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Defibrillator An automatic external defibrillator (AED) delivers 125 J of energy at a voltage of 1050 V. What is the capacitance of this device?

Short Answer

Expert verified
The capacitance of the AED is 226.8 microfarads.

Step by step solution

01

Understand the Formula

The relationship between energy (E) stored in a capacitor, the capacitance (C), and the voltage (V) is given by the formula: \[ E = \frac{1}{2} C V^2 \]. In this equation, E is the energy in joules, C is the capacitance in farads, and V is the voltage in volts.
02

Solve for Capacitance

We need to find the capacitance, so we rearrange the formula to solve for \( C \): \[ C = \frac{2E}{V^2} \].
03

Substitute Known Values

Substitute the known values into the formula: \( E = 125 \) J and \( V = 1050 \) V. Thus, \[ C = \frac{2 \times 125}{1050^2} \].
04

Calculate the Capacitance

Perform the calculation: \[ C = \frac{250}{1102500} = 0.0002268 \] farads. This can also be expressed as 226.8 microfarads.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy stored in a capacitor
Capacitors are important components in many electrical devices, and they work by storing electrical energy. The energy stored in a capacitor is governed by the formula: \[ E = \frac{1}{2} C V^2 \] where \( E \) is the energy measured in joules, \( C \) is the capacitance in farads, and \( V \) is the voltage across the capacitor in volts. This formula shows how the energy is directly proportional to both the capacitance and the square of the voltage.
Understanding this relationship is crucial because it helps predict how much energy a capacitor can store and release. For example, in devices like an Automatic External Defibrillator (AED), having precise control over energy storage allows for critical life-saving functions.
Voltage
Voltage, often described as electric potential difference, is a measure of the energy per unit charge. Simply put, it's the force that pushes electric charges through a circuit.
In the realm of capacitors, voltage plays a key role in determining how much energy can be stored. According to the equation \( E = \frac{1}{2} C V^2 \), the energy stored increases quadratically with an increase in voltage.
  • This means that doubling the voltage results in four times the stored energy.
  • This quadratic relationship underscores the significant impact of voltage on a capacitor's performance.
Grasping the concept of voltage is fundamental when designing and using electrical circuits. Especially in high-voltage applications like those involving AEDs, ensuring proper voltage levels is vitally important.
Automatic external defibrillator (AED)
An Automatic External Defibrillator (AED) is a life-saving medical device used to help those experiencing sudden cardiac arrest. It works by delivering a calculated shock of energy to the heart to restore a normal heartbeat.
This energy is stored in a capacitor within the AED, which must be precisely calibrated in terms of energy and voltage to ensure effectiveness and safety.
AEDs are designed to be easy to use for laypeople and first responders, making them crucial tools in emergency medical situations.
  • The ability to deliver an exact amount of energy (like 125 J) at a specific voltage (1050 V in the example) relies heavily on the device's understanding of capacitance and stored energy.
  • This ensures the electrical impulse is both effective in restarting the heart and safe for the patient.
Farads
The farad is the unit of measurement for capacitance in the International System of Units (SI). Capacitance measures a capacitor's ability to store electrical charge.
The more farads a capacitor has, the more electrical energy it can store. When solving problems involving capacitors, such as determining how much energy an AED can store before delivering a shock, understanding the farad value is essential.
  • In practical applications, capacitors often have capacitances measured in microfarads (millionths of a farad), as full farads are very large values.
  • For instance, an AED with a capacitance of 0.0002268 farads is equivalent to 226.8 microfarads, a much more manageable number for design and calculation purposes.
Knowing the fundamentals of farads allows engineers and technicians to design capacitors accurately for different applications, ensuring devices operate efficiently and effectively.

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Most popular questions from this chapter

Point charges \(+4.1 \mu C\) and \(-2.2 \mu C\) are placed on the \(x\) axis at \((11 \mathrm{m}, 0)\) and \((-11 \mathrm{m}, 0),\) respectively. (a) Sketch the electric potential on the \(x\) axis for this system. (b) Your sketch should show one point on the \(x\) axis between the two charges where the potential vanishes. Is this point closer to the \(+4.1-\mu \mathrm{C}\) charge or closer to the \(-2.2-\mu \mathrm{C}\) charge? Explain. (c) Find the point referred to in part (b).

Points A and B have electric potentials of \(332 \mathrm{V}\) and \(149 \mathrm{V}\) respectively. When an electron released from rest at point \(\mathrm{A}\) arrives at point \(C\), its kinetic energy is \(K_{\Lambda}\). When the electron is released from rest at point B, however, its kinetic energy when it reaches point \(C\) is \(K_{B}=2 K_{A} .\) What are (a) the electric potential at point \(C\) and \((b)\) the kinetic energy \(K_{A} ?\)

The Electric Potential of the Earth The Earth has a vertical electric field with a magnitude of approximately \(100 \mathrm{V} / \mathrm{m}\) near its surface. What is the magnitude of the potential difference between a point on the ground and a point on the same level as the top of the Washington Monument \((555 \mathrm{ft}\) high \() ?\)

Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a \(0.250-\mathrm{kg}\) ball with zero net charge was dropped from rest at a height of \(1.00 \mathrm{m}\). The ball landed 0.552 s later. Next, the ball was given a net charge of \(7.75 \mu \mathrm{C}\) and dropped in the same way from the same height. This time the ball fell for 0.680 s before landing. What is the electric potential at a height of \(1.00 \mathrm{m}\) above the ground on this planet, given that the electric potential at ground level is zero? (Air resistance can be ignored.)

The Sodium Pump Living cells actively "pump" positive sodium ions \(\left(\mathrm{Na}^{7}\right)\) from inside the cell to outside the cell. This process is referred to as pumping because work must be done on the ions to move them from the negatively charged inner surface of the membrane to the positively charged outer surface. Given that the electric potential is \(0.070 \mathrm{V}\) higher outside the cell than inside the cell, and that the cell membrane is \(0.10 \mu \mathrm{m}\) thick (a) calculate the work that must be done (in joules) to move one sodium ion from inside the cell to outside. (b) If the thickness of the cell membrane is increased, does your answer to part (a) increase, decrease, or stay the same? Explain. (It is estimated that as much as \(20 \%\) of the energy we consume in a resting state is used in operating this "sodium pump.")

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