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With what speed must you approach a source of sound to observe a \(15 \%\) change in frequency?

Short Answer

Expert verified
The observer must approach at 51.45 m/s.

Step by step solution

01

Understand the Doppler Effect

The Doppler Effect explains how the frequency of a wave changes for an observer moving relative to the source of the wave. When you move towards a sound source, the observed frequency increases.
02

Identify the given information

We know that the observed frequency change is 15%. Let \( f_s \) be the frequency of the source and \( f \) be the observed frequency. Thus, \( f = 1.15 f_s \).
03

Use the formula for the Doppler Effect

For a moving observer and stationary source, the observed frequency \( f \) is given by \( f = f_s \left(\frac{v + v_o}{v}\right) \), where \( v \) is the speed of sound and \( v_o \) is the speed of the observer. In air, the speed of sound \( v \) is approximately 343 m/s.
04

Substitute the values

Substitute \( f = 1.15 f_s \), \( v = 343 \) m/s into the formula: \[ 1.15 f_s = f_s \left(\frac{343 + v_o}{343}\right) \] Cancel \( f_s \) on both sides.
05

Solve for the observer's speed \( v_o \)

Rearrange the equation: \[ 1.15 = \frac{343 + v_o}{343} \] Multiply through by 343: \[ 1.15 \times 343 = 343 + v_o \] Calculate: \[ 394.45 = 343 + v_o \] Thus, \[ v_o = 394.45 - 343 = 51.45 \]
06

Interpret the result

The observer must approach the source with a speed of approximately 51.45 m/s to observe a 15% increase in frequency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Change and the Doppler Effect
The Doppler Effect is an intriguing phenomenon that affects how we perceive the frequency of sound. It occurs when there is a relative movement between the source of sound and an observer. If you're moving towards a sound source, you'll notice that the sound seems higher in pitch, meaning a higher frequency. This occurs because the sound waves are compressed, leading to an increase in frequency. Conversely, moving away from a sound source will lower the apparent frequency, as the waves are stretched out.

In this particular exercise, we are examining a situation where the observer wants to experience a 15% increase in frequency. This means that the sound heard should be higher by 15% compared to the original sound emitted by the source. Understanding this change is crucial for solving the problem using the Doppler Effect formula.
Influence of Observer Speed on Frequency
The speed of an observer relative to a sound source can significantly influence the perceived frequency of sound. In this exercise, we are dealing with the case where the observer is moving towards the source. When you approach a sound, you're essentially reducing the distance between yourself and the consecutive sound waves. This leads to the waves reaching your ears more frequently, thus increasing the frequency.

We use the formula for the Doppler Effect to calculate this impact: \[ f = f_s \left(\frac{v + v_o}{v}\right) \]Where:
  • \( f \) is the observed frequency
  • \( f_s \) is the source frequency
  • \( v \) is the speed of sound
  • \( v_o \) is the observer's speed
In our solution, substituting known values into this formula helped us find that a 15% increase meant the observer's speed needed to be approximately 51.45 m/s.
The Importance of Speed of Sound
The speed of sound is a fundamental constant in calculating changes due to the Doppler Effect. In air, the speed of sound is approximately 343 m/s, though this can vary slightly based on factors such as temperature and atmospheric pressure.

When you are working with such exercises, it is key to use the correct value for the speed of sound to ensure accuracy. In the Doppler Effect equation, the speed of sound serves as a baseline, interacting with the observer's speed to determine how much the frequency will change. Although different conditions may slightly affect the speed, 343 m/s is the typical value used in most standard conditions.

Hence, accurate calculations require considering this speed carefully, and it's why it's an integral part of understanding and solving Doppler Effect problems.

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Most popular questions from this chapter

A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of \(502 \mathrm{Hz}\) and has a speed of \(27.0 \mathrm{m} / \mathrm{s}\). The motorcycle has a speed of \(13.0 \mathrm{m} / \mathrm{s}\) What frequency does the motorcyclist hear?

A person with perfect pitch sits on a bus bench listening to the \(450-\mathrm{Hz}\) horn of an approaching car. If the person detects a frequency of \(470 \mathrm{Hz},\) how fast is the car moving?

A particular jet engine produces a tone of \(495 \mathrm{Hz}\). Suppose that one jet is at rest on the tarmac while a second identical jet flies overhead at \(82.5 \%\) of the speed of sound. The pilot of each jet listens to the sound produced by the engine of the other jet. (a) Which pilot hears a greater Doppler shift? Explain. (b) Calculate the frequency heard by the pilot in the moving jet. (c) Calculate the frequency heard by the pilot in the stationary jet.

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake with a speed of \(2.0 \mathrm{m} / \mathrm{s}\) and a wavelength of \(1.5 \mathrm{m}\). When these waves move into a shallower part of the lake, their speed decreases to \(1.6 \mathrm{m} / \mathrm{s}\), though their frequency remains the same. Find the wavelength of the waves in the shallower water.

\(\mathrm{CE}\) A harmonic wave travels along a string. (a) At a point where the displacement of the string is greatest, is the potential energy of the string a maximum or a minimum? Explain. (b) At a point where the displacement of the string is zero, is the potential energy of the string a maximum or a minimum? Explain.

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