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Is resolution greater with blue light or red light, all other factors being equal? Explain.

Short Answer

Expert verified
Resolution is greater with blue light because it has a shorter wavelength than red light.

Step by step solution

01

Understand the Concept of Resolution

Resolution in optics refers to the ability of an optical system, like a microscope or telescope, to distinguish two closely spaced objects as separate. It depends inversely on the wavelength of light used, meaning shorter wavelengths provide better resolution.
02

Assess the Wavelength of Colors

Red light typically has a longer wavelength (about 620-750 nm) compared to blue light (about 450-495 nm). This means blue light has a shorter wavelength than red light.
03

Apply the Resolution Formula

The resolution (\( R \)) can be described by the formula \( R = \frac{1.22 \cdot \lambda}{D} \), where \( \lambda \) is the wavelength and \( D \) is the diameter of the aperture. A shorter wavelength \( \lambda \) results in a smaller \( R \), thus higher resolution.
04

Conclude Based on the Relationship

Since blue light has a shorter wavelength compared to red light, it provides higher resolution according to the resolution formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength of Light
The wavelength of light is essentially the distance between two consecutive peaks or troughs in a wave of light. It is the defining characteristic that differentiates one color of light from another. In the visible spectrum, different colors correspond to different wavelengths. For instance, blue light has a shorter wavelength, typically around 450-495 nanometers (nm), while red light has a longer wavelength of about 620-750 nm.

This difference in wavelength explains why blue and red light appear as distinct colors to our eyes. Beyond just color, the wavelength has significant implications in optics, particularly in determining the resolution of optical systems like microscopes and telescopes.
Microscope and Telescope Optics
Microscopes and telescopes are optical instruments designed to enhance our ability to see and resolve details of objects that are either very small or very far away.

The function of a microscope is to magnify small objects that are close, such as cells or bacteria, while a telescope brings distant objects like planets and stars into clearer view. In both cases, the ability of these devices to distinguish between two points or objects that are very close together is known as resolution.
  • Resolution is crucial for the clarity and detail in the images produced by these instruments.
  • The optical system uses lenses or mirrors to focus light, allowing us to see smaller details that are not visible to the naked eye.
Both microscopes and telescopes benefit from using light sources with shorter wavelengths, such as blue light, because it improves their resolving power.
Resolution Formula
The resolution of an optical system is quantified using a formula that relates the wavelength of light to the aperture of the system. This is often expressed as: \[ R = \frac{1.22 \cdot \lambda}{D} \] where
  • \( R \) represents the resolution,
  • \( \lambda \) denotes the wavelength of light,
  • \( D \) is the diameter of the aperture.


According to this formula, if the wavelength (\( \lambda \)) decreases, the resolution (\( R \)) becomes smaller, indicating higher resolution. This is why blue light, with its shorter wavelength, provides better resolution compared to red light.

The aperture size (\( D \)) also plays a role: a larger aperture allows more light to enter, which can enhance resolution by collecting more light waves. Thus, improving both the wavelength and aperture can significantly boost the performance of optical instruments.

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Most popular questions from this chapter

A soap bubble with walls 401 nm thick floats in air. If this bubble is illuminated perpendicularly with sunlight, what wavelength (and color) will be absent in the reflected light? Assume that the index of refraction of the soap film is 1.33 . (Refer to Example \(25-3\) for the connection between wavelength and color.)

A two-slit experiment with blue light produces a set of bright fringes. Will the spacing between the fringes increase, decrease, or stay the same if (a) the separation of the slits is decreased, or (b) the experiment is immersed in water?

A two-slit experiment with slits separated by \(48.0 \times 10^{-5} \mathrm{m}\) produces a second-order maximum at an angle of \(0.0990^{\circ}\) (a) Find the wavelength of the light used in this experiment. (b) If the slit separation is increased but the secondorder maximum stays at the same angle, does the wavelength increase, decrease, or stay the same? Explain. (c) Calculate the wavelength for a slit separation of \(68.0 \times 10^{-5} \mathrm{m}\).

A microphone is located on the line connecting two speakers that are \(0.845 \mathrm{m}\) apart and oscillating \(180^{\circ}\) out of phase. The microphone is \(2.25 \mathrm{m}\) from the midpoint of the two speakers. What are the lowest two frequencies that produce an interference maximum at the microphone's location?

A curved piece of glass with a radius of curvature \(R\) rests on a flat plate of glass. Light of wavelength \(\lambda\) is incident normally on this system. Considering only interference between waves reflected from the curved (lower) surface of glass and the top surface of the plate, show that the radius of the \(nth\) dark ring is $$ r_{n}=\sqrt{n \lambda R-n^{2} \lambda^{2} / 4} $$

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