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A light source emits two distinct wavelengths \(\left[\lambda_{1}=430 \mathrm{nm}\right.\) (violet); \(\lambda_{2}=630 \mathrm{nm}\) (orange)]. The light strikes a diffraction grating with 450 lines/mm at normal incidence. Identify the colors of the first eight interference maxima on either side of the central maximum.

Short Answer

Expert verified
Alternate between violet and orange for maxima from the first to the eighth order on each side.

Step by step solution

01

Understand the Problem

We have a light source emitting two wavelengths, 430 nm and 630 nm, falling on a diffraction grating with 450 lines/mm. We need to find the colors of the first eight interference maxima on either side of the central maximum.
02

Convert Grating Lines to Spacing

Calculate the spacing between the lines of the grating. The number of lines per meter is 450,000 lines/m (since 1 mm = 0.001 m). The spacing, \(d\), is the reciprocal of this:\[d = \frac{1}{450,000} \, \text{m}\]
03

Use the Diffraction Grating Formula

The diffraction condition for maxima is given by:\[d \cdot \sin \theta = m \cdot \lambda\]where \(d\) is the spacing between the lines, \(\theta\) is the diffraction angle, \(m\) is the order of the interference maximum, and \(\lambda\) is the wavelength of light.
04

Calculate First Eight Maxima for Each Wavelength

For each wavelength (430 nm and 630 nm), calculate the angles where maxima occur for \(m = 1, 2, \ldots, 8\). Since \(\theta\) increases with \(m\), the first order maximum is narrowest, and the eighth is broadest. Use:\[sin \theta_m = \frac{m \lambda}{d}\]Calculate \(\theta_m\) for \(m = 1, 2, \ldots, 8\) for both \(\lambda_{1} = 430 \text{ nm}\) (violet) and \(\lambda_{2} = 630 \text{ nm}\) (orange).
05

Determine the Sequence of Colors

In order: compute the angles for both wavelengths and list the maxima sequences. Since \(\lambda_1 < \lambda_2\), the violet maxima for each order will appear at smaller angles compared to orange. For each order \(m\), list the colors as 'violet; orange'. This sequence will alternate on either side of the central maximum (which is white due to the overlay of all colors).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interference Maxima
When light passes through a diffraction grating, it spreads out and creates bright spots on a screen. These bright spots are called interference maxima. Each maximum corresponds to specific angles where constructive interference occurs. The most central spot is called the zeroth-order maximum. As you move away from this central point, you encounter the first order, second order, and so on. The order of the maximum, denoted by \(m\), signifies the number of wavelengths by which paths differ between successive slits.
You can think of interference maxima as bright, colorful dots on your wall when shining light through a grating. The intensity and position of these dots depend on the properties of the light and the grating. For example:
  • Blue or violet light results in interference maxima at different positions compared to red or orange.
  • The order of the maximum (e.g., 1st, 2nd) changes the angle at which these dots appear.
Recognizing these patterns is crucial for understanding phenomena like the separation of light into its component colors.
Wavelength
A wavelength refers to the distance between two consecutive peaks of a wave. It's a crucial characteristic that determines how light interacts with other objects, like a diffraction grating. In this exercise, we have two specific wavelengths: 430 nm (nanometers) for violet light and 630 nm for orange light. These numbers imply how stretched or compressed a wave is.
The difference in these wavelengths is what allows us to see different colors when the light is spread out using a diffraction grating. Longer wavelengths (like 630 nm) are associated with redder colors, whereas shorter wavelengths (like 430 nm) correlate with bluer hues.
  • Shorter wavelengths (violet) will generally diffract at smaller angles.
  • Longer wavelengths (orange) will diffract at larger angles.
Understanding wavelength is fundamental to explaining why different colors appear at different positions in a diffraction pattern.
Diffraction Angle
The diffraction angle, denoted as \(\theta\), is the angle at which light waves spread out after passing through a diffraction grating. It's determined by the spacing of the grating and the wavelength of light. In the context of interference maxima, this angle will vary for different orders \(m\) and wavelengths.
This angle is essential as it dictates where each interference maximum will appear relative to the central maximum. By using the formula \[d \cdot \sin \theta = m \cdot \lambda\] we can calculate the diffraction angles for each order. Typically, shorter wavelengths like violet light will have smaller diffraction angles for the same order compared to longer wavelengths like orange light.
  • The first order maximum will be closer than the eighth, causing an increase in angle with order number.
  • The variation in angles allows different colors to emerge from the combined spectrum.
By understanding diffraction angles, you gain insight into how wave properties influence the appearance of light after passing through a narrow opening.
Diffraction Condition
The diffraction condition is a specific requirement that must be met for interference maxima to form. This condition can be expressed through the diffraction grating formula: \[d \cdot \sin \theta = m \cdot \lambda\] where:
  • \(d\) is the spacing between the lines on the grating.
  • \(\theta\) is the angle of diffraction.
  • \(m\) represents the order of the peak.
  • \(\lambda\) is the wavelength of light.
This equation helps determine which angles will produce bright spots, or maxima, for a given wavelength and order. If the diffraction condition is satisfied, light waves from different slits interfere constructively, enhancing the brightness of the interference pattern.
Understanding the diffraction condition is key to predicting and explaining where and why these bright spots occur. It provides a systematic way to relate the physical properties of the grating to the observable light pattern, helping us harness and analyze optical phenomena efficiently.

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Most popular questions from this chapter

A diffraction grating has 2200 lines/cm. What is the angle between the first- order maxima for red light \((\lambda=680 \mathrm{nm})\) and blue light \((\lambda=410 \mathrm{nm}) ?\)

A thin soap film \((n=1.33)\) suspended in air has a uniform thickness. When white light strikes the film at normal incidence, violet light \(\left(\lambda_{\mathrm{V}}=420 \mathrm{nm}\right)\) is constructively reflected. (a) If we would like green light \(\left(\lambda_{G}=560 \mathrm{nm}\right)\) to be constructively reflected, instead, should the film's thickness be increased or decreased? (b) Find the new thickness of the film. (Assume the film has the minimum thickness that can produce these reflections.)

The yellow light from a helium discharge tube has a wavelength of \(587.5 \mathrm{nm}\). When this light illuminates a certain diffraction grating it produces a first-order principal maximum at an angle of \(1.250^{\circ} .\) Calculate the number of lines per centimeter on the grating.

A person driving at \(17 \mathrm{m} / \mathrm{s}\) crosses the line connecting two radio transmitters at right angles, as shown in Figure \(28-31\). The transmitters emit identical signals in phase with each other, which the driver receives on the car radio. When the car is at point \(A\), the radio picks up a maximum net signal. (a) What is the longest possible wavelength of the radio waves? (b) How long after the car passes point A does the radio experience a minimum in the net signal? Assume that the wavelength has the value found in part (a).

A two-slit experiment with slits separated by \(48.0 \times 10^{-5} \mathrm{m}\) produces a second-order maximum at an angle of \(0.0990^{\circ}\) (a) Find the wavelength of the light used in this experiment. (b) If the slit separation is increased but the secondorder maximum stays at the same angle, does the wavelength increase, decrease, or stay the same? Explain. (c) Calculate the wavelength for a slit separation of \(68.0 \times 10^{-5} \mathrm{m}\).

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