/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 \- An rms voltage of \(120 \math... [FREE SOLUTION] | 91Ó°ÊÓ

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\- An rms voltage of \(120 \mathrm{V}\) produces a maximum current of \(2.1 \mathrm{A}\) in a certain resistor. Find the resistance of this resistor.

Short Answer

Expert verified
The resistance is approximately 80.86 ohms.

Step by step solution

01

Identify Given Values

We are given an RMS voltage of \(V_{rms} = 120 \text{ V}\) and a peak current (maximum current) of \(I_{max} = 2.1 \text{ A}\).
02

Relate Imax and Irms

To find the RMS current \(I_{rms}\), we use the relation between peak current and RMS current: \( I_{rms} = \frac{I_{max}}{\sqrt{2}} \).
03

Calculate Irms

Substitute the values into the formula: \( I_{rms} = \frac{2.1}{\sqrt{2}} \approx 1.484 \text{ A}\).
04

Use Ohm's Law for RMS Values

Ohm's Law relates the RMS voltage and RMS current to resistance: \( V_{rms} = I_{rms} \cdot R \). Rearrange it to solve for resistance: \( R = \frac{V_{rms}}{I_{rms}} \).
05

Calculate Resistance

Substitute the given RMS voltage and calculated RMS current into the formula: \( R = \frac{120}{1.484} \approx 80.86 \text{ ohms}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

RMS voltage
RMS, or Root Mean Square voltage, is an important concept when dealing with alternating current (AC) circuits. In an AC circuit, the voltage constantly changes polarity and magnitude over time. The RMS value provides a way to quantify this varying voltage by converting it into an equivalent steady-state direct current (DC) value. This helps in analyzing and comparing AC circuits effectively.

To calculate RMS voltage, you consider it as the equivalent DC voltage that delivers the same power to a resistor as the given AC voltage.- RMS voltage is often used in everyday applications, such as household outlets, which usually is around 120 V or 230 V (depending on the country's standard).
- It is key for ensuring devices receive adequate power while preventing overheating or damage.

In our exercise, we have an RMS voltage of \(120 \text{ V}\), which acts similarly to a 120 V DC in terms of power delivered to the resistor.
peak current
Peak current, denoted as \(I_{max}\), is the maximum instantaneous current value in an AC circuit during one cycle. It is the highest point reached on the sine wave of the AC current and often plays a crucial role in designing circuits and choosing appropriate components to handle extreme cases.

To calculate the relationship between RMS current \(I_{rms}\) and peak current \(I_{max}\), we use the formula:
  • \( I_{rms} = \frac{I_{max}}{\sqrt{2}} \)

This formula allows you to translate the peak current into a form that's more useful for understanding average power consumption and preventing circuit damage.
- Knowing the peak current helps to select components like resistors or fuses that can withstand instant surges without failure.

In the context of our problem, the peak current of \(2.1 \text{ A}\) has been used to find the RMS current, which was calculated as approximately \(1.484 \text{ A}\).
resistance calculation
When dealing with AC circuits, once you have the RMS values of both voltage and current, calculating resistance is straightforward using Ohm’s Law. Resistance is a measure of how much a component, like a resistor, opposes the flow of current.

Ohm’s Law can be written for RMS values as:
  • \( V_{rms} = I_{rms} \cdot R \)
  • Solving for resistance gives \( R = \frac{V_{rms}}{I_{rms}} \)

This equation tells us that resistance is the ratio of RMS voltage to RMS current. It is essential in planning how much energy a resistor will dissipate as heat during standard operation, allowing for the correct rating and size of resistors to be chosen.

In our exercise, by substituting the calculated RMS current \(\left(1.484 \text{ A}\right)\) and given RMS voltage \(120 \text{ V}\) into this formula, we find the resistance to be approximately \(80.86 \text{ ohms}\). Understanding resistance in this way helps in designing safe and efficient electrical circuits.

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Most popular questions from this chapter

An \(R L C\) circuit with \(R=25.0 \Omega, L=325 \mathrm{mH},\) and \(C=\) \(45.2 \mu \mathrm{F}\) is connected to an ac generator with an \(\mathrm{rms}\) voltage of 24 V. Determine the average power delivered to this circuit when the frequency of the generator is (a) equal to the resonance frequency, (b) twice the resonance frequency, and (c) half the resonance frequency.

CE Predict/Explain When a long copper wire of finite resistance is connected to an ac generator, as shown in Figure \(24-28\) (a). a certain amount of current flows through the wire. The wire is now wound into a coil of many loops and reconnected to the generator, as indicated in Figure \(24-28\) (b). (a) Is the current supplied to the coil greater than, less than, or the same as the current supplied to the uncoiled wire? (b) Choose the best explanation from among the following: I. More current flows in the circuit because the coiled wire is an inductor, and inductors tend to keep the current flowing in an ac circuit. II. The current supplied to the circuit is the same because the wire is the same. Simply wrapping the wire in a coil changes nothing. III. Less current is supplied to the circuit because the coiled wire acts as an inductor, which increases the impedance of the circuit.

\(\cdot\) An \(R L C\) circuit has a capacitance of \(0.29 \mu F\), (a) What inductance will produce a resonance frequency of \(95 \mathrm{MHz} ?\) (b) It is desired that the impedance at resonance be one-fifth the impedance at \(11 \mathrm{kHz}\). What value of \(R\) should be used to obtain this result?

IP Tuning a Radio A radio tuning circuit contains an RLC circuit with \(R=5.0 \Omega\) and \(L=2.8 \mu \mathrm{H.}\) (a) What capacitance is needed to produce a resonance frequency of \(85 \mathrm{MHz}\) ? (b) If the capacitance is increased above the value found in part (a), will the impedance increase, decrease, or stay the same? Explain. (c) Find the impedance of the circuit at reso- nance. (d) Find the impedance of the circuit when the capacitance is \(1 \%\) higher than the value found in part (a).

\- \(\mathrm{A} 115-\Omega\) resistor, a \(67.6-\mathrm{mH}\) inductor, and a \(189-\mu \mathrm{F}\) capacitor are connected in series to an ac generator. (a) At what frequency will the current in the circuit be a maximum? (b) At what frequency will the impedance of the circuit be a minimum?

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