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The barrel of a compound microscope is \(15 \mathrm{cm}\) in length. The specimen will be mounted \(1.0 \mathrm{cm}\) from the objective, and the eyepiece has a \(5.0-\mathrm{cm}\) focal length. Determine the focal length of the objective lens.

Short Answer

Expert verified
The focal length of the objective lens is approximately 1.11 cm.

Step by step solution

01

Understanding the Microscope Setup

In this problem, a compound microscope is used, which consists of two converging lenses: the objective lens and the eyepiece lens. The total length of the microscope tube is the distance from the objective lens to the eyepiece, given as 15 cm. The object distance for the objective is 1 cm from the lens, and the eyepiece has a focal length of 5 cm.
02

Finding the Image Distance for the Objective Lens

First, note that in a compound microscope, the magnified image produced by the objective acts as the object for the eyepiece. Use the lens formula \(\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\) for the objective lens, where \(f\) is the focal length, \(v\) is the image distance, and \(u\) is the object distance (-1 cm since it is on the opposite side of the light direction). We need the total distance \(v + u\) to be less than or equal to 15 cm for the image to properly form within the tube.
03

Relating Objective and Eyepiece Distances

Since the total length of the microscope is 15 cm and the image formed by the objective is at \(v\) cm, we consider that the object for the eyepiece will be at \(15 - v\) cm (the remaining length within the tube). The eyepiece's focal length is 5 cm, and for clear viewing with the eyepiece, the image formed by the eyepiece needs to be at infinity, effectively making the object distance \(15 - v = 5\) (its focal length).
04

Calculating the Focal Length of the Objective Lens

From the relationship \(v + u = 15\) cm and using the eyepiece calculation \(v = 10\) cm, substitute these values into the lens formula for the objective lens: \(\frac{1}{f_o} = \frac{1}{10} - \frac{1}{1}\). Calculate to find \(f_o\).
05

Conclusion and Result

After solving the lens formula for the objective lens, we find \(f_o = 1.11\) cm. This confirms that the objective lens focal length is calculated based on the setup constraints.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Lens
The objective lens is a vital component of a compound microscope. It is the lens closest to the specimen being observed. Its primary function is to collect light from the specimen and create a magnified image. This image is then further magnified by the eyepiece lens. The position and focal length of the objective lens determine how much the specimen is initially magnified.

In a compound microscope, the objective lens is characterized by a short focal length, which allows it to produce a highly magnified image of the specimen that is still located at a short distance. This short distance is often just a few millimeters from the lens, ensuring precise and detailed observations.

When discussing compound microscopes, the relationship between the objective lens and the microscope tube is essential. The lens formula \[\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\] helps determine the required focal length for the objective lens. Here, \(f\) represents the focal length, \(v\) the image distance, and \(u\) the object distance. Understanding this can greatly aid in accomplishing the right setup for scientific experimentation.
Eyepiece
The eyepiece, often known as the ocular lens, is the lens you look through at the top of a microscope. It magnifies the image formed by the objective lens. The typical eyepiece has a focal length of around 5 cm, as seen in the given problem, which plays a crucial role in determining how the final image is viewed.

Eyepieces are usually marked with the magnification they provide. For example, an eyepiece marked "10x" will magnify the intermediate image produced by the objective by an additional 10 times. The positioning of the eyepiece within the microscope tube is also vital. It ensures that the image viewed is clear and enlarged proportionally to the total magnification desired.

Working harmoniously with the objective lens, the eyepiece provides the final magnified image that users see. The correct eyepiece selection depends on the purpose of observation and is crucial for achieving the desired resolution and quality of observation.
Focal Length
Focal length is a critical concept in optics and directly influences the function and performance of lenses used in compound microscopes. It refers to the distance between the lens and its focus point, where light rays converge or appear to diverge.

In the context of the given exercise, focal length determines how the objective and eyepiece lenses work together:
  • The objective lens must have a shorter focal length to magnify the specimen strongly.
  • The eyepiece usually has a longer focal length, influencing how the observer perceives the final image.
By manipulating these focal lengths, the magnification and resolution of a microscope can be finely tuned. This adjustment is crucial for scientific applications where observation detail is of utmost importance, such as in biology and materials science.
Microscope Tube
The microscope tube is the optical pathway linking the objective lens and the eyepiece in a compound microscope. This tube’s length, as given in the problem (15 cm), is the fixed distance over which the intermediate image is transferred from the objective lens to the eyepiece.

The role of the microscope tube is to maintain a constant distance, enabling the formation of a well-aligned image for further magnification by the eyepiece. When the proper lengths and distances are maintained, the resulting image can be accurately observed, magnified, and focused.

Understanding the tube’s role helps in comprehensively setting up a compound microscope, ensuring that the focal lengths are suited for the intended magnification, and connecting the relationship between various optical elements in the microscope effectively. Proper alignment through the microscope tube optimizes the clarity and sharpness of the viewed image, which is fundamental for conducting accurate microscopic observations.

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Most popular questions from this chapter

The focal length of a relaxed human eye is approximately \(1.7 \mathrm{cm}\). When we focus our eyes on a close-up object, we can change the refractive power of the eye by about 16 diopters. (a) Does the refractive power of our eyes increase or decrease by 16 diopters when we focus closely? Explain. (b) Calculate the focal length of the eye when we focus closely.

A photograph is properly exposed when the aperture is set to \(f / 8\) and the shutter speed is \(125 .\) Find the approximate shutter speed needed to give the same exposure if the aperture is changed to \(f / 2.4\)

Two thin lenses have refractive powers of +4.00 diopters and -2.35 diopters. What is the refractive power of the two if they are placed in contact? (Note that these are the same two lenses described in the previous problem.)

Because a concave lens cannot form a real image of a real object, it is difficult to measure its focal length precisely. One method uses a second, convex, lens to produce a virtual object for the concave lens. Under the proper conditions, the concave lens will form a real image of the virtual object! \(A\) student conducting a laboratory project on concave lenses makes the following observations: When a lamp is placed \(42.0 \mathrm{cm}\) to the left of a particular convex lens, a real (inverted) image is formed \(37.5 \mathrm{cm}\) to the right of the lens. The lamp and convex lens are kept in place while a concave lens is mounted \(15.0 \mathrm{cm}\) to the right of the convex lens. A real image of the lamp is now formed \(35.0 \mathrm{cm}\) to the right of the concave lens. What is the focal length of each lens?

A person with a near-point distance of \(25 \mathrm{cm}\) finds that a magnifying glass gives an angular magnification that is 1.5 times larger when the image of the magnifier is at the near point than when the image is at infinity. What is the focal length of the magnifying glass?

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