/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A circular wine barrel \(75 \mat... [FREE SOLUTION] | 91Ó°ÊÓ

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A circular wine barrel \(75 \mathrm{cm}\) in diameter will burst if the net upward force exerted on the top of the barrel is \(643 \mathrm{N}\). A tube \(1.0 \mathrm{cm}\) in diameter extends into the barrel through a hole in the top, as indicated in Figure \(15-26 .\) Initially, the barrel is filled to the top and the tube is empty above that level. What weight of water must be poured into the tube in order to burst the barrel?

Short Answer

Expert verified
The required weight of water is determined after finding the necessary water column height in the tube to produce 643 N of force.

Step by step solution

01

Understanding the Problem

We need to determine the weight of water in the tube required to create a net upward force of 643 N on the top of the barrel, causing it to burst. The barrel and tube have given diameters.
02

Calculate the Area of the Barrel Top

The diameter of the barrel is given as 75 cm, so the radius is half of that: 37.5 cm. Convert this to meters: \(37.5 \text{ cm} = 0.375 \text{ m}\). The area \(A\) of the top of the barrel is \(A = \pi r^2 = \pi (0.375)^2\).
03

Determine the Necessary Pressure

We know the force needed to burst the barrel is 643 N. Using the formula for pressure, \(P = \frac{F}{A}\), find the pressure needed. Substitute \(F = 643 \text{ N}\) and the area \(A = \pi (0.375)^2\).
04

Calculate the Required Water Height in Tube

Convert the necessary pressure to a height of water column in the tube. Use the formula \(P = \rho g h\), where \(\rho = 1000 \text{ kg/m}^3\) (density of water) and \(g = 9.8 \text{ m/s}^2\). Solve for \(h\): \( h = \frac{P}{\rho g} \).
05

Determine Weight of Water

Calculate the volume of water needed using the tube's cross-sectional area \(A_t = \pi r_t^2\), where \(r_t = 0.005 \text{ m}\) (converted from 1.0 cm), and multiply by the height \(h\). Finally, compute the weight: Weight = Volume \( \times \rho \times g \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrostatics
Hydrostatics is the study of fluids at rest and the forces exerted by or upon these fluids. A key concept within hydrostatics is fluid pressure, which is the force per unit area exerted by a fluid. Fluid pressure acts equally in all directions at a given depth. This concept is crucial in solving problems related to fluid-filled containers, like our wine barrel scenario.

The pressure exerted by a fluid increases with depth, as described by the equation \( P = \rho g h \), where \( \rho \) is the fluid's density, \( g \) is the acceleration due to gravity, and \( h \) is the depth of the fluid column. In our exercise, understanding this relationship allows us to determine how much water needs to fill the tube to exert a specific pressure on the barrel top.
  • Pressure-vector relation: At any point in a fluid at rest, the pressure acts perpendicular to any surface. This makes it essential for calculating the force on surfaces like the barrel top.
  • Continuity in resting fluid: The fluid’s pressure remains constant across any horizontal plane at equilibrium in a container without horizontal movement.
Force Calculation
Force calculation in hydrostatic scenarios involves determining the net force exerted by a fluid on a surface. In our barrel problem, we aim to compute the upward force exerted by the water on the barrel's top surface.

To calculate force, we use the formula \( F = P \times A \), where \( F \) is the force, \( P \) is the pressure, and \( A \) is the area. With the force needed to burst the barrel known as 643 N, solving for pressure and consequently the required water height involves rearranging terms in these equations. This helps ensure that when calculating force, the conditions (like area and pressure) are correctly applied.
  • Understand given parameters: Before computing force, ensure you know the pressure acting upon the area and convert all measurements to consistent units.
  • Balanced forces: Assure the calculated force is indeed the net force when equating to any known criteria (e.g., barrel bursting limit).
Circular Area Calculation
Calculating the area of a circular shape is a fundamental mathematical task in geometry and is crucial to solving problems related to circular surfaces. This skill is vital when determining how much area a given force is acting upon, such as the top of our wine barrel.

The formula for the area of a circle is \( A = \pi r^2 \), where \( r \) is the radius of the circle. To apply this, first convert any given diameter to radius by dividing by two. For instance, if the diameter of the barrel is 75 cm, the radius is \( 37.5 \) cm, or \( 0.375 \) meters.
  • Unit conversion: Always ensure dimensions are in consistent units (like meters) to simplify calculations and avoid errors.
  • Importance in force and pressure calculations: Circular area calculations play a crucial role in determining both the surface area under pressure and the resulting force in the problem.
By understanding these concepts, the exercise not only becomes manageable but also illustrates the power of geometric and physical principles in real-world applications.

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Most popular questions from this chapter

A tank of water filled to a depth \(d\) has a hole in its side a height \(h\) above the table on which it rests. Show that water emerging from the hole hits the table at a horizontal distance of \(2 \sqrt{(d-b) h}\) from the base of the tank.

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You step into an elevator holding a glass of water filled to a depth of \(6.9 \mathrm{cm}\). After a moment, the elevator moves upward with constant acceleration, increasing its speed from 0 to \(2.4 \mathrm{m} / \mathrm{s}\) in \(3.2 \mathrm{s} .\) (a) During the period of acceleration, is the pressure exerted on the bottom of the glass greater than, less than, or the same as before the elevator began to move? Explain. (b) Find the change in the pressure exerted on the bottom of the glass as the elevator accelerates.

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