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When technicians work on a computer, they often ground themselves to prevent generating a spark. If an electrostatic discharge does occur, it can cause temperatures as high as \(1500^{\circ} \mathrm{C}\) in a localized area of a circuit. Temperatures this high can melt aluminum, copper, and silicon. What is this temperature in (a) degrees Fahrenheit and (b) kelvins?

Short Answer

Expert verified
2732°F and 1773.15 K.

Step by step solution

01

Convert Celsius to Fahrenheit

To convert from Celsius to Fahrenheit, we use the formula: \[ F = \left( \frac{9}{5} \right) C + 32 \]Here, \( C = 1500^{\circ} \). Substituting the Celsius value:\[ F = \left( \frac{9}{5} \right) \times 1500 + 32 \]\[ F = 2700 + 32 \]\[ F = 2732^{\circ} \] Thus, the temperature is \( 2732^{\circ} \text{F} \).
02

Convert Celsius to Kelvin

To convert from Celsius to Kelvin, we add 273.15 to the Celsius temperature:\[ K = C + 273.15 \]Substituting the Celsius value:\[ K = 1500 + 273.15 \]\[ K = 1773.15 \]Thus, the temperature is \( 1773.15 \text{ K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Celsius to Fahrenheit
The conversion from Celsius to Fahrenheit is essential, particularly in fields where temperature readings need to be precise. To transform a temperature in Celsius (\( C \)) into Fahrenheit (\( F \)), use the formula:
\[ F = \left( \frac{9}{5} \right) C + 32 \]This formula derives from the relationship between the freezing and boiling points of water in both the Celsius and Fahrenheit scales:
  • Water freezes at \( 0^{\circ} \)C and \( 32^{\circ} \)F
  • Water boils at \( 100^{\circ} \)C and \( 212^{\circ} \)F
These two points create a linear relationship. Multiplying by \( \frac{9}{5} \) scales Celsius to Fahrenheit, and adding 32 adjusts for the starting temperature difference. In our example, when a circuit can reach up to \(1500^{\circ}\)C due to electrostatic discharge, converting using the formula results in \(2732^{\circ}\)F, which translates this extreme temperature into the Fahrenheit context most familiar to those in the United States.
Celsius to Kelvin
Converting Celsius to Kelvin is a vital process in the scientific world. This conversion is straightforward and involves simply adding 273.15 to the Celsius temperature, as per the formula:
\[ K = C + 273.15 \]Kelvin is the SI unit of temperature and is most commonly used in scientific calculations because it starts at absolute zero—the point at which there is no thermal energy. This makes the Kelvin scale more intuitive for scientific purposes. In our context, the \(1500^{\circ}\)C temperature of the circuit, when converted, becomes \(1773.15 \)K. This conversion is especially relevant when comparing temperature scales universally, as Kelvin does not have degrees and maintains integrity in scientific calculations.
Electrostatic Discharge
Electrostatic discharge (ESD) refers to the sudden flow of electricity between two electrically charged objects. This can happen when technicians work on sensitive electronics, like computers, and are not properly grounded. ESD can generate exceptionally high temperatures momentarily, such as \(1500^{\circ}\)C in the examples given.

Effects of Electrostatic Discharge

ESD can lead to serious damage to electronic components by causing:
  • Sparks that melt or burn essential circuits
  • Damage to integrated circuits by extreme localized heat

Preventing Electrostatic Discharge

To avoid ESD, technicians use grounding techniques, such as wrist straps or mats, to ensure any built-up static electricity is harmlessly dissipated before coming into contact with electronic components. These precautions help prevent the damaging high temperatures that can potentially melt metals like aluminum, copper, and even silicon components present in circuits.

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Most popular questions from this chapter

Two objects are made of the same material but have different temperatures. Object 1 has a mass \(m\) and object 2 has a mass \(2 m\). If the objects are brought into thermal contact, (a) is the temperature change of object 1 greater than, less than, or equal to the temperature change of object \(2 ?\) (b) Choose the best explanation from among the following: I. The larger object gives up more heat, and therefore its temperature change is greatest. II. The heat given up by one object is taken up by the other object. since the objects have the same heat capacity, the temperature changes are the same. III. One object loses heat of magnitude \(Q\), the other gains heat of magnitude Q. With the same magnitude of heat involved, the smaller object has the greater temperature change.

Two objects at the same initial temperature absorb equal amounts of heat. If the final temperature of the objects is different, it may be because they differ in which of the following properties: mass; coefficient of expansion; thermal conductivity; specific heat?

The specific heat of alcohol is about half that of water. Suppose you have \(0.5 \mathrm{kg}\) of alcohol at the temperature \(20^{\circ} \mathrm{C}\) in one container, and \(0.5 \mathrm{kg}\) of water at the temperature \(30^{\circ} \mathrm{C}\) in a second container. When these fluids are poured into the same container and allowed to come to thermal equilibrium, (a) is the final temperature greater than, less than, or equal to \(25^{\circ} \mathrm{C} ?\) (b) Choose the best explanation from among the following: I. The low specific heat of alcohol pulls in more heat, giving a final temperature that is less than \(25^{\circ}\). II. More heat is required to change the temperature of water than to change the temperature of alcohol. Therefore, the final temperature will be greater than \(25^{\circ}\). III. Equal masses are mixed together; therefore, the final temperature will be \(25^{\circ},\) the average of the two initial temperatures.

If 2200 J of heat are added to a 190 -g object, its temperature increases by \(12 \mathrm{C}^{\circ} .\) (a) What is the heat capacity of this object? (b) What is the object's specific heat?

A sheet of aluminum has a circular hole with a diameter of \(10.0 \mathrm{cm} .\) A \(9.99-\mathrm{cm}\) -long steel rod is placed inside the hole, along a diameter of the circle, as shown in Figure \(16-21\). It is desired to change the temperature of this system until the steel rod just touches both sides of the circle. (a) Should the temperature of the system be increased or decreased? Explain. (b) By how much should the temperature be changed?

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