Chapter 23: Problem 46
A generator is designed to produce a maximum emf of \(170 \mathrm{V}\) while rotating with an angular speed of 3600 rpm. Each coil of the generator has an area of \(0.016 \mathrm{m}^{2}\). If the magnetic field used in the generator has a magnitude of \(0.050 \mathrm{T}\), how many turns of wire are needed?
Short Answer
Step by step solution
Understand the formula for maximum emf
Convert angular speed to radians per second
Rearrange the emf formula to solve for N
Substitute known values into the equation
Calculate the number of turns N
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Generator Design
- The area of each coil, which affects the amount of magnetic flux that passes through it.
- The strength of the magnetic field, which interacts with the coil.
- The speed of rotation, which impacts how rapidly the magnetic environment of the coil changes.
- The number of turns of wire in the coil, which influences the total emf generated.
Angular Speed
The conversion involves multiplying the speed in rpm by \( \frac{2 \pi}{60} \), giving us 377 rad/s in this case. This conversion helps us apply the formula for maximum emf efficiently.