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Two identical objects are placed in a room at \(21^{\circ} \mathrm{C}\). Object 1 has a temperature of \(98^{\circ} \mathrm{C}\), and object 2 has a temperature of \(23^{\circ} \mathrm{C} .\) What is the ratio of the net power emitted by object 1 to that radiated by object \(2 ?\)

Short Answer

Expert verified
The ratio of the net power emitted by object 1 to object 2 is approximately 235.

Step by step solution

01

Understand Stefan-Boltzmann Law

The Stefan-Boltzmann law states that the power radiated by a black body is proportional to the fourth power of its temperature in Kelvin. This is mathematically given by:\[ P = \sigma \cdot A \cdot T^4 \]where:- \( P \) is the power radiated,- \( \sigma \) is the Stefan-Boltzmann constant,- \( A \) is the surface area,- \( T \) is the absolute temperature in Kelvin.
02

Convert Temperatures to Kelvin

Convert the given temperatures from Celsius to Kelvin using the formula \( T(K) = T(^{\circ}C) + 273.15 \).- Object 1: \( 98^{\circ}C = 98 + 273.15 = 371.15 \, K \)- Object 2: \( 23^{\circ}C = 23 + 273.15 = 296.15 \, K \)- Room temperature: \( 21^{\circ}C = 21 + 273.15 = 294.15 \, K \)
03

Calculate Net Power Emitted by Each Object

The net power emitted by an object is the difference between the power emitted by the object and the power absorbed from the room. The formula for net power is:\[ P_{net} = \sigma \cdot A \cdot (T_{obj}^4 - T_{ambient}^4) \]where \( T_{obj} \) is the object's temperature and \( T_{ambient} \) is the room temperature.
04

Calculate Net Power for Object 1

Substitute the values for Object 1 into the equation:\[ P_{1, net} = \sigma \cdot A \cdot ((371.15)^4 - (294.15)^4) \]
05

Calculate Net Power for Object 2

Substitute the values for Object 2 into the equation:\[ P_{2, net} = \sigma \cdot A \cdot ((296.15)^4 - (294.15)^4) \]
06

Compute Ratio of Net Powers

The ratio of the net power emitted by Object 1 to the net power emitted by Object 2 is:\[ \text{Ratio} = \frac{P_{1, net}}{P_{2, net}} = \frac{\sigma \cdot A \cdot ((371.15)^4 - (294.15)^4)}{\sigma \cdot A \cdot ((296.15)^4 - (294.15)^4)} \]Since \( \sigma \) and \( A \) are constants for identical objects, they cancel out.
07

Calculate the Final Ratio

Calculate the numerical values:\[ (371.15)^4 - (294.15)^4 = 16711671003.28 \]\[ (296.15)^4 - (294.15)^4 = 71112061.44 \]So the ratio becomes:\[ \text{Ratio} = \frac{16711671003.28}{71112061.44} \approx 235 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Radiation
The concept of power radiation is crucial to understanding how objects emit energy. Power radiation entails the energy radiated per unit time by a body in the form of electromagnetic waves. This energy emission occurs constantly as long as there is a temperature difference between the object and its surroundings.
In the context of physics, the Stefan-Boltzmann law is used to calculate the power emitted by a body as radiation. The formula, specified as:
  • \( P = \sigma \cdot A \cdot T^4 \)
shows that power \( P \) is a product of the Stefan-Boltzmann constant \( \sigma \), the surface area \( A \) of the body, and the fourth power of the absolute temperature \( T \).
Given that \( A \), the surface area of the objects, and \( \sigma \), the constant, are the same, power emission is largely dependent on the temperature of the object. Hence, factors such as the surface area, nature of material, and environmental conditions affect how much power is radiated.
Black Body
A black body is a theoretical or model object that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. The concept of a black body is fundamental in thermal radiation studies because it provides a perfect reference for thermal energy emission. A real-world application of a black body is limited, but it serves as a crucial idealized concept in physics. Real objects may not achieve perfect energy absorption, but they can behave approximately similar under certain conditions.
Stefan-Boltzmann's law directly connects to black body radiation, as it idealizes bodies to be perfectly black without reflection or transmission, thus giving maximum radiation.
  • This idealized model helps in calculating and understanding how much energy would be radiated by real objects if they behaved like a perfect black body.
This understanding allows scientists and engineers to predict thermal properties and improve designs in thermal systems.
Temperature Conversion
Temperature conversion is a necessary step when calculating radiation physics problems, particularly when using the Stefan-Boltzmann law, which necessitates temperature in Kelvin. The Kelvin scale is the absolute temperature scale, beginning at absolute zero, the point where no thermal energy remains in a body.To convert Celsius to Kelvin:
  • Use the formula \( T(K) = T(^{\circ}C) + 273.15 \).
  • This ensures that temperatures are expressed in an absolute context.
In exercises similar to the one given, correctly converting temperatures is crucial for the accuracy of subsequent calculations. A small mistake here might lead to incorrect conclusions in calculating radiation power.
For example, converting:
  • Object 1: \( 98^{\circ}C = 371.15 K \)
  • Object 2: \( 23^{\circ}C = 296.15 K \)
Ensures precise input for further computations and calculations.
Net Power Emitted
Net power emitted refers to the effective power an object emits after taking into account the energy absorbed from its surroundings. This measure is particularly useful in varying environments where objects not only emit energy but also absorb it simultaneously.In formulaic terms:
  • \( P_{net} = \sigma \cdot A \cdot (T_{obj}^4 - T_{ambient}^4) \)
where \( T_{obj} \) is the temperature of the object and \( T_{ambient} \) is the ambient temperature. This formula calculates the actual power an object is radiating minus what it takes in from its environment.
This concept is important in distinguishing emitted power from net power, allowing us to calculate more precisely the energy exchange between an object and its surroundings. By understanding net power, we can better characterize an object's thermal radiation in real-world situations
For exercises like this, calculating the net power helps us understand how different temperatures affect energy exchange and ensure we attribute the correct ratio of energy emissions.

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