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How much work is required to bring three protons, initially infinitely far apart, to a configuration where each proton is \(1.5 \times 10^{-15} \mathrm{m}\) from the other two? (This is a typical separation for protons in a nucleus.)

Short Answer

Expert verified
The work required is approximately \(4.59 \times 10^{-13} \text{J}\).

Step by step solution

01

Understand the Concept of Work in Electrostatics

In electrostatics, the work required to bring a charge from infinity to a point in space is equal to the change in electric potential energy. For multiple charges, this involves summing the potential energy contributions for each pair of charges brought together.
02

Calculate the Potential Energy of a Pair of Protons

The potential energy between two point charges is given by the formula:\[ U = \frac{k \cdot q_1 \cdot q_2}{r} \]where \( k = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges (each proton has a charge of \(1.6 \times 10^{-19} \, \text{C}\)), and \( r = 1.5 \times 10^{-15} \, \text{m} \) is the separation distance.
03

Compute the Energy for One Proton Pair

Substituting the values into the formula, the potential energy for one pair of protons is calculated as:\[ U = \frac{8.99 \times 10^9 \times (1.6 \times 10^{-19})^2}{1.5 \times 10^{-15}} \approx 1.53 \times 10^{-13} \, \text{J} \]
04

Calculate Total Work for All Three Protons

Since we have three protons, we must account for three pairs: proton 1 with proton 2, proton 2 with proton 3, and proton 3 with proton 1. Thus, the total work required is three times the energy of one pair:\[ W = 3 \times 1.53 \times 10^{-13} \approx 4.59 \times 10^{-13} \, \text{J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Potential Energy
Electric potential energy is the energy a charge possesses due to its position in an electric field. In simpler terms, imagine you have a set of charged particles. The electric potential energy is like the energy stored because of how these particles are arranged. If they are very far from each other, the energy is low. But when brought close, especially at a specific distance, the energy can become significantly higher. This is because charges interact with each other. Opposite charges attract while like charges repel each other.
In the context of the exercise, each proton is a charge, and we're interested in the energy needed to position them at a certain distance. When calculating electric potential energy, we use the formula:
  • \[ U = \frac{k \cdot q_1 \cdot q_2}{r} \]
where:
  • \( k \) is Coulomb's constant,
  • \( q_1 \) and \( q_2 \) are the charges, and
  • \( r \) is the separation distance between the charges.
In the case of three protons, we have multiple pairwise contributions to consider and sum up. This cumulative effect gives us the total work done to achieve the desired configuration.
Coulomb's Constant
Coulomb's constant is a crucial part of understanding electrostatic forces and potential energy between charges. It is a proportionality factor in Coulomb's law, which describes the force of interaction between two point charges. The standard value of Coulomb's constant is:
  • \( k = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \)
This constant allows us to calculate how strongly two charges will push or pull each other when they are at a given distance. It's derived from fundamental properties of electric fields and relates the force experienced by charges to their distance and magnitudes.
In electrostatics problems like the one we are discussing, Coulomb's constant is essential for calculating electrostatic potential energy. Without it, we wouldn't be able to quantify the amount of work required to assemble a system of charges in space. Coulomb's constant essentially bridges the gap between abstract charge interactions and measurable forces and energies.
Work in Physics
In physics, work is a measure of energy transfer. Specifically, it is the energy required to move a force over a distance. In the context of electrostatics, the concept of work relates to moving charges within an electric field, which changes their electric potential energy.
When working with electrostatics, the work involved is quite specific: it's the amount of energy needed to assemble a group of charges from infinity to a certain configuration. It's important to note that work only happens when there is a change involved, such as moving the charges closer together in this scenario. The equation used for work from potential energy is:
  • \( W = \Delta U \)
where \( \Delta U \) represents the change in potential energy. In our exercise, we calculated the total potential energy required to bring three protons together, at specific distances, resulting in the total work done in the system. The work here reflects how energy is transformed and stored when moving these protons into a compact formation like that found in atomic nuclei.

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Most popular questions from this chapter

Predict/Explain A positive charge is moved from one location on an equipotential to another point on the same equipotential. (a) Is the work done on the charge positive, negative, or zero? (b) Choose the best explanation from among the following: I. The electric field is perpendicular to an equipotential, therefore the work done in moving along an equipotential is zero. II. Because the charge is positive the work done on it is also positive. III. It takes negative work to keep the positive charge from accelerating as it moves along the equipotential.

A spark plug in a car has electrodes separated by a gap of 0.025 in. To create a spark and ignite the air-fuel mixture in the engine, an electric field of \(3.0 \times 10^{6} \mathrm{V} / \mathrm{m}\) is required in the gap. (a) What potential difference must be applied to the spark plug to initiate a spark? (b) If the separation between electrodes is increased, does the required potential difference increase, decrease, or stay the same? Explain. (c) Find the potential difference for a separation of 0.050 in.

A charge of \(3.05 \mu C\) is held fixed at the origin. A second charge of \(3.05 \mu C\) is released from rest at the position \((1.25 \mathrm{m},\) \(0.570 \mathrm{m})\). (a) If the mass of the second charge is \(2.16 \mathrm{g}\), what is its speed when it moves infinitely far from the origin? (b) At what distance from the origin does the second charge attain half the speed it will have at infinity?

The electric potential a distance \(r\) from a point charge \(q\) is \(155 \mathrm{V}\), and the magnitude of the electric field is \(2240 \mathrm{N} / \mathrm{C}\). Find the values of \(q\) and \(r.\)

A uniform electric field of magnitude \(4.1 \times 10^{5} \mathrm{N} / \mathrm{C}\) points in the positive \(x\) direction. Find the change in electric potential energy of a \(4.5-\mu C\) charge as it moves from the origin to the points (a) \((0,6.0 \mathrm{m}) ;\) (b) \((6.0 \mathrm{m}, 0) ;\) and (c) \((6.0 \mathrm{m}, 6.0 \mathrm{m})\).

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