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A 0.45-T magnetic field is perpendicular to a circular loop of wire with 53 turns and a radius of \(15 \mathrm{cm} .\) If the magnetic field is reduced to zero in \(0.12 \mathrm{s}\), what is the magnitude of the induced emf?

Short Answer

Expert verified
The magnitude of the induced emf is approximately 14.06 V.

Step by step solution

01

Understanding the Formula

The formula to calculate the induced emf (electromotive force) in a coil is given by Faraday's law of electromagnetic induction: \[ \text{emf}_{ ext{induced}} = -N \frac{\Delta \Phi}{\Delta t} \] where \( N \) is the number of turns, \( \Delta \Phi \) is the change in magnetic flux, and \( \Delta t \) is the time over which the change occurs.
02

Calculate Initial Magnetic Flux

The initial magnetic flux, \( \Phi_i \), through one loop can be calculated using the formula: \[ \Phi_i = B \times A \] where \( B = 0.45 \text{ T} \) is the magnetic field, and \( A \) is the area of the loop. The area \( A \) is calculated using \( A = \pi r^2 \) where \( r = 0.15 \text{ m} \). Thus, \[ A = \pi \times (0.15)^2 = 0.0706858 \text{ m}^2 \] \[ \Phi_i = 0.45 \times 0.0706858 = 0.0318086 \text{ Wb} \] (Weber is the unit of magnetic flux).
03

Calculate Change in Magnetic Flux

The magnetic field is reduced to zero, which leads to a final magnetic flux \( \Phi_f = 0 \text{ Wb} \). Thus, the change in magnetic flux \( \Delta \Phi \) is: \[ \Delta \Phi = \Phi_f - \Phi_i = 0 - 0.0318086 = -0.0318086 \text{ Wb} \]
04

Compute the Induced EMF

Substitute the known values into the formula for induced emf: \[ \text{emf}_{\text{induced}} = -N \frac{\Delta \Phi}{\Delta t} = -53 \left( \frac{-0.0318086}{0.12} \right) \approx -53 \times (-0.265071) \approx 14.06 \text{ V} \] The negative signs indicate direction, but we are concerned with the magnitude. So, the induced emf is approximately 14.06 V.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law of electromagnetic induction is fundamental in understanding how changing magnetic fields can produce electric currents. The law states that the induced electromotive force (emf) in any closed circuit is equal to the negative of the rate of change of the magnetic flux through the circuit. This means that if you have a coil in a magnetic field, and that magnetic field changes, an emf is induced, or generated, in the coil.
This law is represented as \( \text{emf}_{\text{induced}} = -N \frac{\Delta \Phi}{\Delta t} \), where:
  • \( N \) is the number of turns in the coil,
  • \( \Delta \Phi \) is the change in magnetic flux, and
  • \( \Delta t \) is the time it takes for the change to occur.
The negative sign indicates that the direction of the induced emf opposes the change in magnetic flux, according to Lenz's Law. This principle is key in many electrical devices, such as transformers and electric generators.
Magnetic Flux
Magnetic flux is a measure of the total magnetic field passing through a given area. It is an important concept when discussing electromagnetic induction, as it helps quantify how much magnetic field interacts with a coil or loop. The formula for magnetic flux \( \Phi \) is given by:
  • \( \Phi = B \times A \times \cos(\theta) \)
where:
  • \( B \) is the magnetic field strength,
  • \( A \) is the area the magnetic field passes through, and
  • \( \theta \) is the angle between the magnetic field and the normal to the surface area.
In the given exercise, the magnetic field is perpendicular to the loop, which means \( \theta = 0 \) and \( \cos(\theta) = 1 \). This simplifies the calculation to \( \Phi = B \times A \). Understanding magnetic flux helps in calculating the induced emf when changes occur in the field or orientation of a loop.
Induced EMF
Induced electromagnetic force (emf) is the voltage generated within a conductor due to a changing magnetic field. It is central to Faraday's Law and is calculated from the rate of change of magnetic flux over the time period considered. In our exercise, the coil with multiple turns is subjected to an initial magnetic flux, which is then removed, causing a change in flux.

The induced emf can be determined using the formula:
\( \text{emf}_{\text{induced}} = -N \frac{\Delta \Phi}{\Delta t} \). Here:
  • \( N \) is the number of turns, translating to multiple loops experiencing the same flux change,
  • \( \Delta \Phi \) is the change in flux, calculated as the difference between initial and final flux, and
  • \( \Delta t \) is the time taken for this change.
Understanding how these components work together helps to find the induced emf in systems such as electric circuitry and magnetic systems.
Coil
A coil, in the context of electromagnetic induction, refers to a wire wound in a helical shape often used to create a magnetic field or to detect one. Coils are critical in the creation and detection of induced emf.
They can significantly magnify the effects of changes in magnetic flux due to their multiple loops or turns.
In the exercise given, 53 turns of wire in the coil enhanced the induced voltage when the magnetic field was altered. This means that each loop in the coil collected the change in magnetic flux, leading to a greater overall emf. The number of turns (N) directly affects the magnitude of the induced emf. As the number of turns increases, the total emf produced also magnifies proportionally. Coils are essential in devices like transformers, inductors, and even motors, as they allow efficient interaction between magnetic fields and electricity.
Magnetic Field
A magnetic field is a vector field surrounding magnets and electric currents, representing the force exerted by a magnet. It is described by the magnetic field strength (B) and can be visualized with field lines that show the direction and strength of the field.
In contexts like that of electromagnetic induction, a change in the magnetic field intensity near a conductive coil can induce an emf in the coil.
The strength of the magnetic field and its orientation relative to the coil play crucial roles in determining the magnitude of the induced emf. The exercise describes a uniform magnetic field initially at \(0.45 \text{ T}\) perpendicular to the coil. When this field is diminished to zero, it causes a change in magnetic flux, which is necessary for the induction of emf according to Faraday's Law. Understanding how magnetic fields interact with coils is crucial in electricity generation and electromagnetic applications.

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Most popular questions from this chapter

Consider a rectangular loop of wire \(5.8 \mathrm{cm}\) by \(8.2 \mathrm{cm}\) in a uniform magnetic field of magnitude 1.3 T. The loop is rotated from a position of zero magnetic flux to a position of maximum flux in 21 ms. What is the average induced emf in the loop?

IP A solenoid has \(N\) turns of area \(A\) distributed uniformly along its length, \(\ell\). When the current in this solenoid increases at the rate of \(2.0 \mathrm{A} / \mathrm{s},\) an induced emf of \(75 \mathrm{mV}\) is observed. (a) What is the inductance of this solenoid? (b) Suppose the spacing between coils is doubled. The result is a solenoid that is twice as long but with the same area and number of turns. Will the induced emf in this new solenoid be greater than, less than, or equal to \(75 \mathrm{mV}\) when the current changes at the rate of 2.0 A/s? Explain. (c) Calculate the induced emf for part (b).

How many turns should a solenoid of cross-sectional area \(0.035 \mathrm{m}^{2}\) and length \(0.22 \mathrm{m}\) have if its inductance is to be \(45 \mathrm{mH} ?\)

A car drives onto a loop detector and increases the downward component of the magnetic field within the loop from \(1.2 \times 10^{-5} \mathrm{T}\) to \(2.6 \times 10^{-5} \mathrm{T}\) in \(0.38 \mathrm{s} .\) What is the induced emf in the detector if it is circular, has a radius of \(0.67 \mathrm{m},\) and consists of four loops of wire? A. \(0.66 \times 10^{-4} \mathrm{V}\) B. \(1.5 \times 10^{-4} \mathrm{V}\) C. \(2.1 \times 10^{-4} \mathrm{V}\) D. \(6.2 \times 10^{-4} \mathrm{V}\)

A single-turn square loop of side \(L\) is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1250 turns per meter and a diameter of \(6.00 \mathrm{cm},\) and carries a current of \(2.50 \mathrm{A}\). Find the magnetic flux through the loop when (b) \(L=6.00 \mathrm{cm},\) and (c) \(L=12.0 \mathrm{cm}\) (a) \(L=3.00 \mathrm{cm}.\)

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