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A grade school student plans to build a 35 -power telescope as a science fair project. She starts with a magnifying glass with a focal length of \(5.0 \mathrm{cm}\) as the eyepiece. What focal length is needed for her objective lens?

Short Answer

Expert verified
The focal length needed for the objective lens is 175 cm.

Step by step solution

01

Understanding Telescope Magnification

The magnification of a telescope is the ratio of the focal length of the objective lens to the focal length of the eyepiece. It is given by the formula: \( M = \frac{f_o}{f_e} \), where \( M \) is the total magnification, \( f_o \) is the focal length of the objective, and \( f_e \) is the focal length of the eyepiece.
02

Plug in Given Values

The student wants a telescope with a magnification \( M = 35 \), and the focal length of the eyepiece \( f_e = 5.0 \) cm. Substitute these into the formula: \( 35 = \frac{f_o}{5.0} \).
03

Solve for Objective Focal Length

Re-arrange the equation to solve for \( f_o \): \( f_o = 35 \times 5.0 \). By multiplying these values, we find \( f_o = 175 \) cm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Lens Focal Length
The objective lens is a critical component of a telescope. It is responsible for gathering light from the object you're observing and focusing it to create a clear image. The focal length of this lens is really important because it determines how much light is bent towards the image point.

Think of the focal length of the objective lens as its "zooming power". A longer focal length allows the lens to gather more light and provide a bigger, more detailed image. However, it also means that the telescope becomes larger in terms of physical size. For our science fair student, calculating the right focal length for the objective lens means achieving the desired magnification without making the telescope too bulky.
  • More focal length = More zoom
  • Resulting image size depends on the focal length
  • Larger focal lengths require larger telescope setups
Focal Length Calculation
Calculating the focal length for the objective lens in a telescope involves understanding the relationship between the lens components and the desired magnification. The formula we use is:\( M = \frac{f_o}{f_e} \), where:
  • \( M \) is the magnification that we want
  • \( f_o \) is the focal length of the objective lens
  • \( f_e \) is the focal length of the eyepiece
To find out the needed focal length for the objective lens, you simply rearrange the formula to solve for \( f_o \): \( f_o = M \times f_e \).

In our example, with a 35-power telescope and a 5.0 cm eyepiece focal length, plug these values into the formula:\( 35 = \frac{f_o}{5.0} \) and rearrange to get \( f_o = 35 \times 5.0 = 175 \) cm. This focal length is optimal for achieving the desired magnification in the telescope design.
Science Fair Project
Designing a telescope can be an exciting science fair project! It combines conceptual knowledge with practical application, offering a hands-on approach to learning about optics and physics. Such a project requires understanding of light properties, careful calculations, and some creativity.

Considerations for a successful science fair telescope project include:
  • Deciding on the magnification power based on what you want to observe, like stars or distant landscapes
  • Choosing appropriate lenses that fit your design and are available within your resources
  • Assembling the telescope with precision to ensure proper alignment of lenses for a clear image
For our student wanting a 35-power telescope, understanding how to calculate and select the right focal lengths for the lenses is part of the project's challenge and educational benefit. It's a tangible way to see how theoretical knowledge translates into real-world applications, and it can greatly enhance your understanding of the fascinating field of optics.

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