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The world's highest fountain of water is located, appropriately enough, in Fountain Hills, Arizona. The fountain rises to a height of \(560 \mathrm{ft}(5\) feet higher than the Washington Monument). (a) What is the initial speed of the water? (b) How long does it take for water to reach the top of the fountain?

Short Answer

Expert verified
(a) 189.32 ft/s; (b) 5.92 seconds.

Step by step solution

01

Understanding the Problem

We need to find the initial speed of the water and the time it takes for the water to reach a height of 560 feet. For these types of problems, we use the physics equations of motion under constant acceleration due to gravity.
02

Formula for Maximum Height

The formula for the maximum height of a projectile (ignoring air resistance) is given by \[ h = \frac{v_i^2}{2g} \] where \( h \) is the height, \( v_i \) is the initial velocity, and \( g \) is the acceleration due to gravity (\( g = 32 \, \text{ft/s}^2 \) on Earth).
03

Solving for Initial Speed

Rearrange the formula from Step 2 to solve for \( v_i \):\[ v_i = \sqrt{2gh} \]Substitute \( h = 560 \, \text{ft} \) and \( g = 32 \, \text{ft/s}^2 \) into the equation:\[ v_i = \sqrt{2 \times 32 \times 560} = \sqrt{35840} \approx 189.32 \, \text{ft/s} \]
04

Formula for Time to Reach Maximum Height

The time \( t \) it takes for a projectile to reach its maximum height can be found using the formula\[ t = \frac{v_i}{g} \]where \( v_i \) is the initial velocity and \( g \) is the acceleration due to gravity.
05

Solving for Time to Reach Top

Using the initial velocity calculated in Step 3,\[ t = \frac{189.32}{32} \approx 5.92 \, \text{seconds} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Velocity
Understanding the concept of initial velocity is crucial when dealing with projectile motion, such as a water fountain shooting upwards. Initial velocity, often represented as \( v_i \), refers to the speed of an object right as it begins its motion.
In our example, determining this initial velocity is key to figuring out how high the water can actually go. To find it, we use the formula for maximum height:
  • \( h = \frac{v_i^2}{2g} \)
This formula relates the height \( h \) to the initial velocity and gravity, which is consistent when an object is traveling under the influence of earth's gravitational pull.
By rearranging this formula to solve for \( v_i \), we arrive at:
  • \( v_i = \sqrt{2gh} \)
Substituting the values of \( g = 32 \text{ ft/s}^2 \) and \( h = 560 \text{ ft} \), we find the initial velocity to be roughly \( 189.32 \text{ ft/s} \). This involves squaring the initial velocity and dividing by twice the acceleration due to gravity, proving vital for understanding how quickly the water needs to be propelled to reach the height of the fountain.
Maximum Height
Maximum height is the pinnacle point of trajectory for projectile motion where the velocity of the object momentarily becomes zero before it starts to descend due to gravity. It's the highest point that the water reaches when it's shot up into the air from the fountain.
The key formula used to determine this height relies on understanding that all the initial kinetic energy (due to velocity) converts into potential energy at maximum height.
  • The equation is \( h = \frac{v_i^2}{2g} \).
In the fountain's case, the maximum height is given as 560 feet. This height reflects a balancing act between the initial speed of the water and the inevitable pull of gravity acting upon it, until the velocity drops to zero at the peak.
Understanding maximum height helps us appreciate the effects forces like velocity and gravity have on an object. It highlights the transitional phase from ascent to descent in projectile motion.
Gravity
Gravity, always on Earth, acts at a constant acceleration rate of \(32 \text{ ft/s}^2\) when calculations are in imperial units. It's the force that constantly pulls the water from the fountain back downwards.
In projectile motion, like the water jet in Fountain Hills, gravity is what governs the motion once the initial velocity has propelled it upwards.
  • It means any upward motion must contend with gravity's constant downward pull.
  • This results in a symmetrical path called a parabola, showcasing an object's upward and then downward movements.
While initial velocity helps start the journey, gravity ensures the water returns to Earth, affecting both the maximum height and the time taken to reach this height.
In calculations, gravity is often portrayed as a negative acceleration (in math equations) due to its role in decreasing the velocity as the object moves upward and increasing it during the descent. Understanding gravity's unyielding presence aids in predicting the arc and duration of any projectile's movement.

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Most popular questions from this chapter

It was a dark and stormy night, when suddenly you saw a flash of lightning. Three-and-a-half seconds later you heard the thunder. Given that the speed of sound in air is about \(340 \mathrm{m} / \mathrm{s}\) how far away was the lightning bolt?

Two bows shoot identical arrows with the same launch speed. To accomplish this, the string in bow 1 must be pulled back farther when shooting its arrow than the string in bow 2 . (a) Is the acceleration of the arrow shot by bow 1 greater than, less than, or equal to the acceleration of the arrow shot by bow \(2 ?\) (b) Choose the best explanation from among the following: The arrow in bow 2 accelerates for a greater time. II. Both arrows start from rest. III. The arrow in bow 1 accelerates for a greater time.

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IP You are driving through town at \(12.0 \mathrm{m} / \mathrm{s}\) when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at \(3.5 \mathrm{m} / \mathrm{s}^{2}\) (a) How far do you travel before stopping? (b) When you have traveled only half the distance in part \((a),\) is your speed \(6.0 \mathrm{m} / \mathrm{s},\) greater than \(6.0 \mathrm{m} / \mathrm{s},\) or less than \(6.0 \mathrm{m} / \mathrm{s}\) ? Support your answer with a calculation.

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