/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Vector \(\overrightarrow{\mathbf... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Vector \(\overrightarrow{\mathbf{A}}\) points in the negative \(x\) direction and has a magnitude of 22 units. The vector \(\overrightarrow{\mathbf{B}}\) points in the positive \(y\) direction. (a) Find the magnitude of \(\overrightarrow{\mathbf{B}}\) if \(\overline{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) has a magnitude of 37 units. (b) Sketch \(\overrightarrow{\mathbf{A}}\) and \(\overrightarrow{\mathrm{B}}\).

Short Answer

Expert verified
The magnitude of \( \overrightarrow{\mathbf{B}} \) is approximately 29.74 units.

Step by step solution

01

Set up vector components

We know that \( \overrightarrow{\mathbf{A}} \) has a magnitude of 22 units and points in the negative \( x \) direction. Therefore, \( \overrightarrow{\mathbf{A}} = -22\hat{i} \). Also, let the magnitude of \( \overrightarrow{\mathbf{B}} \) be \( B \). Since \( \overrightarrow{\mathbf{B}} \) points in the positive \( y \) direction, \( \overrightarrow{\mathbf{B}} = B\hat{j} \).
02

Express resultant vector

The resultant vector \( \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} \) is given by:\[ \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} = -22\hat{i} + B\hat{j} \]
03

Apply magnitude formula

The magnitude of any vector \( \vec{C} = a \hat{i} + b \hat{j} \) is given by \( |\vec{C}| = \sqrt{a^2 + b^2} \). For \( \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} \), the magnitude is 37 units. Thus:\[ \sqrt{(-22)^2 + B^2} = 37 \]
04

Solve for B

Square both sides of the equation from Step 3:\[ (-22)^2 + B^2 = 37^2 \]\[ 484 + B^2 = 1369 \]Subtract 484 from both sides:\[ B^2 = 1369 - 484 \]\[ B^2 = 885 \]Take the square root of both sides:\[ B = \sqrt{885} \approx 29.74 \]
05

Sketch the vectors

To sketch \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \), draw \( \overrightarrow{\mathbf{A}} \) as an arrow pointing left (negative \( x \) direction) with a length representing 22 units. Then, draw \( \overrightarrow{\mathbf{B}} \) as an arrow pointing upwards (positive \( y \) direction) with a length representing approximately 29.74 units. The resultant vector should be diagonal, pointing towards the top-left corner.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
When we talk about vector components, we're essentially breaking down a vector into parts that align with our coordinate axes, such as the x-axis and y-axis. Imagine you have a box on a hill. Instead of thinking of the box just sitting there, imagine the forces acting on the box as separate parts: one part pushing sideways and another pushing down the hill. This is similar to vector components.

In this exercise, vector \( \overrightarrow{\mathbf{A}} \) is aligned in the negative x-direction and expressed as \( -22\hat{i} \). While \( \overrightarrow{\mathbf{B}} \) points in the positive y-direction, represented as \( B\hat{j} \). Here, \( \hat{i} \) and \( \hat{j} \) are unit vectors that point in the directions of the x and y axes, respectively.

By expressing vectors in terms of their components, we can easily perform mathematical operations such as vector addition or subtraction, and find the overall effect of multiple vectors acting together.
Magnitude of a Vector
The magnitude of a vector resembles the idea of the length of a line segment. It is a scalar quantity that represents the size or extent of the vector, regardless of its direction. This measure follows the principles of geometry where each straight line segment has a length.

To find the magnitude of a vector, we use the Pythagorean theorem. For a vector represented as \( \vec{C} = a \hat{i} + b \hat{j} \), its magnitude \( |\vec{C}| \) is given by \( \sqrt{a^2 + b^2} \). In our context, for the resultant vector \( \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} \), the problem tells us that it has a magnitude of 37 units.

Solving for unknowns using the magnitude involves setting up equations that relate the vector's components through this formula, allowing us to find unknown quantities like the length of \( \overrightarrow{\mathbf{B}} \).
Resultant Vector
The resultant vector is akin to the final destination when multiple vectors are combined. Imagine pushing a toy car; you push it one way, and then another friend pushes it in a different direction. The resultant vector is where the car ends up based on all the pushes.

For two vectors \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \), their sum is a new vector that captures the effect of both. Mathematically, it combines both vector components: \( \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} = -22\hat{i} + B\hat{j} \).

The magnitude of the resultant vector in our exercise was given as 37 units. This helped us solve for \( B \, \), the unknown magnitude of vector \( \overrightarrow{\mathbf{B}} \), by applying the magnitude formula. This concept highlights how vectors can be manipulated and understood through their components and respective magnitudes simply and effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are driving up a long, inclined road. After 1.2 miles you notice that signs along the roadside indicate that your elevation has increased by \(530 \mathrm{ft}\) (a) What is the angle of the road above the horizontal? (b) How far do you have to drive to gain an additional 150 ft of elevation?

A football is thrown horizontally with an initial velocity of \((16.6 \mathrm{m} / \mathrm{s}) \hat{\mathrm{x}} .\) Ignoring air resistance, the average acceleration of the football over any period of time is \(\left(-9.81 \mathrm{m} / \mathrm{s}^{2}\right) \hat{y}\) (a) Find the velocity vector of the ball \(1.75 \mathrm{s}\) after it is thrown. (b) Find the magnitude and direction of the velocity at this time.

Vector A points in the negative \(y\) direction and has a magnitude of 5 units. Vector \(\overrightarrow{\mathrm{B}}\) has twice the magnitude and points in the positive \(\underline{x}\) direction. Find the direction and magnitude of (a) \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}\) (b) \(\overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}},\) and (c) \(\overrightarrow{\mathrm{B}}-\overrightarrow{\mathbf{A}}\)

Suppose we orient the \(x\) axis of a two-dimensional coordinate system along the beach at Waikiki. Waves approaching the beach have a velocity relative to the shore given by \(\mathbf{v}_{w s}=(1.3 \mathrm{m} / \mathrm{s}) \hat{\mathbf{y}} .\) Surfers move more rapidly than the waves, but at an angle to the beach. The angle is chosen so that the surfers approach the shore with the same speed as the waves. (a) If a surfer has a speed of \(7.2 \mathrm{m} / \mathrm{s}\) relative to the water, what is her direction of motion relative to the positive \(x\) axis? (b) What is the surfer's velocity relative to the wave? \((c)\) If the surfer's speed is increased, will the angle in part (a) increase or decrease? Explain.

It is given that \(\overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}}=(-51.4 \mathrm{m}) \hat{\mathrm{x}}, \overrightarrow{\mathrm{C}}=(62.2 \mathrm{m}) \hat{\mathrm{x}},\) and \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}}=(13.8 \mathrm{m}) \hat{\mathrm{x}} .\) Find the vectors \(\overrightarrow{\mathbf{A}}\) and \(\overline{\mathbf{B}}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.