/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 A hot-air balloon plus cargo has... [FREE SOLUTION] | 91Ó°ÊÓ

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A hot-air balloon plus cargo has a mass of \(1890 \mathrm{kg}\) and a volume of \(11,430 \mathrm{m}^{3} .\) The balloon is floating at a constant height of \(6.25 \mathrm{m}\) above the ground. What is the density of the hot air in the balloon?

Short Answer

Expert verified
The density of the hot air in the balloon is approximately \(0.1653 \text{ kg/m}^3\).

Step by step solution

01

Understanding the Problem

To find the density of the hot air inside the balloon, we need to recall that density is mass per unit volume. We have a total mass (balloon plus cargo) and the volume of the balloon.
02

Write the Density Formula

Density is given by the formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). Here, the mass includes both the balloon and cargo, which is given as \(1890\, \text{kg}\), and the volume is \(11,430\, \text{m}^3\).
03

Calculate the Density

Plug the values into the density formula: \( \text{Density} = \frac{1890\, \text{kg}}{11,430\, \text{m}^3} \). Carry out the division to get the density in kg/m\(^3\).
04

Perform the Division

Divide \(1890\) by \(11,430\) to find the density: \[ \text{Density} = \frac{1890}{11,430} \approx 0.1653 \text{ kg/m}^3 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Volume
When studying the relationship between mass and volume, it's essential to understand the specific meaning of each term and their overall significance.
  • Mass: This represents the quantity of matter contained in an object. Typically, it's measured in kilograms (kg) in the metric system. In the context of a hot-air balloon, the mass includes everything inside like the balloon's fabric, the basket, and any cargo or passengers.
  • Volume: Volume measures the amount of space occupied by an object or substance, typically expressed in cubic meters (\( \text{m}^3 \)). For a balloon, this is the total space available within its envelope, which holds the hot air.
Together, mass and volume are essential physical properties and understanding these gives insight into how objects behave, including floating on air or water. The balance between mass and volume directly influences an object's ability to float, as seen with balloons.
Hot-Air Balloon
The hot-air balloon is a fascinating example of basic principles of buoyancy and density at work. It operates based on simple yet effective physics concepts: - **Buoyancy**: This principle explains how objects float. A hot-air balloon rises because the hot air inside is less dense than the cooler outside air. - **Functionality**: By heating the air inside the balloon, the pilot reduces the air's density, allowing it to be buoyant compared to the surrounding cooler air. The floating of the hot-air balloon at a constant height means that the weight of the balloon is balanced by the buoyant force. This delicate balance showcases the elegant scientific principles that float these majestic vessels effortlessly in the sky.
Density Formula
The concept of density links mass and volume and is crucial in understanding the behavior of substances in different environmental conditions.**Density is defined as mass per unit volume**. The formula to calculate density is: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]This formula tells you how much mass is contained within a given space or how compact a substance is.In practical terms, when you know the mass and volume as in the hot-air balloon exercise, you simply plug these values into the formula to find out the density. Here, the mass of the balloon with cargo is given as \(1890 \text{ kg}\), and the volume is \(11,430 \text{ m}^3\). By performing the division:\[ \text{Density} = \frac{1890}{11,430} \approx 0.1653 \, \text{kg/m}^3\] The calculated density shows us the hot air's compactness compared to its total space. Understanding the density helps in explaining why and how the balloon can float.

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Most popular questions from this chapter

In a classroom demonstration, the pressure inside a soft drink can is suddenly reduced to essentially zero. Assuming the can to be a cylinder with a height of \(12 \mathrm{cm}\) and a diameter of \(6.5 \mathrm{cm}\), find the net inward force exerted on the vertical sides of the can due to atmospheric pressure.

Blo Bioluminescence Some species of dinoflagellate (a type of unicellular plankton) can produce light as the result of biochemical reactions within the cell. This light is an example of bioluminescence. It is found that bioluminescence in dinoflagellates can be triggered by deformation of the cell surface with a pressure as low as one dyne \(\left(10^{-5} \mathrm{N}\right)\) per square centimeter. What is this pressure in (a) pascals and (b) atmospheres?

A water tank springs a leak. Find the speed of water emerging from the hole if the leak is \(2.7 \mathrm{m}\) below the surface of the water, which is open to the atmosphere.

You step into an elevator holding a glass of water filled to a depth of \(6.9 \mathrm{cm}\). After a moment, the elevator moves upward with constant acceleration, increasing its speed from 0 to \(2.4 \mathrm{m} / \mathrm{s}\) in \(3.2 \mathrm{s} .\) (a) During the period of acceleration, is the pressure exerted on the bottom of the glass greater than, less than, or the same as before the elevator began to move? Explain. (b) Find the change in the pressure exerted on the bottom of the glass as the elevator accelerates.

BIO A person weighs \(685 \mathrm{N}\) in air but only \(497 \mathrm{N}\) when standing in water up to the hips. Find (a) the volume of each of the person's legs and (b) the mass of each leg, assuming they have a density that is 1.05 times the density of water.

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