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Suppose the speed of light is \(35 \mathrm{mi} / \mathrm{h}\). A paper girl riding a bicycle at \(22 \mathrm{mi} / \mathrm{h}\) throws a rolled-up newspaper in the forward direction, as shown in Figure \(29-30\). If the paper is thrown with a speed of \(19 \mathrm{mi} / \mathrm{h}\) relative to the bike, what is its speed, \(v,\) with respect to the ground?

Short Answer

Expert verified
The speed of the newspaper relative to the ground is 41 mi/h.

Step by step solution

01

Understanding Relative Motion

Relative motion can be described by the formula \(v_{total} = v_1 + v_2\), where \(v_1\) is the speed of an object in its own frame (e.g., the paper relative to the bike), and \(v_2\) is the speed of the frame relative to a reference point (the bike relative to the ground). Here, we determine how these add up to find the object's speed relative to the reference point (the paper relative to the ground).
02

Identify Given Values

We know the speed of the bike relative to the ground is \(22 \mathrm{mi/h}\), and the speed of the newspaper relative to the bike is \(19 \mathrm{mi/h}\).
03

Apply the Formula

Use the formula for relative motion: \(v_{ground} = v_{bike} + v_{paper/bike}\). Substituting in the known values: \(v_{ground} = 22 + 19\).
04

Calculate the Result

Perform the addition to find the speed of the paper relative to the ground. \(v_{ground} = 22 \mathrm{mi/h} + 19 \mathrm{mi/h} = 41 \mathrm{mi/h}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed of Light
The speed of light is a fundamental constant in physics, usually denoted by the symbol "c." It represents the speed at which light travels in a vacuum, which is approximately 186,282 miles per second (or about 299,792 kilometers per second). However, in this exercise, the speed of light is hypothetically set at 35 miles per hour for simplicity's sake, which is not realistic but helps in understanding the concepts of relative motion and velocity addition more clearly. Even when working with such hypothetical scenarios, it's crucial to remember that the actual speed of light is constant and doesn't change under normal conditions. This constancy is central to Einstein's theory of relativity, which explores how the laws of physics, including the speed of light, remain consistent regardless of the observer's velocity. In everyday situations on Earth, where speeds are much slower than light, the principles of relative motion and velocity addition can still be applied using ordinary velocities, as shown in the exercise scenario.
Reference Frame
A reference frame is essentially a viewpoint or perspective from which we observe and measure objects' movements. In physics, choosing the right reference frame is critical for correctly analyzing a situation involving relative motion. In the provided exercise, there are two main reference frames:
  • The bike's reference frame (or frame of reference of the paper girl), where the newspaper is thrown.
  • The ground's reference frame, which helps us calculate the newspaper's speed concerning the ground.
The bike and ground reference frames are related by the motion of the bike. This means that to find out how fast the newspaper moves concerning the ground, we add the speed of the newspaper relative to the bike to the bike's speed in relation to the ground. Understanding how these frames interact allows us to solve complex motion problems easily and apply the correct physics formulas.
Velocity Addition
Velocity addition is a fundamental concept when dealing with objects moving within different reference frames, particularly when they may have different velocities. In classical physics, we often use the simple addition formula:\[ v_{total} = v_1 + v_2 \]In this equation:
  • \(v_1\) is the speed of an object in its immediate frame (like the newspaper relative to the bike).
  • \(v_2\) is the speed of that frame relating to a different reference point (such as the bike's speed relative to the ground).
Applying this to the exercise, the forward speed of the newspaper relative to the bike can be combined with the bike's motion concerning the ground. This results in the paper's overall speed relative to the ground. Simple addition reveals the newspaper travels at 41 mi/h concerning the ground.In scenarios approaching the speed of light, however, the rules modify slightly according to Einstein's theory of relativity, ensuring the speed of light isn't surpassed, but for practical everyday speeds, the straightforward addition of velocities suffices.

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Most popular questions from this chapter

As a spaceship flies past with speed \(v,\) you observe that \(1.0000 \mathrm{s}\) elapses on the ship's clock in the same time that 1.0000 min elapses on Earth. How fast is the ship traveling, relative to the Earth? (Express your answer as a fraction of the speed of light.)

CE An apple drops from the bough of a tree to the ground. Is the mass of the apple near the top of its fall greater than, less than, or the same as its mass after it has landed? Explain.

IP A starship moving away from Earth with a speed of \(0.75 c\) launches a shuttle craft in the reverse direction, that is, toward Earth. (a) If the speed of the shuttle relative to the starship is \(0.40 c,\) and its proper length is \(13 \mathrm{m},\) how long is the shuttle as measured by an observer on Earth? (b) If the shuttle had been launched in the forward direction instead, would its length as measured by an observer on Earth be greater than, less than, or the same as the length found in part (a)? Explain. (c) Calculate the length for the case described in part (b).

Predict/Explain Suppose you are a traveling salesman for \(\$ S C,\) the Spacely Sprockets Company. You travel on a spaceship that reaches speeds near the speed of light, and you are paid by the hour. (a) When you return to Earth after a sales trip, would you prefer to be paid according to the clock at Spacely Sprockets universal headquarters on Earth, according to the clock on the spaceship in which you travel, or would your pay be the same in either case? (b) Choose the best explanation from among the following: I. You want to be paid according to the clock on Earth, because the clock on the spaceship runs slow when it approaches the speed of light. II. Collect your pay according to the clock on the spaceship because according to you the clock on Earth has run slow. III. Your pay would be the same in either case because motion is relative, and all inertial observers will agree on the amount of time that has elapsed.

Albert is piloting his spaceship, heading east with a speed of \(0.90 c .\) Albert's ship sends a light beam in the forward (eastward) direction, which travels away from his ship at a speed \(c\). Meanwhile, Isaac is piloting his ship in the westward direction, also at \(0.90 c,\) toward Albert's ship. With what speed does Isaac see Albert's light beam pass his ship?

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