/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 The actual frame size of \(" 35-... [FREE SOLUTION] | 91Ó°ÊÓ

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The actual frame size of \(" 35-m m "\) film is \(24 \mathrm{mm} \times 36 \mathrm{mm}\). You want to take a photograph of your friend, who is \(1.9 \mathrm{m}\) tall. Your camera has a \(55-\mathrm{mm}\) -focal-length lens. How far from the camera should your friend stand in order to produce a \(36-\mathrm{mm}\) tall image on the film?

Short Answer

Expert verified
Friend stands about 2.903 m from the camera.

Step by step solution

01

Understanding Similar Triangles

In photography, the camera lens creates an image on the film by forming a triangle with the actual object. The object, the lens, and the image form two similar triangles. Here, the film's image height is 36 mm, and your friend's height is 1.9 m. The goal is to find the distance from the camera lens to your friend that gives a 36 mm image height.
02

Set Up Proportion Equations

Since the triangles are similar, the ratio of the image height to the object height is equal to the ratio of the lens's focal length to the object distance from the lens. Let \( h_i \) be the image height (36 mm), \( h_o \) be the object height (1.9 m = 1900 mm), \( f \) be the focal length (55 mm), and \( d_o \) be the object distance. Set up the proportion: \( \frac{h_i}{h_o} = \frac{f}{d_o} \).
03

Solve the Proportion for Object Distance

Plugging in the values, we have \( \frac{36}{1900} = \frac{55}{d_o} \). Cross-multiply to get \( 36d_o = 1900 \times 55 \). Then, solve for \( d_o \) by dividing both sides by 36: \( d_o = \frac{1900 \times 55}{36} \).
04

Calculate Object Distance

Perform the calculation: \( d_o = \frac{1900 \times 55}{36} \approx 2902.78 \text{ mm} \). Convert \( d_o \) from mm to meters by dividing by 1000: \( d_o \approx 2.903 \text{ m} \).
05

Conclusion

Your friend should stand approximately 2.903 meters away from the camera to produce a 36-mm tall image on the film.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length
In the world of optics, the term "focal length" is a core concept that refers to the distance between the lens and the image sensor (or film) when the subject is in focus. A 55 mm focal length lens, like the one in this exercise, defines the lens's capability to converge light and create clear images. Focal length plays a crucial role in determining both the angle of view (how much of the scene will be captured) and the magnification (how large individual elements appear within the frame). With a shorter focal length, you'll capture a wider scene, whereas a longer focal length allows you to zoom in on a particular subject. In our problem, understanding focal length is vital to calculate how far the person should stand to have their image correctly sized on the film. The specific focal length of 55 mm has been used to create a specific image size (36 mm) for an object of height 1.9 m. Keeping these proportions allows us to apply geometric principles of similar triangles effectively.
Image Formation
Image formation in optics involves creating a visual representation of an object using lenses. When light rays pass through a lens, they converge (or sometimes diverge) to form an image. This process is what helps cameras capture photos. The lens of a camera essentially functions as the eye of the system, bending light rays to form an image on the film. For an image to be properly formed, there needs to be a balance between the object distance, focal length, and image height. In this exercise, we are dealing with a 55 mm lens that forms an image of your friend who is 1.9 m tall. By setting up and solving a mathematical proportion, we calculated the necessary distance for the image on the film to be 36 mm tall. This precise arrangement ensures that the image remains sharp and well-proportioned based on the focal length and distances used.
Proportions in Physics
Proportions play a significant role in understanding physical systems, especially in optics where similar triangles are a powerful tool. Similar triangles allow us to relate different parts of a setup simply by comparing their proportional dimensions. In the given problem, the height of your friend and the height of the image formed create two similar triangles when combined with the focal length as a reference point. We use the aspect of similarity to establish a simple equation: the ratio of the image height to object height equals the ratio of the focal length to the object distance from the lens. This concept simplifies our task of determining how far your friend should stand from the camera. After setting up the proportion using our known values, we solve for the unknown, which is the distance. Such use of proportions helps us model and solve a vast array of physical problems where geometry and distances are involved.

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Most popular questions from this chapter

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