Since photon energy is proportional to frequency, a decrease in wavelength results in higher energy photons. This is why decreasing the wavelength can lead to electron ejection in the photoelectric effect.
Planck’s Constant
Planck’s constant is a fundamental quantity in quantum mechanics, symbolized as \( h \). It is crucial for calculating photon energy and is a constant that appears in various equations related to quantum phenomena. Its value is approximately \( 6.626 \times 10^{-34} \text{Js} \).Planck's constant bridges the gap between energy and frequency in the formula \( E = h u \). This constant allows us to calculate the exact amount of energy carried by a photon based on its frequency.
  • Higher frequency light, like ultraviolet, has higher energy photons, measurable using Planck’s constant.
  • Lower frequency light, such as infrared, contains photons with lesser energy.
In photoelectric applications, adjusting wavelength and frequency alongside understanding Planck's constant helps identify how much energy photons will impart when they interact with materials.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exciting an Oxygen Molecule An oxygen molecule \(\left(\mathrm{O}_{2}\right)\) vibrates with an energy identical to that of a single particle of mass \(m=1.340 \times 10^{-26} \mathrm{kg}\) attached to a spring with a force constant of \(k=1215 \mathrm{N} / \mathrm{m} .\) The energy levels of the system are uniformly spaced, as indicated in Figure \(30-20\), with a separation given by ly . (a) What is the vibration frequency of this molecule? (b) How much energy must be added to the molecule to excite it from one energy level to the next higher level?

The Surface Temperature of Betelgeuse Betelgeuse, a redgiant star in the constellation Orion, has a peak in its radiation at a frequency of \(1.82 \times 10^{14} \mathrm{Hz}\). What is the surface temperature of Betelgeuse?

By what factor does the de Broglie wavelength of a particle change if \((a)\) its momentum is doubled or \((b)\) its kinetic energy is doubled? Assume the particle is nonrelativistic.

A jar is filled with monatomic helium gas at a temperature of \(25^{\circ} \mathrm{C}\). The pressure inside the jar is one atmosphere; that is, \(101 \mathrm{kPa} .\) (a) Find the average de Broglie wavelength of the helium atoms. (b) Calculate the average separation between helium atoms in the jar. (Note: The fact that the spacing between atoms is much greater than the de Broglie wavelength means quantum effects are negligible, and the a toms can be treated as particles.)

(a) How many photons are emitted per second by a He-Ne laser that emits \(1.0 \mathrm{mW}\) of power at a wavelength \(\lambda=632.8 \mathrm{nm} ?\) (b) What is the frequency of the electromagnetic waves emitted by a He-Ne laser?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.