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A piston held at the temperature \(T\) contains a gas mixture with molecules of three different types; \(A, B,\) and \(C\). The corresponding molecular masses are \(m_{\mathrm{C}}>m_{\mathrm{B}}>m_{\mathrm{A}} .\) Rank these molecular types in order of increasing (a) average kinetic energy and (b) rms speed. Indicate ties where appropriate.

Short Answer

Expert verified
For average kinetic energy: Tie among A, B, and C. For rms speed: A > B > C.

Step by step solution

01

Understand Average Kinetic Energy

The average kinetic energy of a molecule in an ideal gas is given by the formula \( KE_{avg} = \frac{3}{2}kT \), where \( k \) is the Boltzmann constant and \( T \) is the absolute temperature. The formula shows that the average kinetic energy depends only on the temperature, not on the mass of the gas molecules. Therefore, since all molecules \( A, B, \) and \( C \) are at the same temperature \( T \), their average kinetic energies are equal.
02

Calculate RMS Speed

The root-mean-square (rms) speed of molecules in a gas is given by the formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( m \) is the molecular mass. Notice that the rms speed depends on both temperature \( T \) and the molecular mass \( m \). Since \( m_C > m_B > m_A \), it follows that \( v_{rms,A} > v_{rms,B} > v_{rms,C} \). Thus, lighter molecules move faster than heavier ones.
03

Rank Molecular Types by Average Kinetic Energy

Since all molecules are at the same temperature and average kinetic energy per molecule at a given temperature is the same, the ranking for average kinetic energy is: \( KE_{avg,A} = KE_{avg,B} = KE_{avg,C} \). They all tie for the same average kinetic energy.
04

Rank Molecular Types by RMS Speed

The rms speed is inversely related to the mass of the molecule, so lighter molecules have greater rms speeds. Therefore, we rank them as \( v_{rms,A} > v_{rms,B} > v_{rms,C} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Kinetic Energy
When we talk about the average kinetic energy of molecules in a gas, we're focusing on how much energy these molecules have due to their motion. In ideal gas conditions, the average kinetic energy is represented by the equation \[ KE_{avg} = \frac{3}{2}kT \]Here, \(k\) is known as the Boltzmann constant, and \(T\) is the absolute temperature measured in Kelvin. Notice how mass isn't in this equation? That's because the average kinetic energy is entirely dependent on the temperature, not on the molecular mass of the gas.

So, if you have different types of molecules like \(A, B,\) and \(C\) all at the same temperature \(T\), they'll all have the same average kinetic energy, regardless of their mass. Therefore, no matter what the sizes of the molecules are, they all "tie" when it comes to average kinetic energy. This is a unique property of gases that are in thermal equilibrium, meaning the kinetic energies depend solely on temperature.
RMS Speed
The concept of root-mean-square (rms) speed gives us an idea of how fast particles in a gas are moving on average. It differs from average kinetic energy because here, molecular mass plays a crucial role. The rms speed is given by the formula:\[ v_{rms} = \sqrt{\frac{3kT}{m}} \]This equation shows that while rms speed depends on temperature \(T\), it also inversely depends on the molecular mass \(m\).

In simpler terms, if you hold temperature constant, lighter molecules will travel faster than heavier ones. In the context of our types \(A, B,\) and \(C\), where \(m_C > m_B > m_A\), the speed ranking becomes \(v_{rms,A} > v_{rms,B} > v_{rms,C}\). This means the lightest molecules \(A\) will have the highest speed, while the heaviest, \(C\), will move slower. Thus, rms speed provides a significant insight into how mass differentiates molecular speeds.
Molecular Mass
Understanding molecular mass is key when studying the behavior of gas molecules. It refers to the mass of a given molecule and is expressed in atomic mass units (amu) or grams per mole depending on the context. For gases, molecular mass directly affects properties like rms speed, as seen in the rms speed formula.

In gases, lighter molecules not only move faster, as evidenced by rms speed, but these differences in speed come from variations in molecular mass. A lighter molecule, such as \(A\) with lower mass, outpaces a heavier molecule like \(C\). This is because the kinetic theory of gases has demonstrated that less massive molecules require less energy to achieve higher speeds.

Therefore, while molecular mass does not influence average kinetic energy (since it's determined by temperature), it plays a pivotal role in determining the speeds of different molecules. This lays the foundation for understanding many gas behaviors and is essential in comprehending gas dynamics fully.

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Most popular questions from this chapter

A cylindrical copper rod \(37 \mathrm{cm}\) long and \(7.5 \mathrm{cm}\) in diameter is placed upright on a hot plate held at a constant temperature of \(120^{\circ} \mathrm{C}\), as indicated in Figure \(\mathrm{T}-3 \mathrm{l}\). A small depression on top of the rod holds a \(25-g\) ice cube at an initial temperature of \(0.0^{\circ} \mathrm{C} .\) How long does it take for the ice cube to melt? Assume there is no heat loss through the vertical surface of the rod, and that the thermal conductivity of copper is \(390 \mathrm{W} /\left(\mathrm{m} \cdot \mathrm{C}^{\circ}\right)\).

The rms speed of \(\mathrm{O}_{2}\) is \(1550 \mathrm{m} / \mathrm{s}\) at a given temperature. (a) Is the rms speed of \(\mathrm{H}_{2} \mathrm{O}\) at this temperature greater than, less than, or equal to \(1550 \mathrm{m} / \mathrm{s}\) ? Explain. (b) Find the rms speed of \(\mathrm{H}_{2} \mathrm{O}\) at this temperature.

To stretch a relaxed biceps muscle \(2.5 \mathrm{cm}\) requires a force of \(25 \mathrm{N}\). Find the Young's modulus for the muscle tissue, assuming it to be a uniform cylinder of length \(0.24 \mathrm{m}\) and crosssectional area \(47 \mathrm{cm}^{2}\)

Three moles of oxygen gas (that is, 3.0 mol of \(\mathrm{O}_{2}\) ) are placed in a portable container with a volume of \(0.0035 \mathrm{m}^{3}\). If the temperature of the gas is \(295^{\circ} \mathrm{C}\), find \((a)\) the pressure of the gas and (b) the average kinetic energy of an oxygen molecule. (c) Suppose the volume of the gas is doubled, while the temperature and number of moles are held constant. By what factor do your answers to parts (a) and (b) change? Explain.

A brick has faces with the following dimensions: face 1 is \(1 \mathrm{cm}\) by \(2 \mathrm{cm} ;\) face 2 is \(2 \mathrm{cm}\) by \(3 \mathrm{cm} ;\) face 3 is \(1 \mathrm{cm}\) by \(3 \mathrm{cm} .\) On which face should the brick be placed if it is to have the smallest change in dimensions due to its own weight? Explain.

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