/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 In a physics lab, students measu... [FREE SOLUTION] | 91Ó°ÊÓ

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In a physics lab, students measure the time it takes a small cart to slide a distance of \(1.00 \mathrm{m}\) on a smooth track inclined at an angle \(\theta\) above the horizontal. Their results are given in the following table. $$ \begin{array}{llll} \hline \theta & 10.0^{\circ} & 20.0^{\circ} & 30.0^{\circ} \\ \text { time, } \mathrm{s} & 1.08 & 0.770 & 0.640 \\ \hline \end{array} $$

Short Answer

Expert verified
Time decreases as the incline angle increases, showing faster acceleration.

Step by step solution

01

Identify Given Values

We have the angle \(\theta\) and the time taken for each measurement. For \(\theta = 10.0^{\circ}\), time is 1.08 seconds; for \(\theta = 20.0^{\circ}\), time is 0.770 seconds; and for \(\theta = 30.0^{\circ}\), time is 0.640 seconds.
02

Understand the Problem

We need to understand how the angle \(\theta\) affects the time for the cart to travel 1 meter down the incline. Since the incline angle varies, the component of gravitational force along the incline changes, which in turn influences acceleration.
03

Calculate Acceleration on Incline

On an incline, the acceleration \(a\) of the cart due to gravity can be derived from \(a = g \sin(\theta)\), where \(g = 9.8 \, \text{m/s}^2\). Calculate \(a\) for each angle: \(\theta = 10.0^{\circ}\), \(\theta = 20.0^{\circ}\), and \(\theta = 30.0^{\circ}\).
04

Derive Expected Time Equation

Using the equation \(s = ut + \frac{1}{2} a t^2\) with initial velocity \(u = 0\) and \(s = 1.00\, \text{m}\), rearrange it to find \(t = \sqrt{\frac{2s}{a}}\). This allows calculating theoretical time based on acceleration.
05

Compare Calculated and Measured Times

For each angle, calculate the theoretical time using \(t = \sqrt{\frac{2s}{a}}\) and compare with the measured time. Look for trends or discrepancies to understand the effects of increasing angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Acceleration
Gravitational acceleration is a fundamental concept in physics that affects how objects move when influenced by the force of gravity. Its constant value is approximately 9.8 m/s² on Earth. On an inclined plane, like the one in the original exercise, the gravitational force can be divided into two components: one acting perpendicular to the plane and another parallel to it. The parallel component causes the object to slide down the incline. This component can be calculated using the formula:
  • \( a = g \sin(\theta) \)
where \( a \) is the acceleration along the plane, \( g \) is the gravitational acceleration, and \( \theta \) is the angle of the incline. The gravitational force pulling the cart down the slope increases with the angle. This means, as the angle increases, the component of gravity that acts to move the cart down the slope also increases, leading to faster acceleration.
Kinematic Equations
Kinematic equations describe motion in terms of displacement, velocity, acceleration, and time. In our context, they help us predict how long it takes for the cart to move down the inclined plane. These equations assume constant acceleration and no air resistance. To find the time required for the cart to slide 1 meter, the equation used is:
  • \( s = ut + \frac{1}{2} a t^2 \)
In this equation, \( s \) is the displacement (1 meter in this case), \( u \) is the initial velocity (0, since the cart starts from rest), \( a \) is the acceleration, and \( t \) is the time. Rearranging to solve for time, we find that:
  • \( t = \sqrt{\frac{2s}{a}} \)
This expression allows us to calculate the theoretical time it takes for the cart to travel the given distance based on its acceleration. By comparing this theoretical time with measured values, students can understand how acceleration affects travel time.
Experimental Physics
Experimental physics is all about conducting experiments to test theories or understand physical principles better. In this exercise, students are conducting an experiment to see how changing the angle of an inclined plane affects a cart's travel time. Key components of a successful experiment include:
  • Observation: noticing changes in measurement as the angle increases.
  • Hypothesis Testing: using the kinematic equations and gravitational principles to predict outcomes.
  • Data Collection: recording times accurately for different incline angles.
  • Analysis: comparing experimental data to theoretical predictions to identify any discrepancies.
Such experiments foster a deeper understanding of the concepts like gravitational acceleration and motion. They also highlight practical challenges such as measurement inaccuracies or external factors such as friction, which are not always included in theoretical models. By scrutinizing the differences between calculated and actual times, students develop critical thinking and problem-solving skills that are crucial in experimental physics.

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Most popular questions from this chapter

You drive your car in a straight line at \(15 \mathrm{m} / \mathrm{s}\) for \(10 \mathrm{kilometers},\) then at \(25 \mathrm{m} / \mathrm{s}\) for another \(10 \mathrm{kilome}^{-}\) ters. (a) Is your average speed for the entire trip more than, less than, or equal to \(20 \mathrm{m} / \mathrm{s} ?\) (b) Choose the best explanation from among the following: I. More time is spent at \(15 \mathrm{m} / \mathrm{s}\) than at \(25 \mathrm{m} / \mathrm{s}\). II. The average of \(15 \mathrm{m} / \mathrm{s}\) and \(25 \mathrm{m} / \mathrm{s}\) is \(20 \mathrm{m} / \mathrm{s}\) III. Less time is spent at \(15 \mathrm{m} / \mathrm{s}\) than at \(25 \mathrm{m} / \mathrm{s}\).

A popular entertainment at some carnivals is the blanket toss (see photo, p. 39 ). (a) If a person is thrown to a maximum height of \(28.0 \mathrm{ft}\) above the blanket, how long does she spend in the air? (b) Is the amount of time the person is above a height of \(14.0 \mathrm{ft}\) more than, less than, or equal to the amount of time the person is below a height of \(14.0 \mathrm{ft}\) ? Explain. (c) Verify your answer to part (b) with a calculation.

Coasting due west on your bicycle at \(8.4 \mathrm{m} / \mathrm{s}\), you encounter a sandy patch of road \(7.2 \mathrm{m}\) across. When you leave the sandy patch your speed has been reduced by \(2.0 \mathrm{m} / \mathrm{s}\) to \(6.4 \mathrm{m} / \mathrm{s} .\) (a) Assuming the sand causes a constant acceleration, what was the bicycle's acceleration in the sandy patch? Give both magnitude and direction. (b) How long did it take to cross the sandy patch? (c) Suppose you enter the sandy patch with a speed of only \(5.4 \mathrm{m} / \mathrm{s} .\) Is your final speed in this case \(3.4 \mathrm{m} / \mathrm{s}\) more than \(3.4 \mathrm{m} / \mathrm{s},\) or less than \(3.4 \mathrm{m} / \mathrm{s}\) ? Explain.

At the edge of a roof you drop ball A from rest, and then throw ball B downward with an initial velocity of \(v_{0}\). Is the increase in speed just before the balls land more for ball A, more for ball B, or the same for each ball?

A model rocket blasts off and moves upward with an acceleration of \(12 \mathrm{m} / \mathrm{s}^{2}\) until it reaches a height of \(26 \mathrm{m},\) at which point its engine shuts off and it continues its flight in free fall. (a) What is the maximum height attained by the rocket? (b) What is the speed of the rocket just before it hits the ground? (c) What is the total duration of the rocket's flight?

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