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Two rocket ships approach Earth from opposite directions, each with a speed of \(0.8 c\) relative to Earth. What is the speed of one ship relative to the other?

Short Answer

Expert verified
One ship's speed relative to the other is approximately \(0.9756c\).

Step by step solution

01

Understand the Problem

Two rocket ships are approaching Earth from opposite directions, each with a speed of \(0.8c\) relative to Earth. We need to find the speed of one ship relative to the other. This involves special relativity since the speeds are a significant fraction of the speed of light \(c\).
02

Use the Velocity Addition Formula

In special relativity, the relative velocity \(v_{rel}\) of two objects moving towards each other with velocities \(u\) and \(v\) is given by the formula: \[ v_{rel} = \frac{u + v}{1 + \frac{uv}{c^2}} \] Here, \(u = 0.8c\) and \(v = 0.8c\).
03

Substitute Values into the Formula

Plug in \(u = 0.8c\) and \(v = 0.8c\) into the velocity addition formula: \[ v_{rel} = \frac{0.8c + 0.8c}{1 + \frac{(0.8c)(0.8c)}{c^2}} \]
04

Simplify the Expression

Calculate the numerator and the denominator:- Numerator: \(0.8c + 0.8c = 1.6c\)- Denominator: \(1 + \frac{(0.8c)(0.8c)}{c^2} = 1 + 0.64 = 1.64\)
05

Calculate the Final Relative Velocity

Divide the numerator by the denominator to find \(v_{rel}\): \[ v_{rel} = \frac{1.6c}{1.64} \approx 0.9756c \]
06

Conclusion

The speed of one rocket ship relative to the other is approximately \(0.9756c\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Addition Formula
The velocity addition formula is a crucial concept in special relativity. It allows us to calculate the relative velocity of two objects moving towards or away from each other at significant fractions of the speed of light. This formula corrects the classical idea that you can simply add velocities together, which is only valid at much lower speeds. In the realm of special relativity, velocities don't just add up due to the effects of time dilation and length contraction.

The formula is given by:\[ v_{rel} = \frac{u + v}{1 + \frac{uv}{c^2}} \]where,
  • \(v_{rel}\) is the relative velocity.
  • \(u\) and \(v\) are the velocities of the two objects relative to a third reference point, like Earth in this context.
  • \(c\) is the speed of light in a vacuum.
This formula shows that the relative velocity will never exceed the speed of light, regardless of how fast the two objects approach each other, aligning with Einstein’s theory of relativity.
Relative Velocity
Understanding relative velocity is key when dealing with fast-moving objects, like rocket ships. Relative velocity is the speed of one object as observed from another moving object. In everyday life, we consider this by simply subtracting velocities. However, at high speeds approaching the speed of light, this simple subtraction doesn't hold due to relativistic effects.

In special relativity, the relative velocity is calculated using the velocity addition formula. This accounts for changes in time perception and distance caused by traveling at high speeds, ensuring that calculations remain consistent with the principle that no object can exceed the speed of light.

When applying the formula,
  1. Ensure values are relative to the same reference point.
  2. Remember to use the speed of light as a limit.
  3. Always interpret results in the context of a relativistic universe, avoiding assumptions from classical physics.
Mastering this concept is essential for accurately predicting how velocities compare in high-speed scenarios.
Speed of Light
The speed of light, denoted as \(c\), is one of the cornerstones of special relativity. It is approximately \(299,792,458\) meters per second in a vacuum. This constant speed is crucial because it sets the universal speed limit for how fast information and matter can travel anywhere in the universe.

Why does the speed of light matter so much in relative velocity problems? It prevents any object with mass from reaching or exceeding it. If we simply added velocities in a classical sense, it would imply that speeds could surpass \(c\), violating this fundamental limit.

The consequences of having such a constant are profound. They mean that both time and space are intertwined in what we call spacetime. The velocity addition formula accounts for this by adjusting how velocities add up, such that the total doesn't exceed the speed of light.

Key Points About the Speed of Light:
  • It is always constant and doesn't change, regardless of the observer's movement.
  • It affects both time dilation, where time slows down at speeds near \(c\), and length contraction, where distances compress.
  • No matter the scenario, \(c\) remains the definitive limit for speed.
Understanding \(c\) helps in making sense of how velocities interact at relativistic speeds.

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Most popular questions from this chapter

When traveling past an observer with a relative speed \(v\), a rocket is measured to be \(9.00 \mathrm{m}\) long. When the rocket moves with a relative speed \(2 v,\) its length is measured to be \(5.00 \mathrm{m}\). (a) What is the speed \(v ?\) (b) What is the proper length of the rocket?

Cosmic Rays Protons in cosmic rays have been observed with kinetic energies as large as \(1.0 \times 10^{20} \mathrm{eV}\). (a) How fast are these protons moving? Give your answer as a fraction of the speed of light. (b) Show that the kinetic energy of a single one of these protons is much greater than the kinetic energy of a 15 -mg ant walking with a speed of \(8.8 \mathrm{mm} / \mathrm{s}\).

A proton has 1836 times the rest mass of an electron. At what speed will an electron have the same kinetic energy as a proton moving at \(0.0250 \mathrm{c} ?\)

Captain Jean-Luc is piloting the USS Enterprise XXIII at a a constant speed \(v=0.825 \mathrm{c} .\) As the Enterprise passes the planet Vulcan, he notices that his watch and the Vulcan clocks both read 1: 00 P.M. At 3: 00 P.M., according to his watch, the Enterprise passes the planet Endor. If the Vulcan and Endor clocks are synchronized with each other, what time do the Endor clocks read when the Enterprise passes by?

\(A 2.5-m\) titanium rod in a moving spacecraft is at an angle of \(45^{\circ}\) with respect to the direction of motion. The craft moves directly toward Earth at \(0.98 \mathrm{c}\). As viewed from Earth, (a) how long is the rod and (b) what angle does the rod make with the direction of motion?

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