Chapter 25: Problem 62
Find the rms electric and magnetic fields at a point \(2.50 \mathrm{m}\) from a lightbulb that radiates \(75.0 \mathrm{W}\) of light uniformly in all directions.
Short Answer
Expert verified
The rms electric field is approximately 8.49 V/m, and the rms magnetic field is 2.83 × 10^{-8} T.
Step by step solution
01
Calculate Power per Unit Area
The power radiated by the lightbulb is uniformly distributed over a spherical surface with a radius equal to the distance from the bulb, 2.50 m. The surface area of a sphere is given by \(A = 4 \pi r^2\). Using this formula, the area \(A\) is:\[A = 4 \pi (2.50)^2 \approx 78.54 \, \text{m}^2\]The power per unit area (intensity \(I\)) is then:\[I = \frac{75.0}{78.54} \approx 0.955 \, \text{W/m}^2\]
02
Find RMS Electric Field
The intensity of the lightwave is related to the root mean square (rms) electric field \(E_{\text{rms}}\) by the equation:\[I = \frac{c \varepsilon_0}{2} E_{\text{rms}}^2\]where \(c\) is the speed of light (approximately \(3.00 \times 10^8 \, \text{m/s}\)) and \(\varepsilon_0\) is the vacuum permittivity (approximately \(8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2\)).Rearranging for \(E_{\text{rms}}\):\[E_{\text{rms}} = \sqrt{\frac{2I}{c \varepsilon_0}} = \sqrt{\frac{2 \times 0.955}{3.00 \times 10^8 \times 8.85 \times 10^{-12}}} \approx 8.49 \, \text{V/m}\]
03
Find RMS Magnetic Field
The rms values of the electric and magnetic fields in an electromagnetic wave are related by:\[B_{\text{rms}} = \frac{E_{\text{rms}}}{c}\]Using the rms electric field previously calculated:\[B_{\text{rms}} = \frac{8.49}{3.00 \times 10^8} \approx 2.83 \times 10^{-8} \, \text{T}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
RMS Electric Field
The Root Mean Square (RMS) Electric Field is a way to express the effective strength of an electric field in a wave, especially useful in alternating fields like light. It's like finding the average force with which the field pushes over one cycle of a waveform. Understanding the RMS value is crucial, as it represents more than just the peak value; it captures the consistent force exerted by the field.
The formula relating the intensity of light to the RMS electric field is given by:
The formula relating the intensity of light to the RMS electric field is given by:
- \[I = \frac{c \varepsilon_0}{2} E_{\text{rms}}^2\]
- Where:
- \(I\) is the intensity of light,
- \(c\) is the speed of light, approximately \(3.00 \times 10^8 \, \text{m/s}\),
- \(\varepsilon_0\) is the vacuum permittivity, approximately \(8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2\).
- \[E_{\text{rms}} = \sqrt{\frac{2I}{c \varepsilon_0}}\]
RMS Magnetic Field
Root Mean Square (RMS) Magnetic Field is a concept that helps us understand a constant effective magnetic field value in alternating fields. Much like the electric field, the magnetic field oscillates in electromagnetic waves such as light. Calculating the RMS value gives us a better understanding of the effective intensity of the magnetic field.
The relationship between the electric RMS field and the magnetic RMS field is direct and given by:
The relationship between the electric RMS field and the magnetic RMS field is direct and given by:
- \[B_{\text{rms}} = \frac{E_{\text{rms}}}{c}\]
- With \(E_{\text{rms}}\) representing the RMS Electric Field, and \(c\) being the speed of light.
Intensity of Light
The intensity of light is a measure of the energy a light wave carries per unit area in a perpendicular direction to the wave’s travel. It is pivotal in understanding how much "light power" is reaching a particular destination, like a specific spot in a room.
In the context of a point source like a lightbulb, the light spreads out uniformly in all directions. This spread can be imagined as a growing sphere; thus, the intensity decreases as distance from the source increases.
The formula for intensity \(I\) from a point source is:
In the context of a point source like a lightbulb, the light spreads out uniformly in all directions. This spread can be imagined as a growing sphere; thus, the intensity decreases as distance from the source increases.
The formula for intensity \(I\) from a point source is:
- \[I = \frac{P}{A}\]
- Where:
- \(P\) is the total power output of the source,
- \(A\) is the surface area of the sphere over which the light is spread.
- The surface area \(A\) is calculated using \(A = 4 \pi r^2\), where \(r\) is the radius from the light source.