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In the Bohr model of the hydrogen atom, a proton and an electron are separated by a constant distance \(r .\) (a) Would the electric potential energy of the system increase, decrease, or stay the same if the electron is replaced with a proton? Explain. (b) Suppose, instead, that the proton is replaced with an electron. Would the electric potential energy of the system increase, decrease, or stay the same? Explain.

Short Answer

Expert verified
In both cases, the electric potential energy increases.

Step by step solution

01

Understanding the Bohr Model

In the Bohr model of the hydrogen atom, a proton and an electron exert an electric force on each other. The proton is positively charged, and the electron is negatively charged, leading to an attractive force between the two particles.
02

Analyzing Electron Replacement with Proton

If the electron is replaced with a proton, both particles in the system will now have positive charges. Because like charges repel each other, the electric potential energy of the system would increase, as positive work would be required to bring the two protons closer from an infinite separation to the distance \( r \).
03

Analyzing Proton Replacement with Electron

If the proton is replaced with an electron, the system now consists of two electrons. Both carry negative charges, creating a repulsive electric force between them. Again, bringing them to distance \( r \) requires work, and so the electric potential energy of the system would increase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Potential Energy
Electric potential energy is a type of energy that occurs due to the position of charged particles relative to one another. It is determined by the charges' magnitudes and the distance between them.
In atomic physics, like in the Bohr model of atoms, the electric potential energy is affected by interactions between subatomic particles, such as protons and electrons. If particles have like charges, the potential energy increases because work must be done to bring them close. Opposite charges, on the other hand, attract each other, which decreases potential energy as they naturally move together.
For example, in a hydrogen atom, the proton and electron interaction leads to a stable state where potential energy is minimized due to their opposite charges. Changes in this balance, such as replacing an electron with another proton, significantly impacts this potential energy.
Proton-Electron Interaction
In the Bohr model, a proton-electron interaction forms the basis of atomic structure for hydrogen.
This model depicts the atom as a tiny solar system where one proton (positive charge) exerts an electrostatic force of attraction upon an orbiting electron (negative charge).
This attractive force is crucial as it holds the electron in orbit, creating stability. The magnitude of the force depends on:
  • The charge of the proton and electron, which are equal but opposite.
  • The distance between them, represented by the variable \( r \).
Such interaction minimizes the electric potential energy of the atom, allowing it to exist in a stable, low-energy state. Alterations like replacing an electron with another proton disrupt this balance, leading to increased repulsion and potential energy.
Charge Repulsion
Charge repulsion refers to the phenomenon where like charges, either both positive or both negative, push away from each other.
This is due to the electric force that does not want them to occupy the same space. For instance, should an atom's electron be swapped with a proton, as described in exercise step 2, the system now has two positive charges.
Since these charges repel, potential energy increases because additional energy is needed to keep them together. Another scenario is in exercise step 3, where replacing a proton with an electron results in two negative charges. Again, repulsion occurs, requiring more energy to maintain their proximity.
In both cases, work must be done against the natural repulsive force, fundamentally affecting electric potential energy in the system.
Charge Attraction
Charge attraction is integral to understanding atomic structure, especially within models like Bohr's.
Unlike repulsion, attraction happens between opposite charges: positive protons and negative electrons. This attraction acts as a balancing mechanism and is the reason why atoms maintain a stable form, as described in the hydrogen atom model.
Such forces are important because they counterbalance any kinetic energy the electron may have, allowing it to orbit the proton. If you replace a particle to disturb this attraction, like swapping an electron with a proton, the system destabilizes.
Overall, the natural state of oppositely charged particles is one of minimized potential energy, contrary to what occurs when like charges form a repulsed state.

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Most popular questions from this chapter

A parallel-plate capacitor filled with air has plates of area \(0.0066 \mathrm{m}^{2}\) and a separation of \(0.45 \mathrm{mm} .\) (a) Find the magnitude of the charge on each plate when the capacitor is connected to a 12-V battery. (b) Will your answer to part (a) increase, decrease, or stay the same if the separation between the plates is increased? Explain. (c) Calculate the magnitude of the charge on the plates if the separation is \(0.90 \mathrm{mm}\).

To operate a given flash lamp requires a charge of \(32 \mu C .\) What capacitance is needed to store this much charge in a capacitor with a potential difference between its plates of \(9.0 \mathrm{V} ?\)

A charge of \(24.5 \mu \mathrm{C}\) is located at \((4.40 \mathrm{m}, 6.22 \mathrm{m}),\) and a charge of \(-11.2 \mu \mathrm{C}\) is located at \((-4.50 \mathrm{m}, 6.75 \mathrm{m})\). What charge must be located at \((2.23 \mathrm{m},-3.31 \mathrm{m})\) if the electric potential is to be zero at the origin?

Two point charges are on the \(x\) axis. Charge 1 is \(+q\) and is located at \(x=-1.0 \mathrm{m} ;\) charge 2 is \(-2 q\) and is located at \(x=1.0 \mathrm{m}\) Make sketches of the equipotential surfaces for this system (a) out to a distance of about \(2.0 \mathrm{m}\) from the origin and (b) far from the origin. In each case, indicate the direction in which the potential increases.

An electron is released from rest in a region of space with a nonzero electric field. (a) As the electron moves, does the electric potential energy of the system increase, decrease, or stay the same? (b) Choose the best explanation from among the following: I. Because the electron has a negative charge its electric potential energy doesn't decrease, as one might expect, but in creases instead. II. As the electron begins to move, its kinetic energy increases. The increase in kinetic energy is equal to the decrease in the electric potential energy of the system. III. The electron will move perpendicular to the electric field, and hence its electric potential energy will remain the same.

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