/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 A spaceship moving toward Earth ... [FREE SOLUTION] | 91Ó°ÊÓ

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A spaceship moving toward Earth with a speed of \(0.90 \mathrm{c}\) launches a probe in the forward direction with a speed of \(0.10 c\) relative to the ship. Find the speed of the probe relative to Earth.

Short Answer

Expert verified
The speed of the probe relative to Earth is approximately \(0.9174c\).

Step by step solution

01

Understanding the Problem

The problem involves relativistic velocity addition. Given a spaceship moving at a speed of \(0.90c\) (where \(c\) is the speed of light) towards Earth and a probe launched relative to the spaceship at \(0.10c\), we are to find the speed of the probe relative to Earth.
02

Identify the Relativistic Velocity Addition Formula

In special relativity, the velocity of an object as observed in a different inertial frame is calculated using the formula: \[ v = \frac{u + v'}{1 + \frac{uv'}{c^2}} \]where \(u\) is the velocity of the observer (spaceship) relative to Earth, \(v'\) is the velocity of the probe relative to the observer (spaceship), and \(v\) is the velocity of the probe relative to Earth.
03

Substitute Given Values into the Formula

Substitute \(u = 0.90c\) and \(v' = 0.10c\) into the formula:\[ v = \frac{0.90c + 0.10c}{1 + \frac{0.90c \cdot 0.10c}{c^2}} \]
04

Simplify the Numerator

The numerator becomes:\[ 0.90c + 0.10c = 1.00c \]
05

Simplify the Denominator

The denominator becomes:\[ 1 + \frac{0.90c \cdot 0.10c}{c^2} = 1 + 0.09 = 1.09 \]
06

Compute the Probe's Velocity

Substitute back into the equation:\[ v = \frac{1.00c}{1.09} \approx 0.9174c \]So, the speed of the probe relative to Earth is approximately \(0.9174c\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special Relativity is a cornerstone of modern physics introduced by Albert Einstein in 1905. It revolutionized our understanding of space, time, and motion. One of its key principles is that the laws of physics are the same for all observers in uniform motion relative to each other. This principle challenged the traditional Newtonian physics which treated time and space as absolute. In special relativity, both time and space are intertwined in what is called "spacetime."
  • Time dilation occurs when time appears to run slower for an object moving at high speed compared to a stationary observer.
  • Length contraction means that objects appear shorter in the direction of motion as their speed approaches the speed of light.
These effects are not noticeable at everyday speeds but become significant as speeds approach the speed of light. As demonstrated in the original exercise, the relativistic velocity addition formula is used when dealing with high speeds. Unlike classical velocity addition, this formula ensures the resultant speed never exceeds the speed of light.
Speed of Light
The speed of light, denoted by the symbol \(c\), is the ultimate speed limit in the universe, approximately equal to \(299,792,458\) meters per second (or roughly \(300,000\) kilometers per second). It is fundamental to the theory of special relativity and is independent of the motion of the source or the observer. This means that no matter how fast you are moving, you will always measure the speed of light to be the same.
  • Light travels at constant speed in a vacuum.
  • As an absolute speed limit, massive objects cannot reach or exceed this speed.
This constancy leads to crucial consequences such as time dilation and relativistic velocity addition. In the problem we explored, the probe's speed relative to Earth was found using the relativistic addition formula, ensuring it remains below \(c\). The formula considers both the speeds and factors in their relative directions, critical in maintaining the light speed limit.
Inertial Frame
An inertial frame of reference is a viewpoint in which an object either is at rest or moves at a constant velocity. Special relativity holds most accurately in inertial frames without accelerations. This concept is vital to understanding how observers measure different velocities, times, and lengths.
  • All the laws of physics appear identical to an observer in any inertial frame.
  • Observers in different inertial frames may disagree on measurements of space and time but will find the same speed for light.
In our exercise, Earth and the spaceship are both considered to be in inertial frames. The spaceship moves uniformly towards Earth, which allows us to apply the relativistic principles straightforwardly without needing to account for external forces or accelerations. This simplification is crucial for deriving the relationship between the velocities involved in our problem.

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Most popular questions from this chapter

IP (a) Is it possible for you to travel far enough and fast enough so that when you return from a trip, you are younger than your stay-at-home sister, who was born 5.0 y after you? (b) Suppose you fly on a rocket with a speed \(v=0.99 \mathrm{c}\) for \(1 \mathrm{y}\) according to the ship's clocks and calendars. How much time elapses on Earth during your 1 -y trip? \((c)\) If you were 22 y old when you left home and your sister was 17 , what are your ages when you return?

Albert is piloting his spaceship, heading east with a speed of \(0.90 c .\) Albert's ship sends a light beam in the forward (eastward) direction, which travels away from his ship at a speed \(c\). Meanwhile, Isaac is piloting his ship in the westward direction, also at \(0.90 c,\) toward Albert's ship. With what speed does Isaac see Albert's light beam pass his ship?

Show that the total energy of an object is related to its momentum by the relation \(E^{2}=p^{2} c^{2}+\left(m_{0} c^{2}\right)^{2}.\)

At what speed does the classical momentum, \(p=m v,\) give an error, when compared with the relativistic momentum, of (a) \(1.00 \%\) and (b) \(5.00 \% ?\)

CE Predict/Explain Consider two apple pies that are identical in every respect, except that pie 1 is piping hot and pie 2 is at room temperature. (a) If identical forces are applied to the two pies, is the acceleration of pie 1 greater than, less than, or equal to the acceleration of pie \(2 ?\) (b) Choose the best explanation from among the following: I. The acceleration of pie 1 is greater because the fact that it is hot means it has the greater energy. II. The fact that pie 1 is hot means it behaves as if it has more mass than pie \(2,\) and therefore it has a smaller acceleration. III. The pies have the same acceleration regardless of their temperature because they have identical rest masses.

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