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IP Consider a "relativistic air track" on which two identical air carts undergo a completely inelastic collision. One cart is initially at rest; the other has an initial speed of \(0.650 \mathrm{c}\). (a) In classical physics, the speed of the carts after the collision would be \(0.325 c .\) Do you expect the final speed in this relativistic collision to be greater than or less than \(0.325 c\) ? Explain. momentum conservation to find the speed of the carts after they collide and stick together. (b) Use relativistic

Short Answer

Expert verified
In relativistic physics, the final speed will be less than 0.325c due to relativistic momentum conservation.

Step by step solution

01

Understanding Classical Physics Prediction

In classical mechanics, when two identical masses collide inelastically, momentum is conserved. For one cart at rest and another at speed \(0.650c\) in a classical collision, the final speed \(v_f\) is found using: \[ m v_i = 2m v_f \] where \(v_i = 0.650c\), \(m\) is the mass of one cart. Solving for \(v_f\), we get: \[ v_f = \frac{v_i}{2} = 0.325c \] Since this is a classical approximation, relativity suggests the result will be different.
02

Applying Relativistic Momentum Conservation

Use the relativistic momentum formula to account for speeds close to \(c\). The relativistic momentum is: \[ p = \frac{mv}{\sqrt{1-(v/c)^2}} \] Initially, only one cart has momentum, \(p_i = \frac{mv_i}{\sqrt{1-(v_i/c)^2}}\). After collision, both carts stick together, thus: \(p_f = \frac{2mv_f}{\sqrt{1-(v_f/c)^2}}\). Set \(p_i = p_f\) and solve for \(v_f\): \[ \frac{mv_i}{\sqrt{1-(v_i/c)^2}} = \frac{2mv_f}{\sqrt{1-(v_f/c)^2}} \] Cancel out the mass \(m\) and solve for \(v_f\).
03

Calculating Final Velocity

Rearrange and solve the equation: \[ \frac{v_i}{\sqrt{1-(v_i/c)^2}} = \frac{2v_f}{\sqrt{1-(v_f/c)^2}} \]Plug \(v_i = 0.650c\) into the equation and solve for \(v_f\):\[ v_f = \frac{v_i \sqrt{1-(v_f/c)^2}}{2\sqrt{1-(v_i/c)^2}} \]Solving iteratively, you find \(v_f < 0.325c\). Relativistic effects slow the final velocity compared to the classical prediction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
Momentum conservation is a fundamental principle in physics stating that in a closed system, the total momentum remains constant, regardless of the interactions that occur within the system. This principle holds true both in classical and relativistic mechanics, albeit with some differences in the way momentum is calculated.Classically, momentum is a simple product of mass and velocity: \[ p = mv \]For a completely inelastic collision where two objects stick together after collision, the total momentum before the collision equals the total momentum after the collision.In our example of two colliding air carts, the total initial momentum was entirely carried by one cart, as the other was at rest. By equating the total initial and final momentum, predictions about the final speed can be made. However, for speeds approaching the speed of light, this classical approach requires a relativistic correction to accurately predict outcomes.
Inelastic Collision
An inelastic collision is a type of collision where the colliding objects stick together after the impact, resulting in a loss of kinetic energy from the system, which often translates into deformation or heat. In completely inelastic collisions like the one in this scenario, kinetic energy is not conserved, but momentum is. This makes them unique because, unlike elastic collisions, you can’t use kinetic energy conservation to find final velocities. This characteristic is why the momentum conservation equation is particularly useful here. During our scenario's collision, the two air carts stick together, moving with a common velocity afterwards. The importance of this type of collision lies in understanding how energy is transformed and how momentum conservation provides a predictable outcome, albeit the predicted outcome in a relativistic context requires further calculations.
Relativistic Momentum
Relativistic momentum becomes key when we deal with velocities that are a significant fraction of the speed of light, denoted by \(c\). At these high speeds, the classical definition of momentum becomes inadequate.Relativistic momentum is defined as:\[ p = \frac{mv}{\sqrt{1-(v/c)^2}} \]This formula incorporates the Lorentz factor \(\sqrt{1-(v/c)^2}\), which adjusts for the effects of relativistic speeds.In the given exercise, because one cart is moving at an initial speed of \(0.650c\), relativistic momentum was necessary to accurately maintain the conservation of momentum after the collision. Unlike classical outcomes where you simply sum momenta, the calculation involves solving a more complex equation that takes into account the relativistic mass increase as velocity approaches \(c\).The practical impact is that you expect the final speed of the carts after the collision to be less than traditionally calculated due to these relativistic effects, thus demonstrating the fascinating deviations from classical mechanics at high velocities.

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